We use the method of Lagrange multipliers We up the auxiliary function F given by We compute Hence - see HB pages 25-26. F(x, y, z,λ)=f(x, y, z) − λ(x² + y² + z² = r²) n - n n - = (²)² + (²)² + (£) ” − × (x² + y² + z² − r²). Fx = (na")1/(n+2) X=- (21)1/(n+2) nan xn+1 == - 2x = 0. n 21 1/(n+2) an/(n+2). how ?? come.
We use the method of Lagrange multipliers We up the auxiliary function F given by We compute Hence - see HB pages 25-26. F(x, y, z,λ)=f(x, y, z) − λ(x² + y² + z² = r²) n - n n - = (²)² + (²)² + (£) ” − × (x² + y² + z² − r²). Fx = (na")1/(n+2) X=- (21)1/(n+2) nan xn+1 == - 2x = 0. n 21 1/(n+2) an/(n+2). how ?? come.
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter7: Analytic Trigonometry
Section7.6: The Inverse Trigonometric Functions
Problem 91E
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Transcribed Image Text:M820-eTutorial3.pdf
× chi introduction rs Steven Nepub × 22m820mn-errat non-dated-u2.pdf
We use the method of Lagrange multipliers
We up the auxiliary function F given by
-
see HB pages 25-26.
We compute
Hence
F(x, y, z,λ) = f(x, y, z) — λ(x² + y² + z² = r²)
-
'
n
= (²) " + (²)² + (±) " − × (x² + y² + z² − r²).
Fx =
(nan) 1/(n+2)
x =
(21)1/(n+2)
nan
x+1
2x = 0.
=
- (2)
1/(n+2)
an/(n+2).
-
how
??
come.
Notice it follows from this that (21) 1/(0+2) < 0.
By symmetry of argument it follows
(M820 eTutorial 3)
08:18 AM
94%
y
(nb")1/(n+2)
(21)1/(n+2) '
and
(nc")1/(n+2)
z =
(21)1/(n+2) ·
13th March 2024
4/17
4(27.78%)
Х
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