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What is the
35.50 u, 35.86 u, 36.14 u
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- You are trying to come up with a drug to inhibit the activity of an enzyme thought to have a role in liver disease. In the laboratory the enzyme was shown to have a Km of 1.0 x 10-6 M and Vmax of 0.1 micromoles/min.mg measured at room temperature. You developed a competitive inhibitor. In the presence of 5.0 x 10-5 M inhibitor, the apparent Km of the enzyme was found to be 1.5 x 10-5 M. What is the Ki of the inhibitor?The proton NMR spectrum of a compound, C3H6Cl2, has a pentet at d 2.19 and a triplet at & 3.72 with a 1:2 integration ratio, respectively. Which compound below best matches the data? A) CH₂CH₂CHC1₂ B) CICH₂CH₂CH₂C1 C) CH3CHCH₂C1 Cl C1 D) CH3CCH3 C11-arr In a study of the gas phase decomposition of phosphine at 120 °C PH3(g)- →1/4 P4(g) + 3/2 H2(g) the concentration of PH3 was followed as a function of time. It was found that a graph of In[PH3] versus time in seconds gave a straight line with a slope of -2.50×10² s1 and a y-intercept of -3.24. Based on this plot, the reaction i v O order in PH, and the half life for the reaction is seconds. zero first second
- You are trying to come up with a drug to inhibit the activity of an enzyme thought to have a role in liver disease. In the laboratory the enzyme was shown to have a Km of 1.0 x 10-6 M and Vmax of 0.1 micromoles/min.mg measured at room temperature. You developed an uncompetitive inhibitor. In the presence of 5.0 x 10-5 M inhibitor, the apparent Vmax was determined to be 0.02 micromoles/min.mg. What is the Ki of the inhibitor?The concentration of solution A is 2.0 mol / dm3. Prepare solution B as follows: Pipette solution A into a 5.5 cm3 graduated pipette. Dilute this volume to 25 ml in a measuring bottle. What is the concentration of solution B?(b) Shown below are three different van Deemter curves for particles of varying sizes. Propose explanations for their differences based on terms in the van Deemter equation. Thereby explaining why smaller particle size is desirable. HETP (μm) 60 9 20 0 0 2 10 5 µm 4 FLOW RATE (mL/min) 6 10 μm 3 μm 8
- ESF X empt/quiz_start_frame_auto.d21?ou=9739790&isprv=&qi=11007766&cfql=0&dnb=0&fromQB=0&inProgress=1 ystems Question 5 (1 point) Ben starts walking along a path at 3 mi hr¹. Amanda starts jogging along the same path 1 hour later at 5 mi hr. After how much time jogging does Amanda catch up to Ben? 3.5 hr 2.5 hr 2 hr 16因 + II P 8 团 w/ S - Cameron Hite Learn b Chemistry Questions & Answers + A www-awu.aleks.com/alekscgi/x/Isl.exe/1o_u-IgNslkr7j8P3jH-IVDWKVW_BBZZI6tTytly4Fcfu6zOtOf8oMM9sLjOBhHfJ6ZNhysAi_9KCqM8FRGCtiPxvdUuxrTTETxcEo9QVTr9NhEkLqSLo?1oBw7QYjlbav. E O CHEMICAL REACTIONS 0/3 Cameron V Solving for a reactant in solution One way the U.S. Environmental Protection Agency (EPA) tests for chloride contaminants in water is by titrating a sample of silver nitrate solution. Any chloride anions in solution will combine with the silver cations to produce bright white silver chloride precipitate. Suppose an EPA chemist tests a 200. mL sample of groundwater known to be contaminated with tin(II) chloride, which would react with silver nitrate solution like this: SnCl,(aq) + 2 AgNO,(aq) → 2 AgCl(s) + Sn(NO,),(aq) The chemist adds 23.0 mM silver nitrate solution to the sample until silver chloride stops forming. He then washes, dries, and weighs the precipitate. He finds he has collected 6.8 of silver…Page Grades for Nancy Duran: CHE 103 X A ALEKS - Nancy Duran - Learn × + ✰ www-awa.aleks.com/alekscgi/x/Isl.exe/1o_u-IgNslkr7j8P3jH-IQgHlvdL2donGg9plnQUm9kiGJhghYuAiZLqZVWgwEXBsd4IBLw36AkXLcyDcVVrmllCzwt0IT1g... ? O CHEMICAL REACTIONS Limiting reactants QU N OO EXPLANATION Gaseous butane (CH₂(CH₂)₂CH3) will react with gaseous oxygen (O₂) to produce gaseous carbon dioxide (CO₂) and gaseous water (H₂O). Suppose 2.3 g of butane is mixed with 4.49 g of oxygen. Calculate the maximum mass of water that could be produced by the chemical reaction. Round your answer to 3 significant digits. The question is a limiting reactant problem. You can tell it's a limiting reactant problem by the fact that you were given the initial amounts of more than one reactant. Here is the balanced chemical equation for the reaction you will need to solve the problem: 2 CH₂ (CH₂), CH₂(g) + 130₂ (g) → 8 CO₂(g) + 10 H₂O(g) You can solve limiting reactant problems in the following three steps: Step 1: Find the initial…