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What is T₂(x) centered at a = 3 for a function f(x) such that f(3) = 9, f '(3) = 8, f "(3) = 4, and f "(3) = 12? A.T₂(x)=9+3(x-8)+3(x-4)² +3(x-12)³ B.T3(x)=9+8(x-3)+4(x-3)² C.T3(x)=9+8(x-3)+2(x-3)² + 2(x-3)³ D.T₂(x)=9+8(x-3)+4(x-3)² +12(x-3)³

What is T₂(x) centered at a = 3 for a function f(x) such that f(3) = 9, f '(3) = 8, f "(3) = 4, and f "(3) = 12? A.T₂(x)=9+3(x-8)+3(x-4)² +3(x-12)³ B.T3(x)=9+8(x-3)+4(x-3)² C.T3(x)=9+8(x-3)+2(x-3)² + 2(x-3)³ D.T₂(x)=9+8(x-3)+4(x-3)² +12(x-3)³

Calculus For The Life Sciences
Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter4: Calculating The Derivative
Section4.4: Derivatives Of Exponential Functions
Problem 19E
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What is T3(x) centered at a = 3 for a function f(x) such that f(3) = 9, f '(3) = 8, f "(3) = 4, and f "(3) = 12? A.T₂(x)=9+3(x−8)+3(x−4)² +3(x−12)³ B.T3(x)=9+8(x-3)+4(x-3)² C.T3(x)=9+8(x-3)+2(x-3)² + 2(x − 3)³ D.T₂(x)=9+8(x-3)+4(x-3)² +12(x-3)³
Transcribed Image Text:What is T3(x) centered at a = 3 for a function f(x) such that f(3) = 9, f '(3) = 8, f "(3) = 4, and f "(3) = 12? A.T₂(x)=9+3(x−8)+3(x−4)² +3(x−12)³ B.T3(x)=9+8(x-3)+4(x-3)² C.T3(x)=9+8(x-3)+2(x-3)² + 2(x − 3)³ D.T₂(x)=9+8(x-3)+4(x-3)² +12(x-3)³
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