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What is/are the principle/s involved on ACIDIMETRIC ASSAY BY DOUBLE INDICATOR TITRATION?
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- 6. The mass percent of KHP in an unknown salt sample was determined using both volumetric and gravimetric titration. Ten determinations using each method were performed: (You should be using Excel to solve for the required values) Volumetric (% KHP): 34.22 33.86 34.07 34.49 34.69 33.71 34.28 34.11 34.26 34.10Gravimetric (% KHP): 34.35 34.26 34.10 34.19 34.18 34.32 34.11 34.33 34.17 34.12 a) Do the two methods give similar standard deviations? b) Do the two methods give similar results for the mass percent of KHP at the 95% confidence level?5. A 300.0 mg sample containing Na,CO3, NaHCO3 and NaOH and inert material either alone or in some combination was dissolved and titrated with 0.1000 M HCI the titration required 24.41 mL to reach the phenolphthalein endpoint. And an additional 8.67 mL to reach the methyl red endpoint. Determine the composition of the sample and calculate the percent of each titrated component.Advantages of potentiometric titrations over 'classical' visual indicator methods: (select the correct statement(s)). Can be used for colored, turbid or fluorescent analyte solution. Can be used if there is no suitable indicator or if the color change is difficult to visualize. Both answers 1 and 2 are correct
- A 625 mg sample of sodium bicarbonate tablet required 7.30 mL of 0.9580N sulfuric acid solution to reach the methyl red endpoint. PRELIMINARY QUESTION: Which of the following statements is/are TRUE? I. The țitrant used is sulfuric acid solution. II. The end point is a red/pink solution. III. This is an example of direct assay titration.One of the following statements is incorrect: O Titration error is the difference between equivalence point volume and end point volume O A primary standard should be highly pure, has atmospheric stability and absence of hydrated water O Back-titration is required when the rate of the reaction slow O A standard solution should react completely with the analyte with a definite chemical equation O tandardization is not required when the titrant solution molarity is approximateOne of the following statements is incorrect Select one: O Back-titration is required when the rate of the reaction slow. O A standard solution should react completely with the analyte without a definite chemical equation. Standardization is required when the titrant solution molarity is approximate. O A primary standard should be highly pure, has atmospheric stability and absence of hydrated water. O Titration error is the difference between equivalence point volume and end point volume.
- What is a 3 point calibration in titration?How do you choose the most suitable precipitate for gravimetric purposes if given many choices?An indicator was not used during potentiometric titration of a weak acid Is there a positive error, negative error, no effect, or error could not be determined In terms of the Computed pKa of the unknown weak acid?
- Concentration sodium thiosulfate solution used: 0.056 mol L-1 ACCURATE TITRATION VOLUME OF SODIUM THIOSULFATE SOLUTION USED Volume titration 1, (ml) Volume titration 2, (ml) Your Group 15.80 15.75 Group 1 16.05 15.70 Group 2 16.30 16.25 ANALYSIS Average volume used, (mL) Standard deviation Number of moles sodium thiosulfate used, (mol) Number of moles calcium iodate in solution, (mol) Volume of calcium iodate used, (mL) Concentration of saturated calcium iodate solution (mol L-¹) Unrounded value 15.9750 0.26220 Rounded value 15.97 0.262 10.0Concentration sodium thiosulfate solution used: 0.056 mol L-1 ACCURATE TITRATION VOLUME OF SODIUM THIOSULFATE SOLUTION USED Volume titration 1, (mL) Volume titration 2, (mL) Your Group 15.80 15.75 Group 1 16.05 15.70 Group 2 16.30 16.25 ANALYSIS Average volume used, (ml) Standard deviation Number of moles sodium thiosulfate used, (mol) Number of moles calcium iodate in solution, (mol) Volume of calcium iodate used, (mL) Concentration of saturated calcium iodate solution (mol L-¹) Unrounded value 15.9750 0.26220 0.00089400 0.00036700 A Rounded value 15.97 0.262 8.94 x 10-4 10.0 MinimizeAnswer if true or false , if false, put the correct answer 1. There is 11.34 mmol in 0.2011 of 0.5604 M HgCl2 2. The x axis of sigmoidal titration curve is p function of the analyte or titrant 3.The concentration of the secondary standard is relative to a primary standard 4. There is 110 mmol in 79.8 mL of 0.1379 M NH4VO3 (116.98 g/mol)