Answered: Where T = orbital period in Earth years…

Where T = orbital period in Earth years and R = distance of the planet from the sun in A.U.’s. From this equation how would you describe the relationship between T2 and R3?

Horizons: Exploring the Universe (MindTap Course List)

14th Edition

ISBN:9781305960961

Author:Michael A. Seeds, Dana Backman

Publisher:Michael A. Seeds, Dana Backman

Chapter1: Here And Now

Section: Chapter Questions

Problem 1P: The diameter of Earth across the equator is 7928 miles. If a mile equals 1.609 km. what is Earths...

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The sun is 93 million miles from earth. a) Convert 93 million miles to meters and use scientific notation and round your leading coefficient in your answer to the nearest tenth. (Show step by step conversion factors). EARTH has a mass of 6 x 10^24 kg and the Sun's mass is 1.9 x 10^30 kg. b). Use Newton’s law of universal gravitation to determine the gravitational force (N) between the earth and the sun.
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The table below presents the semi-major axis (a) and Actual orbital period for all of the major planets in the solar system. Cube for each planet the semi-major axis in Astronomical Units. Then take the square root of this number to get the Calculated orbital period of each planet. Fill in the final row of data for each planet. Table of Data for Kepler’s Third Law: Table of Data for Kepler’s Third Law: Planet aau = Semi-Major Axis (AU) Actual Planet Calculated Planet Period (Yr) Period (Yr) __________ ______________________ ___________ ________________ Mercury 0.39 0.24 Venus 0.72 0.62 Earth 1.00 1.00 Mars 1.52 1.88 Jupiter…
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BACKGROUND An ingenious solution to the Earth's circumference occured in 230 BC. Eratosthenes, a Greek geographer, mathematician, music theorist, poet, astronomer, and philosopher, was reading in the Library of Alexandria when he noticed an account for a deep well near Syene (now Aswan), some distance to the south (800 km) in which at high noon on the longest day of the year the bottom of the well was fully illuminated by the Sun. Eratosthenes exclaimed "Ah-ah!" (or something like that), "I can solve for the circumference of the Earth!". In his mind's eye, Eratosthenes could see that at Syene, at the moment when the bottom of the well was fully lit, the Sun must have been at the Zenith (directly overhead). Yet he knew that at the same moment in Alexandria vertical objects (like a tower, pole) cast shadows. Here is the experiment perfomed by Eratosthenes (see the picture below). • He erected a vertical pole at Alexandria (A) and measured the angle of its shadow at the moment when the…
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Show your complete and detailed solution. Round off your answers to 4 decimal digits and box your final answers.
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