Which is the fastest way to square all the integers within [0, 99]? Selecting multiple choices indicates comparable optimized performance. np.array([i**2 for i in range (180)]) пр. ромеr (пр. aгange(10@), 2) пр. роwer(2, пр. arange (18e) np. arange (10e) ** 2

Which is the fastest way to square all the integers within [0, 99]? Selecting multiple choices indicates comparable optimized performance. np.array([i2 for i in range (180)]) пр. ромеr (пр. aгange(10@), 2) пр. роwer(2, пр. arange (18e) np. arange (10e) 2

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Programming in C language. RandomNumbers Declare an integer array locally with the size of 200. Create a program that asks the user how many numbers the have. Use your getChoicel) function from before. Make sure it does not exceed 200 as the locally declared array has the size of 200. Use a loop to assign random numbers from 1 to 10000 to the array elements. (Remember to use srand() to seed the random number generator). Use a second loop to display each number, and also determine the average of all values in the array. You must also find the largest and the smallest numbers. After the for loop, display the average of all numbers. This program will let you enter a list of numbers into an array. It will then display all of the numbers, and finally display the average of all numbers. How many numbers would you like to enter?10 Number 1 is 42 Number 2 is 8468 Number 3 is 6335 Number 4 is 6501 umber 5 is 9170 Number 6 is 5725 Number 7 is 1479 Number 8 is 9359 Number 9 is 6963 Number 10 is…
Multi Dimensional Arrays in C Program Ask the user for the number of rows and columns of a two-dimensional array and then its integer elements. Then, ask the user for another integer value which represents a boogeyman. A boogeyman is a value that we intend to find from a given array. Find and output the coordinates of the boogeyman by this format: "BOOGEYMAN LOCATED AT ROW {row_number}, COLUMN {column_number}!" Input 1. One line containing an integer for the number of rows 2. One line containing an integer for the number of columns 3. Multiple lines containing at least one integer each line for the elements of the array Sample 1 4 2 3 9 1 2 3 4 2 1 1 9 2 8 3 4. One line containing an integer for the boogeyman's value Output Print the row of the position first and then the column of the position. Note that the row and the column is 0-based (i.e. it starts at 0 and not at 1). It is guaranteed that the boogeyman exists and only once in the 2D array. Enter# of rows: 4 Enter…
def findOccurrences(s, ch): lst = [] for i in range(0, len(s)): if a==s[i]: lst.append(i) return lst Use the code above instead of enumerate in the code posted below. n=int(input("Number of rounds of Hangman to be played:")) for i in range(0,n): word = input("welcome!") guesses = '' turns = int(input("Enter the number of failed attempts allowed:")) def hangman(word): secrete_word = "-" * len(word) print(" the secrete word " + secrete_word) user_input = input("Guess a letter: ") if user_input in word: occurences = findOccurrences(word, user_input) for index in occurences: secrete_word = secrete_word[:index] + user_input + secrete_word[index + 1:] print(secrete_word) else: user_input = input("Sorry that letter was not found, please try again: ") def findOccurrences(s, ch): return [i for i, letter in enumerate(s) if letter == ch] *** enumerate not discussed in…
def apply_gaussian_noise(X, sigma=0.1): """ adds noise from standard normal distribution with standard deviation sigma :param X: image tensor of shape [batch, 3, height, width] Returns X + noise. """ ### YOUR CODE HERE ### # noise tests theoretical_std = (X_train[:100].std() ** 2 + 0.5 ** 2) ** .5 our_std = apply_gaussian_noise(X_train[:100], sigma=0.5).std() assert abs(theoretical_std - our_std) < 0.01, \ "Standard deviation does not match it's required value. Make sure you use sigma as std." assert abs(apply_gaussian_noise(X_train[:100], sigma=0.5).mean() - X_train[:100].mean()) < 0.01, \ "Mean has changed. Please add zero-mean noise"
in java Create two arrays with same length n: - Array A with integer numbers that user will insert- Array B with random numbers from 0 to 100.- Find sum of both arrays,- Find maximum values of both array and compare them: .if maximum of 1 st is lower then maximum of 2nd array: print sums of both arrays.if maximum of 1st is greater then maximum of 2nd array print 2nd array (use println)otherwise print first array in reverse.
Integer numElements is read from input and represents: • The number of elements in each array. The number of pairs of integers read from input. Declare two integer arrays, houselds and serviceCosts. Then, read each pair of integers from input. For each pair read, store the first integer into houselds and the second integer into serviceCosts. Ex: If the input is: 4 3 29 9 12 8 18 5 46 then the output is: House id: 3, Costs: $29 House id: 9, Costs: $12 House id: 8, Costs: $18 House id: 5, Costs: $46 1 import java.util.Scanner; 2 3 public class CashRecords { 4 5 16780 O 9 public static void main(String[] args) { Scanner scnr= new Scanner (System.in); int numElements; int i; numElements scnr. nextInt (); /* Your code goes here */ for (i = 0; i< numElements; ++i) { System.out.println("House id: + houseIds[i] + ", Costs: $" + serviceCosts [i]); 10 11 12 13 14 15 16 } 17 } }
Which for statement is correct to produce the indexes of an array in reverse order? Lütfen birini seçin: a. for(int j = arr.length() - 1; j > 0; j--) b. for(int j = arr.length; j >= 0; j--) c. for(int j = arr.length() - 1; j >= 0; j--) d. for(int j = arr.length - 1; j >= 0; j--) e. for(int j = arr.length - 1; j > 0; j--)
void radixSort(int arr[], int n) { intm=getMax(arr, n); for (intexp=1; m/exp>0; exp*=10) countSort(arr, n, exp); } void printData(int arr[], int start, int len) { if( start>=len ) return( 0 ); printf("%d\n", arr[start]); printData(arr, start+1, len); } int main() { intarr[]= {8, 9, 3, 4, 7, 2, 5, 6, 1}; intn=sizeof(arr) /sizeof(arr[0]); radixSort(arr, n); printData(arr, 0, n); return0; } In MIPS
python exercise Given the following list: testlist2 = (23,50,12,80,10,90,34,78,4,19,53) Use testlist2 to create Numpy array of int16 and then display the array. Display the number of dimension of testnp. Display the shape of testnp. Display the number of bytes of testnp. Display the mean, sum, max, and min of testnp.
Declare three arrays: A, B and C each size 3 Read these numbers into A using for loop and scanf : 1, 2, 3 Read these numbers into B using for loop and scanf : -1, -2, -3 C is A+ B. this means you need to add each element of the array A to corresponding element of array B and then C is the sum. Print the elements of array C • Previous t: Stu- J útv G MacBook Air 80 DD F2 F3 F4 F5 F6 F7 F10 F8 F9 @ 23 2$ & * 2 3 4 5 6 7 8 W E R Y S D F H J K C V |N M B
ANSWER IN JAVA: Write an application that inputs five numbers, each between 10 and 100, inclusive. As each number is read, display it only if it’s not a duplicate of a number already read. Provide for the “worst case,” in which all five numbers are different. Use the smallest possible array to solve this problem. Display the complete set of unique values input after the user enters each new value. NOTE: looking for the output to appear on three lines as shown in the results STANDARD OUTPUT: Enter·an·integer·between·10·and·100:This·is·the·first·time·100·has·been·entered↵ Enter·an·integer·between·10·and·100:Enter·an·integer·between·10·and·100:This·is·the·first·time·10·has·been·entered↵ Enter·an·integer·between·10·and·100:This·is·the·first·time·20·has·been·entered↵ Enter·an·integer·between·10·and·100:The·complete·set·of·unique·values·entered·is:↵ Unique·Value·1:·is·100↵ Unique·Value·2:·is·10↵ Unique·Value·3:·is·20↵
Your Friendly Array Neighbor Program only in java not in python Create a Java program that takes an array called ar as an input that keeps track of arrays. Every day a new array is produced using the array of the previous day. On the n’th day, the following operations are performed on the array of day n – 1 to produce the array of day n: -If an element is smaller than both left and right neighbor, then this element is incremented -If an element is bigger than both its left neighbor and its right neighbor, then this element is decremented. -The first and last elements should never change Eventually after some days the array will not change, some examples: Example: Input from user: ar = [6,2,3,4] Output from program: [6,3,3,4] After the first day the array is changed from [6,2,3,4] to [6,3,3,4] and no further operations may be completed. Example: Input from user: ar = [1,6,3,4,3,5] Output from program: [1,4,4,4,4,5] After the first day the array is changed from [1,6,3,4,3,5]…