Why does the final product has the opposite configuration compared to the reactant? Shouldn’t it form OMs first, then OMs gets substituted by Cl- via Sn2 (the 1st inversion of configuration) then the Cl- gets substituted by OCH3- (the 2nd inversion of configuration? To my understanding 2 inversions = same configuration

Why does the final product has the opposite configuration compared to the reactant? Shouldn’t it form OMs first, then OMs gets substituted by Cl- via Sn2 (the 1st inversion of configuration) then the Cl- gets substituted by OCH3- (the 2nd inversion of configuration? To my understanding 2 inversions = same configuration

Organic Chemistry: A Guided Inquiry

2nd Edition

ISBN:9780618974122

Author:Andrei Straumanis

Publisher:Andrei Straumanis

Chapter14: Elimination

Section: Chapter Questions

Problem 22E

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