Answered: Why it is necessary to consider that…

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Physics

Why it is necessary to consider that mass of a particle is a function of its velocity?

College Physics

1st Edition

ISBN:9781938168000

Author:Paul Peter Urone, Roger Hinrichs

Publisher:Paul Peter Urone, Roger Hinrichs

Chapter28: Special Relativity

Section: Chapter Questions

Problem 37PE: (a) Find the momentum of a 1.00109 kg asteroid heading towards the Earth at 30.0 km/s. (b) Find the...

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In a frame at rest with respect to the billiard table, a billiard ball of mass m moving with speed v strikes another billiard ball of mass m at rest. The first ball comes to rest after the collision while the second ball takes off with speed v in the original direction of the motion of the first ball. This shows that momentum is conserved in this frame. (a) Now, describe the same collision from the perspective of a frame that is moving with speed v in the direction of the motion of the first ball. (b) Is the momentum conserved in this frame?
What happens to the density of an object as its speed increases, as measured by an Earth observer?
An object having mass 900 kg and traveling at speed 0.850c collides with a stationary object having mass 1 400 kg. The two objects stick together. Find (a) the speed and (b) the mass of the composite object.
The special theory of relativity predicts that there is an upper limit to the speed of a particle. It therefore follows that there is also an upper limit on the following properties of a particle: Select one alternative: the kinetic energy the total energy the linear momentum more than one of these none of these
Bryce, a mouse lover, keeps his four pet mice in a roomy cage, where they spend much of their spare time (when they are not sleeping or eating) joyfully scampering about on the cage's floor. Bryce tracks his mice's health diligently and just now recorded their masses as 10.3 g,18.5 g,11.3 g, and 18.3 g. At this very instant, the x‑ and y‑components of the mice's velocities are, respectively, (0.115 m/s, −0.527 m/s), ,(−0.237 m/s, −0.391 m/s), ,(0.843 m/s, 0.455 m/s), and (−0.897 m/s, 0.135 m/s). Calculate the x‑ and y‑components of Bryce's mice's total momentum, px and Py. px____kg.m/s py ____kg.m/s
Two particles of mass m and velocity v collide with each other completely inelastic. What is the kinetic energy after they start acting together?
A linear particle accelerator using beta particles collides electrons with their anti-matter counterparts, positrons. The accelerated electron hits the stationary positron with a velocity of 19 x 106 m/s, causing the two particles to annihilate.If two gamma photons are created as a result, calculate the energy of each of these two photons, giving your answer in MeV (mega electron volts), accurate to 1 decimal place. Take the mass of the electron to be 5.486 x 10-4 u, or 9.109 x 10-31 kg.Note: Assume that the kinetic energy is also converted into the gamma rays, and is included in the two photons.
For a car traveling 60 km per hour (kph), the distance required to brake to a stop is normally distributed with mean of 20 meters and a standard deviation of 3 meters. Suppose you are traveling 60 kph in a residential area and a car moves abruptly into your path at a distance of 25 meters. QUESTION: If the only way to avoid a collision is to brake to a stop, what is the percentage probability that you will avoid the collision?
A linear particle accelerator using beta particles collides electrons with their anti-matter counterparts, positrons. The accelerated electron hits the stationary positron with a velocity of 29 x 106 m/s, causing the two particles to annihilate.If two gamma photons are created as a result, calculate the energy of each of these two photons, giving your answer in MeV (mega electron volts), accurate to 1 decimal place. Take the mass of the electron to be 5.486 x 10-4 u, or 9.109 x 10-31 kg.
In this problem we will observe how the momentum of an electron changes as its velocity approaches the speed of light. The mass of an electron is 9.109 × 10-31 kg. (e) When the electron is moving at 85 % of the speed of light, how many times greater is the relativistic momentum than the non-relativistic momentum? (f) Which of the following facts are true about the ratio of relativistic to non-relativistic momentum of an electron? It does not depend on the mass of the electron. It approaches infinity when the speed approaches the speed of light. It depends on the charge of the electron. The relativistic momentum and classical momentum of an electron are always about the same. It does not depend on the speed of the electron. (g) What is the ratio of the relativistic momentum to the classical momentum of a rocketship moving at 99 % of the speed of light, in kg ⋅ m/s?
Electron capture is a variant on beta-radiation. The lightest nucleus to decay by electron capture is 7Be -- beryllium-7. The daughter nucleus is 7Li -- lithium-7. The electron is transformed into a massless particle (a neutrino): e − + 7 B e + ⟶ 7 L i + ν The initial electron is bound in the atom, so the beryllium mass includes the electron. In fact, since the electron starts bound in the atom, a more-accurate statement of the nuclear reaction is probably: 7 B e ⟶ 7 L i + ν The masses are beryllium: 7.016929 u, and lithium: 7.016003 u, and refer to the neutral atom as a whole. (Use uc and uc2 as your momentum and energy units -- but carry them along in your calculation.) The initial beryllium atom is stationary. Calculate the speed of the final lithium nucleus in km/s. (You will make life much easier for yourself if you recognize that practically all the energy released goes into the lighter particle. c = 300,000 km/s)
Electron capture is a variant on beta-radiation. The lightest nucleus to decay by electron capture is 7Be -- beryllium-7. The daughter nucleus is 7Li -- lithium-7. The electron is transformed into a massless particle (a neutrino): e − + 7 B e + ⟶ 7 L i + ν The initial electron is bound in the atom, so the beryllium mass includes the electron. In fact, since the electron starts bound in the atom, a more-accurate statement of the nuclear reaction is probably: 7 B e ⟶ 7 L i + ν The masses are beryllium: 7.016929 u, and lithium: 7.016003 u, and refer to the neutral atom as a whole. (Use uc and uc2 as your momentum and energy units -- but carry them along in your calculation.) The initial beryllium atom is stationary. Calculate the speed of the final lithium nucleus in km/s. (all the energy released goes into the lighter particle. c = 300,000 km/s)