Will a grit particle with a radius of 0.10 mm and a specific gravity of 2.65 be collected in a chamber that is 13.5 m in length if the average grit-chamber flow is 0.15 m³/s, the width of the m, and the horizontal velocity is 0.25 m/s? Hint: Use the data below V's = gS 18 V T DE. 12SIP v=0.959 x 10 m²/s horizontal grit 6.56 chamber is

Will a grit particle with a radius of 0.10 mm and a specific gravity of 2.65 be collected in a chamber that is 13.5 m in length if the average grit-chamber flow is 0.15 m³/s, the width of the m, and the horizontal velocity is 0.25 m/s? Hint: Use the data below V's = gS 18 V T DE. 12SIP v=0.959 x 10 m²/s horizontal grit 6.56 chamber is

Fundamentals of Geotechnical Engineering (MindTap Course List)

5th Edition

ISBN:9781305635180

Author:Braja M. Das, Nagaratnam Sivakugan

Publisher:Braja M. Das, Nagaratnam Sivakugan

Chapter10: Shear Strength Of Soil

Section: Chapter Questions

Problem 10.10P

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Will a grit particle with a radius of 0.10 mm and a specific gravity of 2.65 be collected in a horizontal grit chamber that is 13.5 m in length if the average grit-chamber flow is 0.15 m³/s, the width of the chamber is 0.56 m, and the horizontal velocity is 0.25 m/s? Hint: Use the data below S-1 V's= 18 v=0.959 x 10-6 m²/s
Solve as soon as possible -- The following data are given for a channel-type grit chamber of length 7.5 m. 1. Flow through velocity = 0.3 m/s 2. The depth of waste water at peak flow in the channel = 0.9 m 3. Specific gravity of inorganic particles = 2.5 4. g 9.80 m/s², μ = 1.002 x 10-3 N-s/m² at = 20°C, Pw = 1000 kg/m³ Assuming that the Stoke's law is valid, the smallest diameter particle that would be removed with 100% efficiency is
3. Consider the following data in the design of grit chamber : 1. Specific gravity of grit = 2.7 %3D 2. Size of grit particle = 0.21 mm %3D 3. Viscosity of water = 1.0 × 10-2 cm²/s The setting velocity (cm/s) of the grit particle will be (a) 1 to 2.5 E (b) 2.6 to 5.0 (c) 5.1 to 7.8 (d) > 7.8
ANSWER MUST BE: (a) t50 = 8.37 years, (b) t90 = 35.96 years, (c) U ≈ 17%, (d) U ≈ 39% A clay specimen was tested in a laboratory consolidation device, whichwas 12.7 mm (½ in.) thick and the top and the bottom boundaries weredrained. A 50% consolidation time on the specimen was obtained as28.4 minutes. Determine the following:(a) Time for 50% consolidation in the field with this soil with a 2.5 mthickness where only the top layer is drained (b) Time for 90% consolidation in the field with this soil with a 2.5 mthickness where only the top layer is drained (c) For the same field condition above, at the end of 1 year after theplacement of load, how much primary consolidation settlementoccurs relative to its final amount of the settlement? (d) The same question as in (c), but at the end of 5 years
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Q2: The dial readings recorded during a consolidation test at a certain load increment are given below. Determine c, by both the square root of time and log of time methods. The thickness of the sample = 2 cm and the sample is drained both sides. Time Dial Reading Time min Dial Reading cm x 10-4 min cm x 10-4 0 240 15 622 0.10 318 H 30 738 C₁=0.848- 0.25 340 60 842 0.50 360 120 930 1.00 385 240 975 2.00 415 1200 1070 C,=0.197 4.00 464 8.00 530 90 H² tso
What can you conclude in the sieve analysis in the image below?
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3- A sand sample is subjected to drainage cutting test with a hollow cylinder device. Rupture occurs with increasing internal pressure while external pressure is constant. At the moment of rupture, the external stress is 200 kPa and the internal stress is 300| Kilopascals - be. Internal and external radii of the sample are 40 and 60 mm. A) Obtain the angle of soil friction. B) At the moment of rupture, what is the axial stress applied to the sample?
The results of a laboratory consolidation test on a clay sample are given below: Pressure, p (kN/m²) Void ratio, e 23.94 1.112 47.88 1.105 95.76 1.080 191.52 0.985 383.04 0.850 766.08 0.731 (43) a) Draw an e-log p plot. (44) b) Determine the pre-consolidation pressure, p. . (45) c) Find the compression index, Ce. Appendix For ø=35°, N¸=57.8, N,=41.4, and N,=41.1. o,'=0;'tan²| 45°+ +2c tan| 45°+
A rock core sample with a diameter of 47.6 mm and a length of 11.21 cm is loaded in uniaxial compressionThe difference in length and diameter recorded during testing are respectively 0.36 mm and 0.044mm for anaxial stress of 78 MPaCalculate the Elastic modulus (GPa) and Poison's ratio tor that rock snecimen.?
Solve this problem The following data are given for a channel-type grit chamber of length 7.5 m. 1. Flow through velocity = 0.3 m/s 2. The depth of waste water at peak flow in the channel = 0.9 m 3. Specific gravity of inorganic particles = 2.5 4. g 9.80 m/s², μ = 1.002 x 10-3 N-s/m² at = 20°C, Pw = 1000 kg/m³ Assuming that the Stoke's law is valid, the smallest diameter particle that would be removed with 100% efficiency is