Write a program using a user defined recursive function to implement the following code segment. main() will call the recursive function and print the value of sum. int n, i, sum; n= last_two_digits_of_your_student_id+3; sum=0; for (i=n-3; i<=n; i++){ sum=sum+i; } printf(“%d”, sum)
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Write a
main() will call the recursive function and print the value of sum.
int n, i, sum;
n= last_two_digits_of_your_student_id+3;
sum=0;
for (i=n-3; i<=n; i++){
sum=sum+i;
}
printf(“%d”, sum)
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- Write the definition of a recursive function int simpleSqrt(int n) The function returns the integer square root of n, meaning the biggest integer whose square is less than or equal to n. You may assume that the function is always called with a nonnegative value for n. Use the following algorithm: If n is 0 then return 0. Otherwise, call the function recursively with n-1 as the argument to get a number t. Check whether or not t+1 squared is strictly greater than n. Based on that test, return the correct result. For example, a call to simpleSqrt(8) would recursively call simpleSqrt(7) and get back 2 as the answer. Then we would square (2+1) = 3 to get 9. Since 9 is bigger than 8, we know that 3 is too big, so return 2 in this case. On the other hand a call to simpleSqrt(9) would recursively call simpleSqrt(8) and get back 2 as the answer. Again we would square (2+1) = 3 to get back 9. So 3 is the correct return value in this case.Write a function that takes in an integer n and computes n!. Do this without recursion. In [ ]: deffactorial_iter(n):"""Takes in an integer n>0 and returns the product of all integers from 1 to n."""# YOUR CODE HEREraiseNotImplementedError() In [ ]: In [ ]: assert factorial_iter(6) == 720 assert factorial_iter(7) == 5040 assert factorial_iter(10) == 3628800CodeW X bFor fun X C Solved x b Answer + x https://codeworko... CodeWorkout X265: Recursion Programmlng Exercise: GCD The greatest common divisor (GCD) for a pair of numbers is the largest positive integer that divides both numbers without remainder. For function GCD , write the missing base case condition and action. This function will compute the greatest common divisor of x and y.You can assume that x and y are both positive integers and that x > y. Greatest common divisor is computed as follows: = x and GCD(x, y) = GCD(y, x % y). Examples: GCD (6, 4) -> 2 Your An swer: 1 public int GCD(int x, int y) { if > { 2. > 3. } else { 4. return GCD(y, x % y); 9. { 7. 1:09 AM 50°F Clear 1V 1. 12/4/2021 甲