Convolution with Impulse (Dirac) Function. Convolution with impulse function can be performed by the following properties: 1. X(t) & (t) = x(t). 2. X(t) S(tito) = x(t+to) 3. x(t+t₁) S(t±+₂). = X(t±ti±t₂). EXP Find graphically, the convolution between x(6) and hit) shown below. Sol -1 xit 1 2 y(t) = x(t) @ h(t). = x(t) @ [s(t) = S(t+1)] = X(t) S(t) = X(t) ⓇS(t+1) - X(t) = x (t+1) = X(t) + [_x(t+1)] y(t) = A (t-1) _A (²+2) A: triangular pulse قسـم الكهرباء h(t) x(t)@s(t)= X(t). 14 2 -X(t+1) -1 'yit! K How did he get the value inside the circle t
Convolution with Impulse (Dirac) Function. Convolution with impulse function can be performed by the following properties: 1. X(t) & (t) = x(t). 2. X(t) S(tito) = x(t+to) 3. x(t+t₁) S(t±+₂). = X(t±ti±t₂). EXP Find graphically, the convolution between x(6) and hit) shown below. Sol -1 xit 1 2 y(t) = x(t) @ h(t). = x(t) @ [s(t) = S(t+1)] = X(t) S(t) = X(t) ⓇS(t+1) - X(t) = x (t+1) = X(t) + [_x(t+1)] y(t) = A (t-1) _A (²+2) A: triangular pulse قسـم الكهرباء h(t) x(t)@s(t)= X(t). 14 2 -X(t+1) -1 'yit! K How did he get the value inside the circle t
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![Convolution with Impulse (Dirac) Function.
Convolution with impulse function can be performed by the
following properties:
1. X(t)
& (t) = x(t). 2. X(t) S(tito) = x(t+to)
3. x(t+t₁) S(t±+₂). = X(t±ti±t₂).
EXP Find graphically, the convolution between x(6)
and hit) shown below.
Sol
-1
xit
1
2
y(t) = x(t) @ h(t).
= x(t) @ [s(t) = S(t+1)]
= X(t)
S(t) = X(t) ⓇS(t+1)
-
X(t) = x (t+1)
= X(t) + [_x(t+1)]
y(t) = A (t-1) _A (²+2)
A: triangular pulse
قسـم الكهرباء
h(t)
x(t)@s(t)= X(t).
14
2
-X(t+1)
-1
'yit!
K
How did he get the
value inside the circle
t](https://content.bartleby.com/qna-images/question/2e310b2c-960d-4a58-8b22-5c1623696321/0ddb8eb3-da26-43b9-882f-6bd27045bd2d/bzawk2e_processed.jpeg)
Transcribed Image Text:Convolution with Impulse (Dirac) Function.
Convolution with impulse function can be performed by the
following properties:
1. X(t)
& (t) = x(t). 2. X(t) S(tito) = x(t+to)
3. x(t+t₁) S(t±+₂). = X(t±ti±t₂).
EXP Find graphically, the convolution between x(6)
and hit) shown below.
Sol
-1
xit
1
2
y(t) = x(t) @ h(t).
= x(t) @ [s(t) = S(t+1)]
= X(t)
S(t) = X(t) ⓇS(t+1)
-
X(t) = x (t+1)
= X(t) + [_x(t+1)]
y(t) = A (t-1) _A (²+2)
A: triangular pulse
قسـم الكهرباء
h(t)
x(t)@s(t)= X(t).
14
2
-X(t+1)
-1
'yit!
K
How did he get the
value inside the circle
t
