Concept explainers
Reduce each of the networks shown in Figure P2.1 to a single equivalent resistance by combining resistances in series and parallel.
* Denotes that answers are contained in the Student Solutions flies. See Appendix E for more information about accessing the Student Solutions
FIgure P2.1
(a)
The equivalent resistance by combining resistance in series.
Answer to Problem 2.1P
The value of equivalent resistance is
Explanation of Solution
Calculation:
The required diagram is shown in Figure 1.
Mark the resistance
The required diagram is shown in Figure 2.
The value of resistance
Substitute
The required diagram is shown in Figure 3.
The value of resistance
Substitute
The required diagram is shown in Figure 4.
The value of resistance
Substitute
The required diagram is shown in Figure 5.
The value of resistance
Substitute
The required diagram is shown in Figure 6.
Conclusion:
Therefore, the value of equivalent resistance is
(b)
The equivalent resistance by combining resistance in series.
Answer to Problem 2.1P
The value of equivalent resistance is
Explanation of Solution
Calculation:
The required diagram is shown in Figure 7.
The value of resistance
Substitute
The required diagram is shown in Figure 8.
The value of resistance
Substitute
The equivalent resistance is shown in Figure 9.
The value of resistance
Substitute
The required diagram is shown in Figure 10.
The value of resistance
Substitute
The equivalent resistance is shown in Figure 11.
The value of resistance
Substitute
The required diagram is shown in Figure 12.
The value of resistance
Substitute
The required diagram is shown in Figure 13.
Conclusion:
Therefore, the value of equivalent resistance is
Want to see more full solutions like this?
Chapter 2 Solutions
Electrical Engineering: Principles & Applications (7th Edition)
- Consider the circuit below. Point b is grounded(potential=0). Determine the potential at a. Two resistors of cylindrical shape, A & B, made from the same material. The length of resistor A is twice that of resistor B. The diameter of B is half that of A. Determine the ratio of Resistance of A/Resistance of B.arrow_forwardWhat approximation do we usually make in circuit theory? -A current-carrying particle is the current. -A current-carrying particle has no charge. -A current-carrying particle does't accelerate. -A current-carrying particle is mythical. -A current-carrying particle is massless Please see diagram for more details.arrow_forwardplease have step by step solution and explainarrow_forward
- Consider the circuit shown in Figure P1.68. a. Which elements are in series?b. Which elements are in parallel? c. Apply Ohm’s and Kirchhoff’s laws to solve for R x.arrow_forwardQuestion 3: A very simple model for the distribution of clectricity to a typical home is shown in the figure below. Some of components labeled a, b, c, d, c, f, g and h represent the electrical source to the home, some represent the wires that carry the electrical current from the source to the devices in the home requiring electrical power, some represent lamps, televisions, hair dryers and other devices that require power. Assume you are an engineer in charge of a project and one of your subordinate engineers reports that the interconnection in the figure does not pass the power check. The data for the interconnection are given in the table below. Is the subordinate correer? Explain your answer. If the subordinate is correct, find the error in the data. Explain your answer clearly. Based on your answer identify that which label(s) used for the electrical source, wires or other devices. a e harrow_forwardFor the given circuit, find the currents and (a) right after switch S is closed and (b) a long time after switch S has been closed. Let's now assume that the switch has been closed for a long time, and we again open the switch. (c) find the three currents right after the switch is open, and (d) find the potential drop across the resistor R2. (e) What would be values of all three currents a long time after switch S was opened second time? to R=120n R=30r L%3D3H %3Darrow_forward
- Please determine equivalent resistance and currentsarrow_forwardMore details and step by step solutionsarrow_forwardAssuming R0 = 2 , R1 = 1 , R2 = 4/3 , R3 = 6 , and VS = 12 V in the circuit of Figure P2.55, use Kirchhoff’s voltage law and Ohm’s law to finda. ia, ib, and ic.b. The current through each resistance.arrow_forward
- Find the equivalent resistance looking into terminals a and b in Figure P2.3.arrow_forwardFor the circuit shown in Figure P2.49, find the equivalent resistance, where R1 = 5 , R2 = 1 k , R3 = R4 = 100 , R5 = 9.1 and R6 = 1 k .arrow_forwardUsing these diagrams of circuits, what are the steps and materis to create these kind of circuits?arrow_forward
- Introductory Circuit Analysis (13th Edition)Electrical EngineeringISBN:9780133923605Author:Robert L. BoylestadPublisher:PEARSONDelmar's Standard Textbook Of ElectricityElectrical EngineeringISBN:9781337900348Author:Stephen L. HermanPublisher:Cengage LearningProgrammable Logic ControllersElectrical EngineeringISBN:9780073373843Author:Frank D. PetruzellaPublisher:McGraw-Hill Education
- Fundamentals of Electric CircuitsElectrical EngineeringISBN:9780078028229Author:Charles K Alexander, Matthew SadikuPublisher:McGraw-Hill EducationElectric Circuits. (11th Edition)Electrical EngineeringISBN:9780134746968Author:James W. Nilsson, Susan RiedelPublisher:PEARSONEngineering ElectromagneticsElectrical EngineeringISBN:9780078028151Author:Hayt, William H. (william Hart), Jr, BUCK, John A.Publisher:Mcgraw-hill Education,