Chapter 9, Problem 9.35P

A moving electron collides with a stationary electron and an electron-positron pair comes intobeing as a result (a positron is a positively charged electron). When all four particles have thesame velocity after the collision, the kinetic energy required for this process is a minimum.Use a relativistic calculation to show that KEmin = 6 mc2 , where m is the rest mass of the electron.

A linear particle accelerator using beta particles collides electrons with their anti-matter counterparts, positrons. The accelerated electron hits the stationary positron with a velocity of 98 x 106 m/s, causing the two particles to annihilate.If two gamma photons are created as a result, calculate the energy of each of these two photons, giving your answer in MeV (mega electron volts), accurate to 1 decimal place. Take the mass of the electron to be 5.486 x 10-4 u, or 9.109 x 10-31 kg.Note: Assume that the kinetic energy is also converted into the gamma rays, and is included in the two photons.

An electron is accelerated inside a parallel plate capacitor. The electron leaves the negative plate with à negligible initial velocity and then after the acceleration it hits the positive plate with a final velocity B. The distance between the plates is 11.6 cm, and the voltage difference is 107 kV. Determine the final velocity B of the electron using classical mechanics. (The rest mass of the electron is 9.11x1031 kg, the rest energy of the electron is 511 kev.) 6.471x10-1 You are correct. Your receipt no. is 151-494 e Previous Tries What is the final velocity B of the electron if you use relativistic mechanics? 0.948*10°8 Submit Answer Incorrect. Tries 8/12 Previous Tries Send Feedback Post Discussion

A linear particle accelerator using beta particles collides electrons with their anti-matter counterparts, positrons. The accelerated electron hits the stationary positron with a velocity of 29 x 106 m/s, causing the two particles to annihilate.If two gamma photons are created as a result, calculate the energy of each of these two photons, giving your answer in MeV (mega electron volts), accurate to 1 decimal place. Take the mass of the electron to be 5.486 x 10-4 u, or 9.109 x 10-31 kg.

If a particle of mass m moves with velocity v = (dr/dt) in the field, show that if E is constant the total energy of the particle E is given by E = (1/2)m (dr/dt)^2 + (1/5)kr^3 Make a rough sketch to describe this field.

6.3 A pion moving along x-axis with B = 0.8 in the lab system decays by emitting a muon with B' 0.268 along the incident direction (x'-axis) in the rest system of pion. Find the velocity of the muon (magnitude and direction) in the lab system.

A pion has a rest energy of 135 MeV. It decays into two gamma-ray photons, bursts of electromagnetic radiation that travel at the speed of light. A pion moving through the laboratory at v=0.98c decays into two gamma-ray photons of equal energies, making equal angles (theta) with the original direction of motion. Find the angle (theta) and the energies of the two gamma-ray photons.

Sunlight above the Earth’s atmosphere has an intensity of 1.30 kW/m2 . If this is reflected straight back from a mirror that has only a small recoil, the light’s momentum is exactly reversed, giving the mirror twice the incident momentum. (a) Calculate the force per square meter of mirror. (b) Very low mass mirrors can be constructed in the near weightlessness of space, and attached to a spaceship to sail it. Once done, the average mass per square meter of the spaceship is 0.100 kg. Find the acceleration of the spaceship if all other forces are balanced. (c) How fast is it moving 24 hours later?

a) In the rest frame of an electron, an incident y-ray with an energy of 0.25 MeV interacts with the electron. Following the collision, the y-ray has a final energy of 0.1 MeV. What is the angle between the y-ray's initial direction and its final direction? Explain how this type of scattering differs from the classical prediction.