✓ Defining Equality [54] # @title Defining Equality def interval equality(self, other): Return True iff the intervals self and other are equal, and False otherwise."▪▪▪▪▪ # Remember, other is not guaranteed to be an Interval. ### YOUR CODE HERE + Os Interval. _eq_ = interval_equality [42] i = Interval(3, 5) j = Interval(4, 5) i == j # Tests 5 points. assert i != j assert Interval(5, 7) == Interval(5, 7) E [↑] Traceback (most recent call last) AssertionError in () 2 3 assert i != j ----> 4 assert Interval(5, 7) Interval(5, 7) AssertionError:
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- #define _CRT_SECURE_NO_WARNINGS #include <stdio.h> #define NAME_LEN 25 #define MAX_PARTS 100 struct part { int number; char name[NAME_LEN + 1]; int on_hand; double price; } inventory[MAX_PARTS]; int num_parts = 0; int find_part(int number); void insert(void); void search(void); void update(void); void print(void); int read_line(char str[], int n); int main(void) { char code; for (;;) { printf("Enter operation code: "); scanf(" %c", &code); while (getchar() != '\n') /* skips to end of line */ ; switch (code) { case 'i': insert(); break; case 's': search(); break; case 'u': update(); break; case 'p': print(); break; case 'q': return 0; default: printf("Illegal code\n"); } printf("\n"); } } int find_part(int number) { int i; for (i = 0; i < num_parts; i++) if…Sum of two squares def sum_of_two_squares(n): Some positive integers can be expressed as a sum of two squares of some positive integers greater than zero. For example, 74 = 49 + 25 = 72 + 52. This function should find and return a tuple of two positive integers whose squares together add up to n, or return None if the parameter n cannot be broken into a sum of two squares. To facilitate the automated testing, the returned tuple must present the larger of its two numbers first. Furthermore, if some integer can be broken down to a sum of squares in several ways, return the breakdown that maximizes the larger number. For example, the number 85 allows two such representations 72 + 62 and 92 + 22 , of which this function must return (9, 2). The technique of two approaching indices that start from the beginning and end of a sequence, respectively, and approach each other until they meet somewhere, used in the function two_summers in one of our class examples, is directly applicable to this…Sum of two squares def sum_of_two_squares(n): Some positive integers can be expressed as a sum of two squares of some positive integers greater than zero. For example, 74 = 49 + 25 = 72 + 52. This function should find and return a tuple of two positive integers whose squares together add up to n, or return None if the parameter n cannot be broken into a sum of two squares.To facilitate the automated testing, the returned tuple must present the larger of its two numbers first. Furthermore, if some integer can be broken down to a sum of squares in several ways, return the breakdown that maximizes the larger number. For example, the number 85 allows two such representations 72 + 62 and 92 + 22 , of which this function must return (9, 2).The technique of two approaching indices that start from the beginning and end of a sequence, respectively, and approach each other until they meet somewhere, used in the function two_summers in one of our class examples, is directly applicable to this…
- Sum of two squares def sum_of_two_squares(n): Some positive integers can be expressed as a sum of two squares of some positive integers greater than zero. For example, 74 = 49 + 25 = 7^2 + 5^2. This function should find and return a tuple of two positive integers whose squares together add up to n, or return None if the parameter n cannot be broken into a sum of two squares.To facilitate the automated testing, the returned tuple must present the larger of its two numbers first. Furthermore, if some integer can be broken down to a sum of squares in several ways, return the breakdown that maximizes the larger number. For example, the number 85 allows two such representations 7^2 + 6^2 and 9^2 + 2^2 , of which this function must return (9, 2).The technique of two approaching indices that start from the beginning and end of a sequence, respectively, and approach each other until they meet somewhere is directly applicable to this problem. In this problem, these indices crawl towards each…def count_odds(values): 695 >>> count_odds([[111, 165, 207]]) [3] >>> count_odds([[1, 2], [8], [5, 6, 7]]) [1,0, 2] 695Count consecutive summers def count_consecutive_summers(n): Like a majestic wild horse waiting for the rugged hero to tame it, positive integers can be broken down as sums of consecutive positive integers in various ways. For example, the integer 42 often used as placeholder in this kind of discussions can be broken down into such a sum in four different ways: (a) 3 + 4 + 5 + 6 + 7 + 8 + 9, (b) 9 + 10 + 11 + 12, (c) 13 + 14 + 15 and (d) 42. As the last solution (d) shows, any positive integer can always be trivially expressed as a singleton sum that consists of that integer alone. Given a positive integer n, determine how many different ways it can be expressed as a sum of consecutive positive integers, and return that count. The number of ways that a positive integer n can be represented as a sum of consecutive integers is called its politeness, and can also be computed by tallying up the number of odd divisors of that number. However, note that the linked Wikipedia de0inition…
- if L1={ab,b} L2={abb,bb} then L1L2= * O {ababb,abbb,abbab,bbab} O {ab,b,abb,bb} O {ababb,abbb,babb,bbb} O {abbab,abbb,bbab,bbb}Match the C-function on the left to the Intel assemble function on the right. W: cmpl $4 movl %edi , %edi jmp .L4(,%rdi,8) %edi .L3: movl $17, %eax ret .15: movl $3, %eax int A ( int x , int y) { int a ; if ( x == 0 ) else i f ( x == 1 ) a = 3 ; else i f ( x == 2 ) a = 2 0 ; else i f ( x == 3 ) a = 2 ; else i f ( x == 4 ) a = 1 ; ret .L6: a = 17; movl $20, %eax ret .L7: movl $2, %eax ret else a = 0; .L8: return a ; movl $1, %eax .L2: ret . section .rodata . L4: .quad .L3 .quad .L5 .quad .L6 .quad .L7 .quad .L8 X: testl %edi, %edi je cmpl je cmpl je стр1 je cmpl .L16 $1, %edi .L17 $2, %edi .L18 $3, %edi int B (int x, int y) { int a; switch (x) { .L19 $4, %edi %al movzbl %al, %eax case 0: a = 17; break; sete break; case 1: a = 3; case 2: a = 20; break; case 3: a = 2; break; case 4: a = 1; a = 0; } return a; ret .L16: break; movl $17, %eax ret .L17: movl $3, %eax } ret .L18: movl $20, %eax ret .L19: movl ret $2, %eax* .gcd(91, 287) =gcd(91, 14) yes No
- Brussel's choice def brussels_choice_step(n, mink, maxk): This problem is adapted from another jovial video "The Brussel's Choice" of Numberphile (a site so British that you just know there has to be a Trevor and a Colin somewhere in there) whose first five minutes you should watch to get an idea of what is going on. This function should compute and return the list of all numbers that the positive integer n can be converted to by treating it as a string and replacing some substring m of its digits with the new substring of either 2*m or m/2, the latter substitution allowed only when m is even so that dividing it by two produces an integer. This function should return the list of numbers that can be produced from n in a single step. To keep the results more manageable, we also impose an additional constraint that the number of digits in the chosen substring m must be between mink and maxk, inclusive. The returned list must contain the numbers in ascending sorted order.L et D= { s, d, b}, E= { c, k}, G= { a, k }, U={a, b, c, d, k, s} DUE=Count consecutive summers def count_consecutive_summers(n): Like a majestic wild horse waiting for someone to come and tame it, positive integers can be broken down as sums of consecutive positive integers in various ways. For example, the integer 42 often used as placeholder in this kind of discussions can be broken down into such a sum in four different ways: (a) 3 + 4 + 5 + 6 + 7 + 8 + 9, (b) 9 + 10 + 11 + 12, (c) 13 + 14 + 15 and (d) 42. As the last solution (d) shows, any positive integer can always be trivially expressed as a singleton sum that consists of that integer alone. Given a positive integer n, determine how many different ways it can be expressed as a sum of consecutive positive integers, and return that count. The count of how many different ways a positive integer n can be represented as a sum of consecutive integers is also called its politeness, and can be alternatively computed by counting how many odd divisors that number has. However, note that the linked…