Human Heredity: Principles and Issues (MindTap Course List)
11th Edition
ISBN: 9781305251052
Author: Michael Cummings
Publisher: Cengage Learning
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Chapter 11, Problem 15QP
Summary Introduction
To explain: The working principle of the anticipation theory.
Introduction: Trinucleotide repeats are the sequences of three
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Synpolydactyly is an abnormality characterized by webbing between partially or completely duplicated fingers or toes (Figure 18.15). The same mutations that cause the human phenotype give rise to a similar phenotype in mice. In what family of genes do you think these mutations occur?
Different mutations in the WDR62 gene that inactivate gene function were found in the genomes of many different people with microcephaly. This information provided strong support for the idea that the WDR62 gene mutation causes microcephaly.
The human genome sequence identified WDR62 as one of the approximately 27,000 genes in the human genome. What information about the function of WDR62 do you think was learned originally from the DNA sequence of the normal human genome?
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Huntington disease (HD) is an inherited neurodegenerative disorder characterized by gradual, irreversible impairment of psychological, motor, and cognitive functions. Symptoms typically appear in middle age, but onset can occur at almost any age, and the course of the disease can range from 15 to 20 years. The molecular basis of HD is becoming better understood, and the genetic mutation has been traced to a gene that encodes a large protein of unknown function. In individuals who will not develop HD, a region of the gene that encodes the N-terminus of this protein has a sequence of CAG codons (for glutamine) repeated 6 to 39 times in succession.
In individuals with adult-onset HD, this codon (3 nucleotides) is typically repeated 40 to 55 times
In those with childhood-onset HD, it is repeated more than 70 times.
*codon: refers to the 3 nucleotides that code for amino acid.
A small portion of the coding sequence of the HD gene is given below. The nucleotide sequence of the DNA is…
Chapter 11 Solutions
Human Heredity: Principles and Issues (MindTap Course List)
Ch. 11.4 - Consumer products including bandages, cotton...Ch. 11.4 - Prob. 2EGCh. 11 - Prob. 1CSCh. 11 - Prob. 2CSCh. 11 - Prob. 3CSCh. 11 - Prob. 1QPCh. 11 - Achondroplasia is an autosomal dominant form of...Ch. 11 - Why is it almost impossible to directly measure...Ch. 11 - What are the factors that influence the mutation...Ch. 11 - Achondroplasia is a rare dominant autosomal defect...
Ch. 11 - Although it is well known that X-rays cause...Ch. 11 - Prob. 7QPCh. 11 - Bruce Ames and his colleagues have pointed out...Ch. 11 - Define and compare the following types of...Ch. 11 - If the coding region of a gene (the exons)...Ch. 11 - Two types of mutations discussed in this chapter...Ch. 11 - Prob. 12QPCh. 11 - A frameshift mutation is caused by a: a....Ch. 11 - In the gene-coding sequence shown here, which of...Ch. 11 - Prob. 15QPCh. 11 - Familial retinoblastoma, a rare autosomal dominant...Ch. 11 - Tay-Sachs disease is an autosomal recessive...Ch. 11 - Replication involves a period of time during which...Ch. 11 - Our bodies are not defenseless against mutagens...Ch. 11 - The cystic fibrosis gene encodes a chloride...
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- Explain what happens to the sequence of DNA during trinucleotiderepeat expansion (TNRE). If someone was mildly affected with a TNRE disorder, what issues would be important when considering possible effects in future offspring?arrow_forwardOne of the two genes known to be mutated in cases of Hypokalemic periodic paralysis (which is inherited in an autosomal dominant pattern but known to affect males more often than females) is the calcium voltage-gated channel subunit alpha1 S (CACNA1S). What is known about the gene is recorded here: https://www.ensembl.org/Homo_sapiens/Gene/Summary?db=core;g=ENSG00000081248;r=1:201039512-201112451 Please navigate to the link above and use the information and link-outs from the page to answer the following question. GIVE YOUR ANSWER AS A NUMBER ONLY, NO UNITS: What is the size in amino acid residues of the CACNA1S transcript named CACNA1S-202? Answer: The size of the CACNA1S transcript named CACNA1S-202 is how many amino acid residues.arrow_forwardOne of the two genes known to be mutated in cases of Hypokalemic periodic paralysis (which is inherited in an autosomal dominant pattern but known to affect males more often than females) is the calcium voltage-gated channel subunit alpha1 S (CACNA1S). What is known about the gene is recorded here: https://www.ensembl.org/Homo_sapiens/Gene/Summary?db=core;g=ENSG00000081248;r=1:201039512-201112451 Please navigate to the link above and ensure that you click to reveal the transcript table. Then use the information in the table to answer the following question. PLEASE GIVE YOUR ANSWER AS A NUMBER ONLY, NO UNITS What is the size in base pairs of the CACNA1S transcript named CACNA1S-202? Answer: The size of the CACNA1S transcript named CACNA1S-202 isarrow_forward
- One of the two genes known to be mutated in cases of Hypokalemic periodic paralysis (which is inherited in an autosomal dominant pattern but known to affect males more often than females) is the calcium voltage-gated channel subunit alpha1 S (CACNA1S). What is known about the gene is recorded here: https://www.ensembl.org/Homo_sapiens/Gene/Summary?db=core;g=ENSG00000081248;r=1:201039512-201112451 Please navigate to the link above and use the information and link-outs from the page to answer the following questions ANSWER ONLY IN UPPERCASE LETTERS, NO UNITS: Using the left-hand menu to view the sequence for CACNA1S, what are the last three nucleic acid bases of exon 1?arrow_forwardOne of the two genes known to be mutated in cases of Hypokalemic periodic paralysis (which is inherited in an autosomal dominant pattern but known to affect males more often than females) is the calcium voltage-gated channel subunit alpha1 S (CACNA1S). What is known about the gene is recorded here: https://www.ensembl.org/Homo_sapiens/Gene/Summary?db=core;g=ENSG00000081248;r=1:201039512-201112451 Please navigate to the link above and use the information and link-outs from the page to answer the following question. What is the NCBI accession number (including the version) of the RefSeq Match for the first transcript (CACNA1S-201)?arrow_forwardScientists have observed that individuals with LOW birthweight are MORE likely to become obese as teenagers. To study this observation in more depth, a scientist compared the methylation of the promoter region of the leptin gene in low birthweight (LBW) and normal birthweight (NBW) individuals by treating isolated DNA from these individuals with bisulfite and comparing the results to untreated DNA. The results are shown below. What conclusion can you draw? Untreated: ATTCGATTCGCGAA Treated NBW: ATTCGATTCGCGAA Treated LBW: ATTTGATTCGTGAA Scientists have observed that individuals with LOW birthweight are MORE likely to become obese as teenagers. To study this observation in more depth, a scientist compared the methylation of the promoter region of the leptin gene in low birthweight (LBW) and normal birthweight (NBW) individuals by treating isolated DNA from these individuals with bisulfite and comparing the results to untreated DNA. The results are shown below. What…arrow_forward
- As discussed, the overall rate of mutations in humans is estimated to be about 1 × 10−8 mutations per base pair per generation. How many new mutations would you expect each person to carry, on average, based on this mutation rate? Other studies have estimated that each person carries about 100 new loss-of-function mutations. How does this number compare with your estimate of the number of mutations based on the mutation rate? What might account for any differences?arrow_forwardThe phenotype of a heterozygous mouse (Aa) is agouti. The agouti banding pattern is due to altered expression of the agouti gene. Which of the following statement is false? a) Expression of the agouti gene inhibits the production of eumelanin. b) Evidence suggests that the agouti gene is only expressed in tissues associated with fur production. c) Epigenetic markers silence the agouti gene resulting in dark pigmentation at the tip and root of the hair. d) All of the abovearrow_forwardThe genetic alteration responsible for sickle-cell anemia in humans involves: a transition mutation from A to G, substituting glutamic acid for valine in a-globin a transversion mutation from T to A, substituting valine for glutamic acid in b-globin a transition mutation from T to C, substituting valine for glutamic acid in b-globin a transversion mutation from G to C, substituting glutamic acid for valine in a-globin a frameshift mutation of one ATC codon, removing glutamic acid from b-globinarrow_forward
- Most black bears (Ursus americanus) are black or brown in color. However, occasional white bears of this species appear in some populations along the coast of British Columbia. Kermit Ritland and his colleagues determined that white coat color in these bears results from a recessive mutation (G) caused by a single nucleotide replacement in which guanine substitutes for adenine at the melanocortin-1 receptor locus (mc1r), the same locus responsible for red hair in humans (K. Ritland, C. Newton, and H. D. Marshall. 2001. Current Biology 11:1468–1472). The wild-type allele at this locus (A) encodes black or brown color. Ritland and his colleagues collected samples from bears on three islands and determined their genotypes at the mc1r locus: Genotype Number AA 42 AG 24 GG 21 a. What are the frequencies of the A and G alleles in these bears? b. Give the genotypic frequencies expected if the population is in Hardy– Weinberg equilibrium. c. Use a chi-square test to compare the number of…arrow_forwardLeber Congenital Amaurosis (LCA) causes progressive vision loss due to defects in the gene that encodes RPE65 isomerase. Affected individuals are homozygous recessive for mutant alleles of the RPE65 gene. You are trying to determine the molecular nature of the mutations in three individuals with LCA. For ease of analysis, you may assume that each individual is homozygous for the same mutant allele (though the three individuals have different mutations than each other). You use the polymerase chain reaction to amplify DNA from each patient and you determine the sequence of the DNA and compare it to unaffected individuals. You identify the following differences. Note that the non-template strand of DNA is given and the changes are highlighted using red boldface. You can assume that the sequences are in the first reading frame (eg. the first three nucleotides of each sequence is a codon). The coding region of the gene is 1602 bp and the position of the sequences shown below is…arrow_forwardGene mutations can be classified in two major ways:(1) hereditary or germline mutations that are inherited from a parent and are present throughout a person’s life in virtually every cell in the body.(2) acquired or somatic mutations that occur at some time during a person’s life and are present only in certain cells, not in every cell in the body.If there is no family history of a particular disease but a child has the disease then it may have arisen due to a(n) ________ mutation early during development. A) acquired B) inherited C) silent D) transitionarrow_forward
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