(a)
The magnitude of the magnetic field the cord produces midway between the two wires
Answer to Problem 78QAP
Magnitude of the magnetic field the cord produces midway between the two wires=
Explanation of Solution
Given info:
Formula used:
Calculation:
Conclusion:
Magnitude of the magnetic field the cord produces midway between the two wires=
(b)
The magnitude of the magnetic field the cord produces 2.0 mm from one of the wires in the same plane in which the two wires lie
Answer to Problem 78QAP
Magnitude of the magnetic field the cord produces 2.0 mm from one of the wires in the same plane in which the two wires lie=
Explanation of Solution
Given info:
Formula used:
Calculation:
For the wire on the right side d =2 mm
Field is directed outwards.
For the wire on the left side d =2+4 mm=6 mm
Field is directed inwards.
Field is directed outwards.
Conclusion:
Magnitude of the magnetic field the cord produces 2.0 mm from one of the wires in the same plane in which the two wires lie=
(c)
Comparison of previous magnetic fields with earth's magnetic field
Answer to Problem 78QAP
For case a),
For case b),
Explanation of Solution
Given info:
Formula used:
Calculation:
For case a),
For case b),
Conclusion:
For case a),
For case b),
(d)
Magnetic force do the two wires exert on one another
Answer to Problem 78QAP
Force=
Force is very small
Explanation of Solution
Given info:
Formula used:
Calculation:
Force on each wire.
Force is very small
Conclusion:
Force=
Force is very small
Want to see more full solutions like this?
Chapter 19 Solutions
COLLEGE PHYSICS
- Determine the initial direction of the deflection of charged particles as they enter the magnetic fields as shown in Figure P22.2. Figure P22.2.arrow_forwardFigure CQ19.7 shows a coaxial cable carrying current I in its inner conductor and a return current of the same magnitude in the opposite direction in the outer conductor. The magnetic field strength at r = r0 is Find the ratio B/B0, at (a) r = 2r0 and (b) r = 4r0. Figure CQ19.7arrow_forwardWhy is the following situation impossible? Figure P28.46 shows an experimental technique for altering the direction of travel for a charged particle. A particle of charge q = 1.00 C and mass m = 2.00 1015 kg enters the bottom of the region of uniform magnetic field at speed = 2.00 105 m/s, with a velocity vector perpendicular to the field lines. The magnetic force on the particle causes its direction of travel to change so that it leaves the region of the magnetic field at the top traveling at an angle from its original direction. The magnetic field has magnitude B = 0.400 T and is directed out of the page. The length h of the magnetic field region is 0.110 m. An experimenter performs the technique and measures the angle at which the particles exit the top of the field. She finds that the angles of deviation are exactly as predicted. Figure P28.46arrow_forward
- A magnetic field directed into the page changes with time according to B = 0.030 0t2 + 1.40, where B is in teslas and t is in seconds. The field has a circular cross section of radius R = 2.50 cm (see Fig. P23.28). When t = 3.00 s and r2 = 0.020 0 m, what are (a) the magnitude and (b) the direction of the electric field at point P2?arrow_forwardCalculate the magnitude of the magnetic field at a point 25.0 cm from a long, thin conductor carrying a current of 2.00 A.arrow_forwardThe accompanying figure shows a cross-section of a long, hollow, cylindrical conductor of inner radius r1= 3.0 cm and outer radius r2= 5.0 cm. A 50-A current distributed uniformly over the cross-section flows into the page. Calculate the magnetic field at r = 2.0 cm. r = 4.0 cm. and r = 6.0 cm.arrow_forward
- Physics for Scientists and Engineers with Modern ...PhysicsISBN:9781337553292Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningPrinciples of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningPhysics for Scientists and EngineersPhysicsISBN:9781337553278Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
- Physics for Scientists and Engineers, Technology ...PhysicsISBN:9781305116399Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningCollege PhysicsPhysicsISBN:9781285737027Author:Raymond A. Serway, Chris VuillePublisher:Cengage LearningCollege PhysicsPhysicsISBN:9781305952300Author:Raymond A. Serway, Chris VuillePublisher:Cengage Learning