Concept explainers
(a)
The acceleration of a thrown base-ball.
Answer to Problem 31QAP
The acceleration of the thrown baseball =
where
d = the displacement of the ball from behind the body of the pitcher to the point where it is released (Refer the picture below)
Explanation of Solution
Given:
During this calculation it is assumed that the baseball undergoes constant linear acceleration. Also, it is assumed that the linear velocity of the baseball when it is thrown is
Formula used:
Calculation:
During the throwing process the baseball is at rest in pitcher's hand. This means that that the initial velocity of the baseball is 0 ms-1. Assume that the pitcher releases the baseball at a linear velocity of
Also, the difference between the two positions is equal to d. Hence substituting to the above equation;
Conclusion:
The acceleration of the thrown baseball =
Where
d = the displacement of the ball from behind the body of the pitcher to the point where it is released
(b)
The acceleration of a kicked soccer ball.
Answer to Problem 31QAP
The acceleration of the thrown baseball = - (
where
d = the displacement of the soccer ball
Explanation of Solution
Given:
During this calculation it is assumed that the soccer ball undergoes constant linear acceleration. Also it is assumed that the linear velocity of the baseball when it is thrown is
Formula used:
Calculation:
It is assumed that player A kicks the soccer ball with a liner velocity and the player B catches the soccer ball. When player B catches the soccer ball the velocity of the ball would be zero. It is assumed that the ball travels a distance of d during this process.
Note in this case the final velocity is zero hence the sign of the acceleration is negative.
Conclusion:
The acceleration of the thrown baseball = - (
where
d = the displacement of the soccer ball
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Chapter 2 Solutions
COLLEGE PHYSICS
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