A compound having molecular weight 151.163 g/mol is determined in a sample. A 0.0302 g sample was dissolved in an aqueous solvent and diluted the solution to 1 L. The solution has λ max at 243 nm (ε=2.6×104 cm-1 mol-1 L). The solution exhibits an absorbance of 0.642 in a 2 cm cell. Calculate the percentage of the above compound in the sample.

A compound having molecular weight 151.163 g/mol is determined in a sample. A 0.0302 g sample was dissolved in an aqueous solvent and diluted the solution to 1 L. The solution has λ max at 243 nm (ε=2.6×104 cm-1 mol-1 L). The solution exhibits an absorbance of 0.642 in a 2 cm cell. Calculate the percentage of the above compound in the sample.

Chemistry & Chemical Reactivity

10th Edition

ISBN:9781337399074

Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel

Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel

Chapter4: Stoichiometry: Quantitative Information About Chemical Reactions

Section4.9: Spectrophotometry

Problem 4.14CYU

See similar textbooks

Similar questions

What is the concentration of a solution with an absorbance of 0.23 a.u. in ppm when y=45.3509y
The molar absorptivity constant of a particular chemical is 2.31 M/cm. Determine the concentration of a solution made from this chemical that has an absorbance of 0.408 with a cell path length of 1.12 cm.
The nitrite in a series of standard solutions (mg/L, n = 5) are converted to azo dye and the slope of the calibration curve is 2.0 ppm. A 10.00-mL mineral water sample is treated in the same way as standards and diluted to a final volume of 100.00-mL It gives an absorbance of 0.80. The absorbance of blank solution under the same conditions is 0.10. Calculate ppm (mg/L) of NO2 (46 g/mol) and the molarity of NaNO2 (69 g/mol) in the original sample
(b) A compound having molecular weight 151.163 g/mol is determined in a sample. A 0.0302 g sample was dissolved in an aqueous solvent and diluted the solution to 1 L. The solution has A max at 243 nm (ɛ=2.6×104 cm1 mol1 L). The solution exhibits an absorbance of 0.642 in a 2 cm cell. Calculate the percentage of the above compound in the sample.
In an analytical laboratory a chemical compound namely Paracetamol (151.163 g/mol) is determined in a sample. A sample weighing 0.0295 g was dissolved in a solvent and diluted the solution to 1 L. The solution has λ max at 243 nm (ε=2.6×104 cm-1 mol-1 L). The solution exhibits an absorbance of 0.638 in a 2 cm cell. Calculate the percentage paracetamol in the sample.
Calculate the absorbance of 0.00038 moles in 24.2 mL of solution given the molar absortivity is 1168 M-1 cm-1 and the path length is 0.6 cm. Report your answer to 3 significant figures.
A solution of Tryptophan has an absorbance at 280 nm of 0.54 in a 0.5 cm length cuvette. Given the absorbance coefficient of trp is 6.4 x 103 Lmol-1cm-1. What is the concentration of solution? The options are as follows A) 0.17 x10-3 mol/L B)2.56x10-3mol/L C)0.17x10+3mol/L D)2.56x10+3mol/L
Q3) A solution of Tryptophan has an absorbance at 280 nm of 0.25 in a 0.5 cm length cuvette. Given the absorbance coefficient of Tryptophan is 6.4 × 103 L Mol-1 cm-1. What is the concentration of solution?
an absorbance of a solution with a pathlength of 1.00 cm is 0.544 and concentration is 1.40x10^ ^ -3 M , what is its molar absorptivity?
1. How would you find the solution for this dilution and absorbance problem? What would the set-up for solving this look like? (A = 0.0252C(ppm) - 0.0162)
The un-ionized form of the weak acid HA does not absorb in the visible region. When it ionizes, its conjugate base (A-) absorbs light strongly at 510 nm. The following data were obtained by measuring the absorbance at 510 nm of solutions with a concen- tration of 1.0 x 104 M HA in different pH buffers. pH Absorbance 2.0 0.00 3.0 0.00 4.0 0.00 5.0 0.025 6.0 0.180 7.0 0.480 8.0 0.570 9.0 0.595 10.0 0.595 11.0 0.595 12.0 0.595 What is the approximate pK of HA?
An unknown sample of Cu2+gave an absorbance of 0.262. Then 1.00 mL of solution containing 100 ppm (ug/mL)Cu2+was mixed with 95.0 mL of the unknown and the mixture was diluted to 100 mL in a volumetric flask with deionized water. The absorbanceof the new solution was 0.500. a.Denoting the initial unknown concentrationas [Cu2+]i,write an expression for the final concentrationafter dilution [Cu2+] b.Find [Cu2+]in the unknown.