As a roller coaster car crosses the top of a 40m diameter loop-the-loop its apparent weight is the same as its true weight. What is the car’s speed at the top
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- 5. View the YouTube video: Tony Hawk's Loop of Death. The video shows skateboarders going through a loop-the-loop. Assume the top of the ramp is a distance 3.25R above the ground where R is the radius of the loop and the skateboarder has mass M. The skateboarder starts from rest at the top of the ramp and successfully goes around the loop. a. What is the skateboarder's speed at the top of the loop? b. What is the normal force that the track exerts on the skateboarder at the top of the loop? Suggestion: draw the free body diagram. c. What is the minimum speed of the skateboarder at the top of the loop so that the skateboarder stays in contact with the track?Under good conditions, a car can travel at a maximum speed of vmax around a particular unbanked curve. In the aftermath of an ice storm, however, driving at that same speed will cause the car to slide off the road. Which of the statements below best describes why this is true? a. The friction force is no longer strong enough to balance the centripetal force and give the car zero acceleration. b. The friction force is needed to do negative work on the car to reduce the car’s kinetic energy. c. The friction force no longer provides a strong enough unbalanced force to change the car’s velocity quickly enough to stay on the curve. d. The car “floats” on the ice reducing the gravitational force which is what keeps the car on the road. e. [All of the above.]A motorcyclist performs uniform circular motion on a globe of death with a radius of 4.00 m. It has a module speed of 10.9 m/s. The motorcycle and motorcyclist assembly has a mass of 200.0 kg. Consider g=10.0 m/s2. How much work (in joules) does the centripetal force do when the motorcyclist makes one complete turn of the globe? a) 1370 b) 6850 c) 3420 e) 0 f) 1710 g) 685 h) 342 i) 428
- 4. An object of mass m makes a loop-the-loop as shown. When it is upside down at point A, the normal force is found to be 2mg. a) What is the speed of the object at point A in terms of g and R? b) What is the normal force at point B, neglecting any friction of air resistance? Put your answer in terms of m and g. A BA particle of mass m moves in the XY-plane, and its position vector is given by = a cos wtî + b sin wtĵ where a, b, and w are positive constants, and a > b. Show that a. The particle moves in an ellipse. b. The force acting on the particle is always directed toward the origin. c. The total work done by the force in moving the particle once around the ellipse is zero d. The force is conservative.A frictionless block of mass 0.5 kg slides down a ramp of height 0.8 m and onto a horizontal frictionless table. A circular frictionless wall forces the block to move in a circular path. Using gravity as 10m/s^2, calculate the force at point A. If the radius is 0.5 meters. Smooth wall A Smooth Ramp Side View Top View 2 N 4 N 6 N 10N 12 N 14 N 16 N Other:
- Modern roller coasters have vertical loops like the one shown in the figure below. The radius of curvature is smaller at the top than on the sides so that the downward centripetal acceleration at the top will be greater than the acceleration due to gravity, keeping the passengers pressed firmly into their seats. D B minimum Imaximum C A What is the speed, in m/s, of the roller coaster at the top of the loop if the radius of curvature there is 16.0 m and the downward acceleration of the car is 1.50 g? 24.5 What is the relationship between centripetal acceleration and tangential speed? m/sModern roller coasters have vertical loops like the one shown in the figure. Frinimum B C masimum A The radius of curvature is smaller at the top than on the sides so that the downward centripetal acceleration at the top will be greater than the acceleration due to gravity, keeping the passengers pressed firmly into their seats. What is the speed of the roller coaster at the top of the loop (in m/s) if the radius of curvature there is 17.0 m and the downward acceleration of the car is 1.50 g? m/sModern roller coasters have vertical loops like the one shown in the figure. minimum B macimum A The radius of curvature is smaller at the top than on the sides so that the downward centripetal acceleration at the top will be greater than the acceleration due to gravity, keeping the passengers pressed firmly into their seats. What is the speed of the roller coaster at the top of the loop (in m/s) if the radius of curvature there is 17.0 m and the downward acceleration of the car is 1.50 g? 15.00 x m/s
- A small box of mass m is given a speed of v = cylinder shown in (Figure 1). Figure A 3 CTC gr at the top of the smooth half 1 of 1 Part A Determine the angle at which the box leaves the surface. Express your answer in degrees using three significant figures. 0 = Submit VO Provide Feedback ΑΣΦ Request Answer vec ? Review Next >QUESTION 1 A boy takes a 2.0-kg rock and ties it to the end of a light, uniform, 0.80-m-long rope. He then grabs the other end of the rope and swings the rock in a vertical circle. If he imparts a tension of 20 N to the rope as he swings the rock over the top of the circular motion, what will be the speed of the rock at the very top of the motion? Assume that g = 9.8 m/s2. а. 2.0 m/s b. 6.0 m/s C. 5.0 m/s d. 4.0 m/s е. 3.0 m/s1.1 A thin uniform circular disk of radius a, mass m and A mass per unit length exerts gravitational force on a particle of mass M at distance b from the center of the ring, see figure below. Find the gravitational force that the disk exerts on the particle. AZ M Note! Disk is in the XY-plane and D is along the Z-axis b 1.2 Given that A = 5.0 kgm', a = 0.5 cm and d 150 cm. Determine the gravitational force that the disk exerts on a particle of mass M = 1000 g.