HBrBr2CH2Cl2H,BrElectrophilic addition of bromine, Brɔ, to alkenes yields a 1,2-dibromoalkane. The reaction proceeds through a cyclic intermediate known as a bromonium ion. The reaction occurs in ananhydrous solvent such as CH2Clɔ.In the second step of the reaction, bromide is the nucleophile and attacks at one of the carbons of the bromonium ion to yield the product. Due to steric clashes, the bromide ion always attacksthe carbon from the opposite face of the bromonium ion so that a product with anti stereochemistry is formed.Draw curved arrows to show the movement of electrons in this step of the mechanism.Arrow-pushing InstructionsHBrH-BrH.:Br:ProvioucNoxt

When alkene is treated with Br2,then first form cyclic brominium ion as intermediate and then form…

Answered: Br Br2 CH2CI2 H' H. Br H Electrophilic…

Organic Chemistry

9th Edition

ISBN:9781305080485

Author:John E. McMurry

Publisher:John E. McMurry

Chapter19: Aldehydes And Ketones: Nucleophilic Addition Reactions

Section19.SE: Something Extra

Problem 28VC

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When propene reacts with gaseous hydrogen bromide, HBr, two products, 1-bromopropane and 2-bromopropane are formed. The reaction is a two-step process in which the electrophilic attack occurs in the first step. Identify the electrophile in this reaction Draw a diagram showing the first step of the reaction that leads to the production of 2-bromopropane.
Br Brz CH3 CH3 H3C CH2CI2 H3C Br Electrophilic addition of bromine, Br2; to alkenes yields a 1,2-dibromoalkane. The reaction proceeds through a cyclic intermediate known as a bromonium ion. The reaction occurs in an anhydrous solvent such as CH,Cl). In the second step of the reaction, bromide is the nucleophile and attacks at one of the carbons of the bromonium ion to yield the product. Due to steric clashes, the bromide ion always attacks the carbon from the opposite face of the bromonium ion so that a product with anti stereochemistry is formed. Draw curved arrows to show the movement of electrons in this step of the mechanism. Arrow-pushing Instructions Br: :Br: .CH3 H3C H3C CH3 Br:
An electron-deficient carbon atom reacts with a nucleophile, symbolized as: Nu−. Define this ?
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What explains why many aldehydes and ketones can undergo self-condensation reactions in basic conditions? The alpha carbon can lose a proton and act like a nucleophile and the carbonyl carbon is an electrophile. The alpha carbon can gain a proton and act like an electrophile and the carbonyl carbon is a nucleophile. The oxygen of the carbonyl group can attack the carbon of the carbonyl group. Only esters can undergo self-condensation reactions.
CCH H20, H2SO4 H9SO4 CH3 Alkynes do not react directly with aqueous acid as do alkenes, but will do so in the presence of mercury(II) sulfate as a Lewis acid catalyst. The reaction occurs with Markovnikov regiochemistry, so the OH group adds to the more highly substituted carbon and the H adds to the less highly substituted carbon. The initial product of the reaction is a vinyl alcohol, also called an enol. The enol immediately rearranges to a more stable ketone via tautomerization. Draw curved arrows to show the movement of electrons in this step of the mechanism. Arrow-pushing Instructions Hjö: -CH3 -CH3 H3O*
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Hydration of aldehydes and ketones can be catalyzed by acid or base. Bases catalyze hydration by: protonating the carbonyl oxygen making the carbonyl group more electrophilic employing hydroxide ion, which is a better nucleophile than water making the carbonyl group less electrophilic shifting the equilibrium position of the reaction to favor products

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