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Calculate the binding energy per nucleon for the 26 Fe nucleus. (Atomic masses: iron-56 = 55.9349 amu; hydrogen-1 = 1.0078 amu; mass of neutron = 1.0087 amu) HOW DO WE GET THERE? We must first calculate the mass defect (Am) for 56Fe. Since atomic masses (which include the electrons) are given, we must decide how to account for the electron mass: 55.9349 = mass of Fe atom = mass of nucleus + 26 me 1.0078 = mass of †H atom = mass of nucleus + me Thus, since a 56Fe nucleus is "synthesized" from 26 protons and 30 neutrons, we see that Am = (55.9349 - 26 me) - [26(1.0078 - me) + 30(1.0087)]. Solve for Am. Am = 56.4634 X amu

Calculate the binding energy per nucleon for the 26 Fe nucleus. (Atomic masses: iron-56 = 55.9349 amu; hydrogen-1 = 1.0078 amu; mass of neutron = 1.0087 amu) HOW DO WE GET THERE? We must first calculate the mass defect (Am) for 56Fe. Since atomic masses (which include the electrons) are given, we must decide how to account for the electron mass: 55.9349 = mass of Fe atom = mass of nucleus + 26 me 1.0078 = mass of †H atom = mass of nucleus + me Thus, since a 56Fe nucleus is "synthesized" from 26 protons and 30 neutrons, we see that Am = (55.9349 - 26 me) - [26(1.0078 - me) + 30(1.0087)]. Solve for Am. Am = 56.4634 X amu

Chemistry
Chemistry
9th Edition
ISBN:9781133611097
Author:Steven S. Zumdahl
Publisher:Steven S. Zumdahl
Chapter19: The Nucleus: A Chemist's View
Section: Chapter Questions
Problem 7RQ
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INTERACTIVE EXAMPLE Nuclear Binding Energy II Calculate the binding energy per nucleon for the Fe nucleus. (Atomic masses: iron-56 = 55.9349 amu; hydrogen-1 = 1.0078 amu; mass of neutron = 1.0087 amu) HOW DO WE GET THERE? We must first calculate the mass defect (Am) for 56Fe. Since atomic masses (which include the electrons) are given, we must decide how to account for the electron mass: 55.9349 = mass of Fe atom = mass of nucleus + 26 me 1.0078 = mass of H atom = mass of nucleus + m. Thus, since a 56Fe nucleus is "synthesized" from 26 protons and 30 neutrons, we see that Am = (55.9349 - 26 m.) - [26(1.0078 - me) + 30(1.0087)]. Solve for Am. Am = 56.4634 amu
Transcribed Image Text:INTERACTIVE EXAMPLE Nuclear Binding Energy II Calculate the binding energy per nucleon for the Fe nucleus. (Atomic masses: iron-56 = 55.9349 amu; hydrogen-1 = 1.0078 amu; mass of neutron = 1.0087 amu) HOW DO WE GET THERE? We must first calculate the mass defect (Am) for 56Fe. Since atomic masses (which include the electrons) are given, we must decide how to account for the electron mass: 55.9349 = mass of Fe atom = mass of nucleus + 26 me 1.0078 = mass of H atom = mass of nucleus + m. Thus, since a 56Fe nucleus is "synthesized" from 26 protons and 30 neutrons, we see that Am = (55.9349 - 26 m.) - [26(1.0078 - me) + 30(1.0087)]. Solve for Am. Am = 56.4634 amu
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