etermine the maximum wu that the beam can carry based on the shear capacity of the beam
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The rectangular beam with a span length of 7.2 m has an effective depth, d = 430mm and a width of 250mm. It has 2-legged 10mmØ stirrups spaced at 130 mm on centers all throughout the beam length. Determine the maximum wu that the beam can carry based on the shear capacity of the beam. Use fc' = 21MPa and Grade 40 rebars
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- 2. The beam shown in Figure P5.8-3 is a W16 × 31 of A992 steel and has continuous lateral support. The two concentrated loads are service live loads. Neglect the weight of the beam and determine whether the beam is adequate for flexure and shear. a. Use LRFD. b. Use ASD.1%9. l. In. • f 10 Y:- quiz2.pdf > Quiz: Design the reinforcement steel that necessary for the shcar and torsion for the rectangular cantilever beam shown in figure. Use for stirrups (o12) and let f.=25 MPa, f-400 MPa, dead load (5 kN/m?) and live load (10 kN/m), take into account the self-weight of beam. All dimensions in (mm) 1000 800 3000 300 Cnand TEXTEDT IIQ2) The members of the truss structure shown below is plain concrete. The compressive strength of the concrete is 25 MPa. Compute the maximum load P that can be carried by the structure. (Cross section of each member of the truss is 200 x 200 mm and don't use material factors and do not consider slenderness) Comment on your results briefly. P A& 2m SC 2 m 1380 2m D
- The rectangular beam with a span length of 7.2 m has an effective depth, d = 430mm and a width of 250mm. It has 2-legged 10mmØ stirrups spaced at 130 mm on centers all throughout the beam length. Determine the maximum wu that the beam can carry based on the shear capacity of the beam. Use fc' = 21MPa and Grade 40 rebars. a. Adopt smaller of S' : S'1 = Avfy / (0.062b√f'c) S'2 = Avfy / (0.35b) b. S" = (0.062/0.33) / S'1 c. 1. if S > S' ; ØVn = Ø 0.5Vc 2. if S"<S<S' ; Smax = least of S' or d/2 or 600mm i. S> Smax ; ØVn = Ø 0.5Vc ii. S< Smax ; ØVn = Ø (Vc + ( Avfyd / S ) ) 3. if S < S" ; Smax = least of S' or d/4 or 300mm i. S> Smax ; Vs = 0.33√f'c bwd ØVn = Ø (Vc + 0.33√f'c bwd) ii. S< Smax ; ØVn = Ø (Vc + ( Avfyd / S ) ) Find: 1. Vc 2. s' and s'' 3. smax 4. ØVn 5. WuA cantilever beam AB of length L = 6.5 ft supportsa trapezoidal distributed load of peak intensity q,and minimum intensity q/2, that includes the weight ofthe beam (see figure). The beam is a steel W12 X14wide-flange shape (see Table F-1(a), Appendix F).Calculate the maximum permissible load q basedupon (a) an allowable bending stress σallow =18 ksiand (b) an allowable shear stress τallow = 7.5 ksi.Note: Obtain the moment of inertia and section modulusof the beam from Table F-1(a).3-3 A rectangular section with width b=200mm and depth h=450mm is reinforced with 4 16 of HRB400. The design bending moment is M-100kN m. Is the section safe enoitesu or not? oro 500
- 4 - For the beam loading configuration and cross-section shown below, what is the maximum allowable load P given that the maximum allowable stress (in tension and compression) is 120 MPa? PO Р 1.6m PN ż 0.8m 0.8m P80 1.6m Р 30 30 T 10 dimensions in mm beam cross-section (same as problem 3, but inverted)b) This is a concrete frame (the interior lines represent reinforcing bars), If P is dead load, draw the BMD and the SFD as a result of ULTIMATE LOAD. 6.0 ft. P= 1.0 Kip Own weight of the beam = 1.0 kip/ft. (Uniform dead load)SITUATION 1 Determine (approximately) the force in each member of the truss. Assume the diagonals can support either a tensile or a compressíve force and assuming that the díagonals cannot support a compressíve force. A. Use Method 2 7 k 14 k 14 k 7 k Н F E oo 2 k 380 6 ft A D В C 8 ft 8 ft 8 ft B. Use Method 1 50 kN 40 kN 20 kN E D 3 m B 3 m 3 m
- A simply supported beam is subjected to a uniform service dead load of 15kN/m(including the weight of the beam), a uniform service live load of 30kN/m. the beam is 12 meters long and is laterally supported at the midspan, and A572 Gr.50 steel is used. Is W30x108 adequate? Assume Cb=1 by 4 d fore k h h Z S Ly 267 TH mm 19.3 757 13.8 min m 35.8 685.4 54.6 737.7 5670 x10^3 4900 x103 mm 60.8 x10 6 mm 2080 x10 3 8300 x10^9 mm wwwThe beam cross-section shown is design to resist a nominal moment M₁ of 320 kN m, if f = 35 MPa and fy = 420 MPa, determine the required area of steel reinforcement Ag. 75,75,75 As 225- 75 565 60 700mm 0.85f I N2 0.85f d 1-17/22 T₁ T = T₁+T₂ d C₂ a-75 I a-75 2 T₂5. The beam-column has a height of 7.5m and is a member of a braced frame. It is subjected to an axial load of DL-65KN and LL= 1OOKN. It is pinned at both ends. A W12X35 section was used and was made up of A-36 steel with Fy-250MPA. Compute the interaction value for beam- column based on NSCP 2015 code provisions. Ngelect the weight of the section. A = 6645 mm2 Zx- 839x10^3 mm3 d- 317.50mm Sx- 747x10^3 mm3 tw= 7.62 Rx= 133.35 bf= 166.62 ly= 10x10^6 mm4 tf- 13.21 Sy= 122x10^3 mm3 Ix= 119x10^6 mm4 Ry3 39.12mm 3.5 Note: Use C=D1.00%--0.2