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- The motion of a point on the circumference of a rolling wheel of radius 3 feet is described by the vector function 7(t) = 3(10t – sin(10t))ỉ + 3(1 – cos(104))} Find the velocity vector of the point. v(t) = Find the acceleration vector of the point. a(t) Find the speed of the point. s(t) =The motion of a point on the circumference of a rolling wheel of radius 5 feet is described by the vector function F(t) = 5(12t - sin(12t))? +5(1 cos(12t))) Find the velocity vector of the point. (t) = 60(1- cos (12t)i + sin(12t)j) × Find the acceleration vector of the point. ä(t) = 720(sin(12t)i + cos (12t)j) ✓ Find the speed of the point. s(t) = 120 sin (6t) (Write i, j, k for 2,5, k.) Submit QuestionThe motion of a point on the circumference of a rolling wheel of radius 2 feet is described by the vector function r(t) = 2(23t sin (23t))i + 2(1 - cos(23t))j - Find the velocity vector of the point. v(t) = Find the acceleration vector of the point. a(t) = Find the speed of the point. s(t) =
- Find the directional derivative of g(a, b) = cos(3a + 4b) at the π point ( along the direction of the vector (-4,-3)The motion of a point on the circumference of a rolling wheel of radius 3 feet is described by the vector function 7(t) = 3(22t – sin(22t))i + 3(1 – cos(22t))} Find the velocity vector of the point. v(t) = (66 – 66 cos(22t) )i + 66 sin( 22t)jv Find the acceleration vector of the point. a(t) = Find the speed of the point. s(t) = 66y cos( 22t) + sin( 22t) xThe motion of a point on the circumference of a rolling wheel of radius 5 feet is described by the vector function F(t) = 5(24t - sin(24t))i +5(1 - cos(24t))j Find the velocity vector of the point. v(t) Find the acceleration vector of the point. ä(t) 2880 sin (24t)i + 2880 cos (24t)j✔ CABAME 120(1- cos (24t) )i + 120 sin (24t)j✔ Find the speed of the point. s(t) 240 sin (12t) wwwww Submit Question X Q Search EO H
- The equation r(t)= |- (21-16²) Ji jis the position of a particle in space at time t. Find the angle between the velocity and acceleration vectors at time t=0.The motion of a point on the circumference of a rolling wheel of radius 3 feet is described by the vector function 7(t) = 3(26t – sin(26t))i + 3(1 – cos(26t))} Find the velocity vector of the point. (?)a Find the acceleration vector of the point. d(t) Find the speed of the point. s(t)The motion of a point on the circumference of a rolling wheel of radius 5 feet is described by the vector function r(t) = 5(11t sin(11t))i +5(1 − cos(11t))] Find the velocity vector of the point. v(t) Find the acceleration vector of the point. ä(t) = Find the speed of the point. s(t) =
- The equation r(t) = (3 sin t) i + (2 cos t)j + (3t) k is the position of a particle in space at time t. Find the particle's velocity and acceleration vectors. Then write the particle's velocity at t= 2 as a product of its speed and direction.The motion of a point on the circumference of a rolling wheel of radius 4 feet is described by the vector function F(t) = 4(26t – sin(26t))i + 4(1 – cos(26t))3 Find the velocity vector of the point. ü(t) = | 4(26 – 26 cos(26t))i + 4(26 sin( 26t ))j Find the acceleration vector of the point. ä(t) = | 2704 sin(26t )i + 2704 cos( 26t)j v| Find the speed of the point. s(t) = 2704 sin(26t)i+ 2704 cos( 26t)j x syntax error. Check your variables - you might be using an incorrect one.Q2:- A/ Given a position vector: R (t)= 3 cos tỉ+ 3 sin tj+ t2 k find 1- The velocity vector and acceleration vector at any time(t)? 2- Magnitudes of velocity and acceleration at time (t= 1)?