The fork lift has a weight of 2400 lb and a center of gravityat G (Figure 1).Figure2.5 ft1.25 ft-3.50 ft-< 1 of 1XIXIXPart AIf the rear wheels are powered, whereas the front wheels are free to roll, determine the maximum number of 300-1b crates the fork lift can pushforward. The coefficient of static friction between the wheels and the ground is μs = 0.4, and between each crate and the ground μ's = 0.35.Express your answer as an integer.n =SubmitProvide FeedbackΑΣΦRequest Answervecwwwww.11?Next >

Answered: Image /qna-images/answer/39c30d2d-d3ae-4683-b60b-3dbb0ec24a79.jpg

The fork lift has a weight of 2400 lb and a center of gravity at G (Figure 1). Figure 2.5 ft 1.25 ft 3.50 ft- < 1 of 1 > Part A If the rear wheels are powered, whereas the front wheels are free to roll, determine the maximum number of 300-lb crates the fork lift can push forward. The coefficient of static friction between the wheels and the ground is μ =0.4, and between each crate and the ground = 0.35. Express your answer as an integer. n = Submit Provide Feedback AΣ Ivec Request Answer ? Next >

The fork lift has a weight of 2400 lb and a center of gravity at G (Figure 1). Figure 2.5 ft 1.25 ft 3.50 ft- < 1 of 1 > Part A If the rear wheels are powered, whereas the front wheels are free to roll, determine the maximum number of 300-lb crates the fork lift can push forward. The coefficient of static friction between the wheels and the ground is μ =0.4, and between each crate and the ground = 0.35. Express your answer as an integer. n = Submit Provide Feedback AΣ Ivec Request Answer ? Next >

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

G, Problem 2 Given: (0.75 m 10.4 m Mass of car: 1400 kg D 800 kg 2 m +1.5 m- -2 m- -1.25 m Mass of trailer: Braking force at C (uc= 0.40) is applied and causes skid. PIN G, 0.75 m 0.4 m FREE TO ROLL ·FREE TO ROLL H m-- -2 m- + 1.5 m-- 2 m 1.25 m Determine the reactions at B, C, and D. Note: Pin supports can resist both vertical and horizontal forces.
A W530x92 supports a uniformly distributed load of 12 kN/m (including the weight of the beam) and equal concentrated load P at quarter points (L/4, L/2, and 3L/4). The compression flange is laterally supported at quarter points and at the ends. The beam is 12m simply supported. Using A36 steel, the beam has the following properties: d = 533 mm bf = 209 mm tf = 15.6 mm tw = 10.2 mm k = 32 mm ry = 44.9 mm Sx = 2070 x 10^3 mm^3 Zx = 2360 x 10^3 mm^3 Es = 200,000 MPa Ix = 552 x 10^6 MPa Find the maximum allowable load P so that it will not exceed its maximum allowable moment capacity. Use conservative assumption for Cb.
Asap
Find the maximum point live load (P) can be loaded on the end of the cantilever beam shown below. If f'c-20 Mpa, fy-300 Mpa, and the uniform live load equal to (10 kN/m), the dead load is the self-weight of the beam. W =10kN/m 4m PL=7 H 70mm 530mm 4025 ..... 270mm
Description Road at span B-D-F-H-J I'm Traffic moves to the left only. Determine: MANI વાઆડકી ગા POL-200kN@ Joint H P₁ = 150KN WOL= 201(last digit of your SN) kN/m W₁ = 36+ (last digit of your SN) kN/m 4m 3m •Maximum axial force at member FH • Maximum axial force at member CF Maximum axial force at member EG 6
Q3/ A rigid beam ABCD shown in Figure with negligible weight is pinned at one end and attached to two vertical rods. If the beam is subjected to load of P=60 kN. Find the vertical movement at D. Aluminum A- s mm Steel E- 68000 MP L-2 A-300 E- 200000 MPa D 60 KN | Im Im IIm
A W530x92 supports a uniformly distributed load of 12 kN/m (including the weight of the beam) and equal concentrated load P at quarter points (L/4, L/2, and 3L/4). The compression flange is laterally supported at quarter points and at the ends. The beam is 12m simply supported. Using A36 steel, the beam has the following properties: d = 533 mm %3D bf = 209 mm %3D tf = 15.6 mm tw 10.2 mm %3D k = 32 mm ry = 44.9 mm %3D Sx = 2070 x 10^3 mm^3 Zx = 2360 x 10^3 mm^3 Es = 200,000 MPa %3D \x 3 552 х 10^6 MРа Find the maximum allowable load P so that it will not exceed its maximum allowable moment capacity. Use conservative assumption for Cb. Consider all the necessary failure that could happen.
1. CALCLULATE THE FEM OF THE FOLLOWING USING THREE MOMENT EQUATION. B -L/2- -L/2-
Use THREE-MOMENT EQUATION in solving the given statically indeterminate beam. E and I are constant 100 kN w = 40kN/m A 5m Зт р 8m OB 10m 1. Consider A-B-C, what is the value of L1 6A,b2 ? 2. Consider the A-B-C, what is the value of L2 6Azb2 ? 3. Consider B-C-D, what is the value of L2 4. What is the bending moment that support A? 5. What is the bending moment that support B? 6. What is the bending moment that support C? 7. What is the vertical reaction at A? 8. What is the reaction at B? 9. What is the reaction at C? 10. What is the reaction at D? 11. Draw the shear diagram 12. Draw the moment diagram
The 71-lb crate slides down the curved path in the vertical plane. If the crate has a velocity of 7.7 ft/sec down the incline at.A and a velocity of 30.8 ft/sec at B, compute the work U; done on the crate by friction during the motion from A to B. 7.7 ft/sec 21' B 30.8 ft/sec 39' Answer: Uf = i ft-lb
A beam is simply supported and has a span of 12 m. The beam is a W33×240 with Ey=345 MPa. Compute the allowable (ASD) and ultimate (LRFD) uniformly distributed load that can be safely carried by the beam including its weight: A. If the compression flange is fully braced laterally. Express your answer in kN/m. (ASD) B. If the compression flange has lateral support only at its ends. Express your answer in kN/m. (ASD) C. If the compression flange is fully braced laterally. Express your answer in kN/m. (LRFD) D. If the compression flange has lateral support only at its ends. Express your answer in kN/m. (LRFD) Properties of W33×240: Weight = 3.51 kN/m tw = 21.08 mm x = 352.54 mm A = 45,548 mm? Ix = 5,660.75 × 10° mm* Ty = 92.34 mm d = 850.9 mm ly = 388.34 × 10® mm Jc = 14.51 x 10° mm* bị = 402.97 mm Sx = 13,322.68 × 10° mm3 ris = 105.92 mm t = 35.56 mm Sy = 1,933.67 x 10° mm3
4 -800mm- 2-20mm DIA A 3-32mm DIA od قت -300mm 4 D 90mm 450mm