What is the role of his119 in the RNase-catalyzed hydrolysis of RNA, as indicated in the Figure below? RNA 5' -O–CH2 O Base 4' H H His 119 3 OTH O–CH2 H H ΝΗ His 12 Base H O -0-P=0 H OH It acts as a general base, abstracting a proton from the 2' hydroxyl in order to increase its nucleophilicity. It forms an H-bond with his12 in order to stabilize the transition state. It serves as a general acid, donating a proton to improve the quality of the leaving group. It works through concerted general acid-base catalysis with his 12 in order to favour the products of the reaction. Two of the above are true.

Biochemistry
6th Edition
ISBN:9781305577206
Author:Reginald H. Garrett, Charles M. Grisham
Publisher:Reginald H. Garrett, Charles M. Grisham
Chapter26: Synthesis And Degradation Of Nucleotides
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Problem 6P: Allosteric Regulation of Ribonucleotide Reductase by ATP and Deoxynucleotides Describe the...
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What is the role of his119 in the RNase-catalyzed hydrolysis of RNA, as indicated in
the Figure below?
RNA
-0-CH₂ Q Base
His 119
H H
NH
His 12
-P-0-CH₂ a Base
H H
3'
H
O
2'
O-H
OH
O
-0-P=0
It acts as a general base, abstracting a proton from the 2' hydroxyl in order to
increase its nucleophilicity.
It forms an H-bond with his12 in order to stabilize the transition state.
It serves as a general acid, donating a proton to improve the quality of the
leaving group.
It works through concerted general acid-base catalysis with his 12 in order to
favour the products of the reaction.
Two of the above are true.
Transcribed Image Text:What is the role of his119 in the RNase-catalyzed hydrolysis of RNA, as indicated in the Figure below? RNA -0-CH₂ Q Base His 119 H H NH His 12 -P-0-CH₂ a Base H H 3' H O 2' O-H OH O -0-P=0 It acts as a general base, abstracting a proton from the 2' hydroxyl in order to increase its nucleophilicity. It forms an H-bond with his12 in order to stabilize the transition state. It serves as a general acid, donating a proton to improve the quality of the leaving group. It works through concerted general acid-base catalysis with his 12 in order to favour the products of the reaction. Two of the above are true.
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