Chemistry: Principles and Practice
3rd Edition
ISBN: 9780534420123
Author: Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher: Cengage Learning
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Textbook Question
Chapter 11, Problem 11.61QE
Arrange the following substances in order of increasing strength of crystal forces: CO2, KCl, H2O, N2, CaO.
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Calculate the lattice energy of ionic solid MX,
given the following thermodynamic data:
M(s) + X2(9) → MX(s) AHræn
M(s) → M(g) AHrän= 88. kJ
Bond energy of X2 = 196. kJ/mol
lonization energy for M(s) = 485. kJ /mol
Electron affinity of X = -281. kJ/mol
AHrxn = -616.
Enter your answer in decimal notation,
rounded to the appropriate number of
significant figures.
Consider the following chemical reaction between component A and B:
A(?) + 2B(g) → C(g)+ 3D(l) …..ΔH°r = −2253.2 kJ
i. State whether the reaction is exothermic or endothermic.
ii. Based on the value of heat of reaction, explain the chemical reaction above in terms of the energy associated with breaking or formation of molecular bonds.
iii. Consider a similar reaction of A and B as the one shown above. However, the reaction now generates D in vapor form instead of liquid. Explain how the heat of reaction value differs from the one shown above.
iv. If the above reaction occurs in an isothermal system where there is no work interaction and both kinetic and potential energy changes are too small such that they are negligible, write the energy balance for the system.
Calculate the lattice enthalpy for RbC1. You will need the following information:
Species AfH°, kJ/mol
Rb(g)
RbCl(s)
Cl(g)
80.9
- 435.4
121.3
Enthalpy of ionization for Rb(g) is 403.0 kJ/mol; electron attachment enthalpy for Cl(g) is −349.0 kJ/mol.
Lattice enthalpy =
kJ/mol
Chapter 11 Solutions
Chemistry: Principles and Practice
Ch. 11 - Prob. 11.1QECh. 11 - Prob. 11.2QECh. 11 - Prob. 11.3QECh. 11 - Prob. 11.4QECh. 11 - Prob. 11.5QECh. 11 - Why does a perspiring body achieve greater cooling...Ch. 11 - Prob. 11.7QECh. 11 - Prob. 11.8QECh. 11 - Prob. 11.9QECh. 11 - Prob. 11.10QE
Ch. 11 - Prob. 11.11QECh. 11 - Prob. 11.12QECh. 11 - Prob. 11.13QECh. 11 - Prob. 11.14QECh. 11 - Prob. 11.15QECh. 11 - Prob. 11.16QECh. 11 - Prob. 11.17QECh. 11 - Prob. 11.18QECh. 11 - Prob. 11.19QECh. 11 - Prob. 11.20QECh. 11 - The compounds ethanol (C2H5OH) and dimethyl ether...Ch. 11 - Prob. 11.22QECh. 11 - Prob. 11.23QECh. 11 - An amorphous solid can sometimes be converted to a...Ch. 11 - Prob. 11.25QECh. 11 - Prob. 11.26QECh. 11 - Prob. 11.27QECh. 11 - Prob. 11.28QECh. 11 - Prob. 11.29QECh. 11 - Prob. 11.30QECh. 11 - Prob. 11.31QECh. 11 - Prob. 11.32QECh. 11 - Prob. 11.33QECh. 11 - Prob. 11.34QECh. 11 - Prob. 11.35QECh. 11 - Prob. 11.36QECh. 11 - Prob. 11.37QECh. 11 - Prob. 11.38QECh. 11 - What is the enthalpy change when a 1.00-kg block...Ch. 11 - Prob. 11.40QECh. 11 - Prob. 11.41QECh. 11 - Prob. 11.42QECh. 11 - Prob. 11.43QECh. 11 - Prob. 11.44QECh. 11 - Prob. 11.45QECh. 11 - Prob. 11.46QECh. 11 - Prob. 11.47QECh. 11 - Prob. 11.48QECh. 11 - Identify the kinds of intermolecular forces...Ch. 11 - Prob. 11.50QECh. 11 - Prob. 11.51QECh. 11 - Prob. 11.52QECh. 11 - Prob. 11.53QECh. 11 - Prob. 11.54QECh. 11 - Prob. 11.55QECh. 11 - Prob. 11.56QECh. 11 - Prob. 11.57QECh. 11 - Prob. 11.58QECh. 11 - Prob. 11.59QECh. 11 - Identify the kinds of forces that are most...Ch. 11 - Arrange the following substances in order of...Ch. 11 - Arrange the following substances in order of...Ch. 11 - Prob. 11.63QECh. 11 - Silicon carbide, SiC, is a very hard, high-melting...Ch. 11 - Prob. 11.65QECh. 11 - Calcium oxide consists of a face-centered cubic...Ch. 11 - Prob. 11.67QECh. 11 - Prob. 11.68QECh. 11 - Prob. 11.69QECh. 11 - Prob. 11.70QECh. 11 - Prob. 11.71QECh. 11 - Prob. 11.72QECh. 11 - Prob. 11.73QECh. 11 - Prob. 11.74QECh. 11 - Lithium hydride (LiH) has the sodium chloride...Ch. 11 - Cesium iodide crystallizes as a simple cubic array...Ch. 11 - Palladium has a cubic crystal structure in which...Ch. 11 - Prob. 11.78QECh. 11 - Prob. 11.79QECh. 11 - Prob. 11.80QECh. 11 - Prob. 11.81QECh. 11 - Prob. 11.82QECh. 11 - Prob. 11.83QECh. 11 - Prob. 11.84QECh. 11 - Prob. 11.85QECh. 11 - The coordination number of uniformly sized spheres...Ch. 11 - Prob. 11.87QECh. 11 - Prob. 11.88QECh. 11 - Prob. 11.89QECh. 11 - Prob. 11.90QECh. 11 - Prob. 11.91QECh. 11 - Prob. 11.93QECh. 11 - Prob. 11.94QECh. 11 - A 1.50-g sample of methanol (CH3OH) is placed in...Ch. 11 - Prob. 11.96QECh. 11 - Prob. 11.97QECh. 11 - Prob. 11.98QECh. 11 - Prob. 11.99QECh. 11 - Prob. 11.100QECh. 11 - Prob. 11.103QE
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- Calculate the lattice enthalpies, ΔU (also called ΔHL), of the following group 1 fluoride compounds by using the Born–Mayer equation. The radius of Na is 102 pm and the radius of F– is 133 pm. The radius of Cs is 167 pm and the radius of F– is 133 pm.arrow_forwardMX(s) + crystal lattice energy → M*(g) + X(g) is the reaction for crystal lattice energy. True O Falsearrow_forward16). Using the thermochemical data below calculate the lattice energy for the formation of Na₂O. Na(s) → Na(g) 107.3 kJ/mol Na(g) → Na (g) + 1 e - 495.9 kJ/mol -418 kJ/mol 249.1 kJ/mol -141 kJ/mol -1484.5 kJ/mol 2 Na(s) + O₂(g) →→→ Na₂O(s) 1/2 O₂(g) → 0(g) O(g) + 1 e→O(g) O(g) +1e0²(g)arrow_forward
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