Show that for k = 0 : u = F ( ϕ , 0 ) = ϕ , sn u = sin u , cn u = cos u , dn u = 1 and for k = 1 : u = F ( ϕ , 1 ) = ln ( sec ϕ + tan ϕ ) or ϕ = gd u (Problem 19 ) , sn u = tanh u , cn u = dn u = sech u .
Show that for k = 0 : u = F ( ϕ , 0 ) = ϕ , sn u = sin u , cn u = cos u , dn u = 1 and for k = 1 : u = F ( ϕ , 1 ) = ln ( sec ϕ + tan ϕ ) or ϕ = gd u (Problem 19 ) , sn u = tanh u , cn u = dn u = sech u .
Show that for
k
=
0
:
u
=
F
(
ϕ
,
0
)
=
ϕ
,
sn
u
=
sin
u
,
cn
u
=
cos
u
,
dn
u
=
1
and for
k
=
1
:
u
=
F
(
ϕ
,
1
)
=
ln
(
sec
ϕ
+
tan
ϕ
)
or
ϕ
=
gd
u
(Problem
19
)
,
sn
u
=
tanh
u
,
cn
u
=
dn
u
=
sech
u
.
Calculus for Business, Economics, Life Sciences, and Social Sciences (14th Edition)
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