(a)
The number of times the Halley’s Comet reappeared in the sky since its early sighting.
(a)
Answer to Problem 41QP
The Halley’s Comet has reappeared for
Explanation of Solution
The Halley’s Comet was first observed in the sky in
Write the expression for the time elapsed since the first appearance of comet.
Here,
Write the expression for the number of reappearance of the Halley’s Comet.
Here,
Conclusion:
Substitute
Substitute
Thus, the Halley’s Comet has reappeared for
(b)
The mass lost by the comet since its first appearance in
(b)
Answer to Problem 41QP
The total mass lost by the comet since its early sighting is
Explanation of Solution
The every comet when comes near the sun, the comet action takes place and the body losses some of material as the action occurs.
The Halley’s Comet has appeared for
Write the expression for the mass lost by the comet during all its appearance.
Here,
Conclusion:
Substitute
Thus, the total mass lost by the comet since its early sighting is
(c)
The percentage of the comet’s total mass lost by the comet.
(c)
Answer to Problem 41QP
The mass lost by the Halley’s Comet is about
Explanation of Solution
Write the expression for the total mass of the comet at its first sight.
Here,
Write the expression for the percentage of mass of the comet as of its initial mass.
Here,
Conclusion:
Substitute
Substitute
Thus, the mass lost by the Halley’s Comet is about
Want to see more full solutions like this?
Chapter 12 Solutions
21st Century Astronomy
- Comet Halley has a semi-major axis of 17.7 AU. (The AU, or Astronomical Unit, is the distance from the Sun to the Earth. 1 AU = 1.50x1011 m.) The eccentricity of Comet Halley is 0.967. a. How far is Comet Halley from the sun at Aphelion, the farthest position from the sun? (Give your answer in AU.)? b. What is comet Halley's orbital time? (Give your answer in years.) Note: Using Kepler's third law in the form: P2 = a3 is convenient. This equation works for any object orbiting the sun when the orbital period is in years and the semi major axis is in AU. The reason this works is because this equation is normalized to earth. The AU and year are both 1 for Earth. c. In what year will Comet Halley start to move back toward the sun?arrow_forwardThe initial mass of a certain species of fish is 2 million tons. The mass of fish, if left alone, would increase at a rate proportional to the mass, with a proportionality constant of 5/yr. However, commercial fishing removes fish mass at a constant rate of 12 million tons per year. When will all the fish be gone? If the fishing rate is changed so that the mass of fish remains constant, what should that rate be? When will all the fish be gone? Inco The fish will all be gone in years. (Round to three decimal places as needed.)arrow_forwardWhat is the ratio of mass of Earth (5.972×10,-kg) to mass of moon (7.348×10,,kg) in scientific notation? I know the answer is 0.813x102 but I don't know how they got to that answer.arrow_forward
- To model a moon in the solar system, consider a sphere with radius R and uniform mass density p. Let gm = the acceleration due to gravity on the surface of the sphere. Calculate gm for these values of R and p: R = 2.0×106 m; p= 2.7x103 kg/m^3; (in m/s^2) OA: OB: 1.509 2.007 OC: 2.669 OD: 3.549 OE: OF: 4.721 6.279 OG: 8.351 OH: 1.111x101arrow_forwardFour astronauts are in a spherical space station. (a) If, as is typical, each of them breathes about 500 cm3 of air with each breath, approximately what volume of air (in cubic meters) do these astronauts breathe in a year? (b) What would the diameter (in meters) of the space station have to be to contain all this air?arrow_forwardIf the mass of Jupiter is defined as 1 MJ = 1.90 ✕ 1027 kg, what is the mass of Saturn (5.68 ✕ 1026 kg) in units of MJ? What is the mass of Venus (4.86 ✕ 1024 kg) in MJ? What is the mass of Earth (5.97 ✕ 1024 kg) in MJ?arrow_forward
- Comet Halley (Fig. P11.21) approaches the Sun to within 0.570 AU, and its orbital period is 75.6 yr. (AU is the symbol for astronomical unit, where 1 AU = 1.50 1011 m is the mean EarthSun distance.) How far from the Sun will Halleys comet travel before it starts its return journey?arrow_forwardSarah traveled 90 km at a certain speed. In going back, she increased her speed by 10 km/hr. If it took her a total of 10/3 hours, what was her original speed? Explain also. Create an expression to: Sarah traveled 90 km at a certain speed. Create another expression to: In going back, she increased her speed by 10 km/hr. Formula: v = d/tarrow_forwardWe have a very large sheet of extremely thin paper. Assume that the paper is in fact only 0.1mm (0.0039 inches) thick. Imagine that this paper will be folded in half repeatedly, 50 times. Guess how thick the paper will be at the end! Quick metric system converter: 10mm=1cm (about 0.39 inches) 100cm=1meter ( about 3.3 feet) 1000m=1kilometer (about 0.62miles)arrow_forward
- Two exoplanets, UCF1.01 and UCF1.02 are found revolving around the same star. The period of planet UCF1.01 is 92.4 days, and that of planet UCF1.02 is 7.1 days. If the average distance of UCF1.01 to the sun is 5,828.0 km, what is the average distance of UCF1.02 to the sun in km? Please keep four digits after decimal points.arrow_forwardCalculate how many seconds there are in 1.0 Mars year (678 Earth days). Report your answer in scientific notation with the correct number of significant digits.arrow_forwardThe moon has a mass of 7.34x10²² kg and a radius of 1.74x10⁶meters. If you have a mass of 66 kg, how strong is the force between you and the moon?arrow_forward
- Principles of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning