Physics
5th Edition
ISBN: 9781260486919
Author: GIAMBATTISTA
Publisher: MCG
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Chapter 14, Problem 77P
To determine
The surface area of the filament if the lamp delivers
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The filament of a light bulb has a temperature of 2580°C and radiates 60 W of power. The emissivity
of the filament is 0.36. What is the surface area of the filament? o = 5.67x10-8
O 0.44 cm²
0.62 cm²
O 0.74 cm²
O 0.91 cm²
O 0.144 cm²
W
m²K 4
The filament in a light bulb has a diameter of 0.02 mm and an emissivity of 1.0.
The temperature of the filament is 3×1000°C. What should be the length of the
filament in meters so it will radiate 60 W of power? The Stefan-Boltzmann
constant is 5.670 × 10-8 W/m2 · K4. Please give your answer with 3 decimal
places.
An incandescent lightbulb is an inexpensive but highly inefficient device that converts electrical energy into light. It converts about 10 percent of the electrical energy it consumes into light while converting the remaining 90 percent into heat. The glass bulb of the lamp heats up very quickly as a result of absorbing all that heat and dissipating it to the surroundings by convection and radiation. Consider an 8-cm-diameter 60-W lightbulb in a room at 25°C. The emissivity of the glass is 0.9. Assuming that 10 percent of the energy passes through the glass bulb as light with negligible absorption and the rest of the energy is absorbed and dissipated by the bulb itself by natural convection and radiation, determine the equilibrium temperature of the glass bulb. Assume the interior surfaces of the room to be at room temperature.
Chapter 14 Solutions
Physics
Ch. 14.1 - 14.1 On the Rebound
If a rubber ball of mass 1.0...Ch. 14.1 - Prob. 14.2PPCh. 14.2 - CHECKPOINT 14.2
Take a rubber band and stretch it...Ch. 14.2 - Prob. 14.3PPCh. 14.3 - Prob. 14.3CPCh. 14.3 - Prob. 14.4PPCh. 14.3 - Prob. 14.5PPCh. 14.4 - Prob. 14.6PPCh. 14.5 - Prob. 14.5CPCh. 14.5 - Prob. 14.7PP
Ch. 14.5 - Prob. 14.8PPCh. 14.5 - Prob. 14.9PPCh. 14.6 - Prob. 14.6CPCh. 14.6 - Prob. 14.10PPCh. 14.6 - Prob. 14.11PPCh. 14.8 - Prob. 14.12PPCh. 14.8 - Prob. 14.8CPCh. 14.8 - Prob. 14.13PPCh. 14.8 - Prob. 14.14PPCh. 14.8 - Prob. 14.15PPCh. 14 - Prob. 1CQCh. 14 - Prob. 2CQCh. 14 - 3. Why do lakes and rivers freeze first at their...Ch. 14 - Prob. 4CQCh. 14 - Prob. 5CQCh. 14 - Prob. 6CQCh. 14 - Prob. 7CQCh. 14 - Prob. 8CQCh. 14 - 9. What is the purpose of having fins on an...Ch. 14 - Prob. 10CQCh. 14 - Prob. 11CQCh. 14 - 12. Explain the theory behind the pressure cooker....Ch. 14 - Prob. 13CQCh. 14 - Prob. 14CQCh. 14 - Prob. 15CQCh. 14 - Prob. 16CQCh. 14 - Prob. 17CQCh. 14 - Prob. 18CQCh. 14 - Prob. 19CQCh. 14 - Prob. 20CQCh. 14 - Prob. 21CQCh. 14 - Prob. 22CQCh. 14 - Prob. 23CQCh. 14 - Prob. 24CQCh. 14 - Prob. 25CQCh. 14 - Prob. 26CQCh. 14 - 1. The main loss of heat from Earth is by
(a)...Ch. 14 - Prob. 2MCQCh. 14 - Prob. 3MCQCh. 14 - Prob. 4MCQCh. 14 - Prob. 5MCQCh. 14 - Prob. 6MCQCh. 14 - Prob. 7MCQCh. 14 - Prob. 8MCQCh. 14 - Prob. 9MCQCh. 14 - Prob. 10MCQCh. 14 - Prob. 11MCQCh. 14 - Prob. 12MCQCh. 14 - Prob. 1PCh. 14 - Prob. 2PCh. 14 - Prob. 3PCh. 14 - Prob. 4PCh. 14 - Prob. 5PCh. 14 - Prob. 6PCh. 14 - Prob. 7PCh. 14 - Prob. 8PCh. 14 - Prob. 9PCh. 14 - Prob. 10PCh. 14 - Prob. 11PCh. 14 - Prob. 12PCh. 14 - Prob. 13PCh. 14 - Prob. 14PCh. 14 - Prob. 15PCh. 14 - Prob. 16PCh. 14 - Prob. 17PCh. 14 - Prob. 18PCh. 14 - Prob. 19PCh. 14 - Prob. 20PCh. 14 - Prob. 21PCh. 14 - Prob. 22PCh. 14 - Prob. 23PCh. 14 - Prob. 24PCh. 14 - Prob. 25PCh. 14 - Prob. 26PCh. 14 - Prob. 27PCh. 14 - Prob. 28PCh. 14 - Prob. 29PCh. 14 - Prob. 30PCh. 14 - Prob. 31PCh. 14 - Prob. 32PCh. 14 - Prob. 33PCh. 14 - Prob. 34PCh. 14 - Prob. 35PCh. 14 - Prob. 36PCh. 14 - Prob. 37PCh. 14 - Prob. 38PCh. 14 - Prob. 39PCh. 14 - Prob. 40PCh. 14 - Prob. 41PCh. 14 - Prob. 42PCh. 14 - Prob. 43PCh. 14 - Prob. 44PCh. 14 - 45. Is it possible to heat the aluminum of Problem...Ch. 14 - Prob. 46PCh. 14 - Prob. 47PCh. 14 - Prob. 48PCh. 14 - Prob. 49PCh. 14 - Prob. 50PCh. 14 - Prob. 51PCh. 14 - Prob. 53PCh. 14 - Prob. 52PCh. 14 - Prob. 54PCh. 14 - Prob. 55PCh. 14 - Prob. 56PCh. 14 - Prob. 57PCh. 14 - Prob. 58PCh. 14 - Prob. 59PCh. 14 - Prob. 60PCh. 14 - Prob. 61PCh. 14 - Prob. 62PCh. 14 - Prob. 63PCh. 14 - Prob. 64PCh. 14 - Prob. 65PCh. 14 - Prob. 66PCh. 14 - 67. One cross-country skier is wearing a down...Ch. 14 - Prob. 68PCh. 14 - Prob. 69PCh. 14 - Prob. 70PCh. 14 - Prob. 71PCh. 14 - Prob. 72PCh. 14 - Prob. 73PCh. 14 - Prob. 74PCh. 14 - Prob. 75PCh. 14 - Prob. 76PCh. 14 - Prob. 77PCh. 14 - Prob. 78PCh. 14 - Prob. 79PCh. 14 - Prob. 80PCh. 14 - Prob. 81PCh. 14 - Prob. 82PCh. 14 - Prob. 83PCh. 14 - Prob. 84PCh. 14 - Prob. 85PCh. 14 - Prob. 86PCh. 14 - Prob. 87PCh. 14 - Prob. 88PCh. 14 - Prob. 89PCh. 14 - Prob. 93PCh. 14 - Prob. 91PCh. 14 - Prob. 92PCh. 14 - Prob. 94PCh. 14 - Prob. 95PCh. 14 - Prob. 96PCh. 14 - Prob. 97PCh. 14 - Prob. 98PCh. 14 - Prob. 99PCh. 14 - Prob. 100PCh. 14 - Prob. 101PCh. 14 - Prob. 102PCh. 14 - Prob. 103PCh. 14 - Prob. 104PCh. 14 - Prob. 105PCh. 14 - Prob. 106PCh. 14 - Prob. 107PCh. 14 - Prob. 108PCh. 14 - Prob. 109PCh. 14 - Prob. 110PCh. 14 - Prob. 112PCh. 14 - Prob. 111PCh. 14 - 116. It requires 17.10 kJ to melt 1.00 × 102 g of...Ch. 14 - Prob. 113PCh. 14 - Prob. 90PCh. 14 - Prob. 115PCh. 14 - Prob. 116PCh. 14 - Prob. 117PCh. 14 - Prob. 118PCh. 14 - Prob. 119PCh. 14 - Prob. 120P
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