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Evaluating a Line
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Chapter 15 Solutions
Calculus (MindTap Course List)
- Displacement d→1 is in the yz plane 62.8 o from the positive direction of the y axis, has a positive z component, and has a magnitude of 5.10 m. Displacement d→2 is in the xz plane 37.0 o from the positive direction of the x axis, has a positive z component, and has magnitude 0.900 m. What are (a) d→1⋅d→2 , (b) the x component of d→1×d→2 , (c) the y component of d→1×d→2 , (d) the z component of d→1×d→2 , and (e) the angle between d→1 and d→2 ?arrow_forward(5) Let ß be the vector-valued function 3u ß: (-2,2) × (0, 2π) → R³, B(U₁₂ v) = { 3u² 4 B (0,7), 0₁B (0,7), 0₂B (0,7) u cos(v) VI+ u², sin(v), (a) Sketch the image of ß (i.e. plot all values ß(u, v), for (u, v) in the domain of ß). (b) On the sketch in part (a), indicate (i) the path obtained by holding v = π/2 and varying u, and (ii) the path obtained by holding u = O and varying v. (c) Compute the following quantities: (d) Draw the following tangent vectors on your sketch in part (a): X₁ = 0₁B (0₂7) B(0)¹ X₂ = 0₂ß (0,7) p(0.4)* ' cos(v) √1+u² +arrow_forward(b) Consider the vector-valued function r(t) = t 2 i + (t − 3)j + tk. Write a vector-valued function s(t) that is the specified transformation of r. iii. a horizontal translation 5 units in the direction of the positive y-axisarrow_forward
- Application of Green's theorem Assume that u and u are continuously differentiable functions. Using Green's theorem, prove that JS D Ur Vy dA= u dv, where D is some domain enclosed by a simple closed curve C with positive orientation.arrow_forwardLet r (t) = The dot product r (1) · r' (1) =arrow_forwardConsider the vector-valued function r(t) = 3t2i + (t − 1)j + tk. Write a vector-valued function u(t) that is the specified transformation of r. A horizontal translation one unit in the direction of the positive x-axisarrow_forward
- Sketch the curve represented by the vector-valued function r(t) = 2 cos ti + tj + 2 sin tk and give the orientation of the curve.arrow_forwardEvaluating a Line Integral Using Green's Theorem In Exercise, use Green's Theorem to evaluate the line integral. √(√(x² - 1²) C: r = 1 + cos 8 (x² - y²) dx + 2xy dyarrow_forwardExercise 1: Show that the functions are orthogonal the indicated interval. a) f(x) = x, g(x)=x², x = [-2.2] c) f(x) = r, g(x) = cos 2r, x[-/2, π/2] b) f(x)=e¹, g(x) = re-e, r€ [0,2]arrow_forward
- The position vector r describes the path of an object moving in the xy-plane. Position Vector Point r(t) = 4 cos ti + 4 sin t (2V2,2V2) (a) Find the velocity vector v(t), speed s(t), and acceleration vector a(t) of the objeot. v(t) s(t) = a(t) = (b) Evaluate the velocity vector and acceleration vector of the object at the given point.arrow_forwardNonuniform straight-line motion Consider the motion of an object given by the position function r(t) = ƒ(t)⟨a, b, c⟩ + ⟨x0, y0, z0⟩, for t ≥ 0,where a, b, c, x0, y0, and z0 are constants, and ƒ is a differentiable scalar function, for t ≥ 0.a. Explain why r describes motion along a line.b. Find the velocity function. In general, is the velocity constant in magnitude or direction along the path?arrow_forwardEvaluate F · dr using the Fundamental Theorem of Line Integrals. Use a computer algebra system to verify your results. (2z + 4y) dx + (4x – 3z) dy + (2x – 3y) dz (a) C: line segment from (0, 0, 0) to (1, 1, 1) (b) C: line segment from (0, 0, 0) to (0, 0, 1) to (1, 1, 1) (c) C: line segment from (0, 0, 0) to (1, 0, 0) to (1, 1, 0) to (1, 1, 1)arrow_forward
- Algebra & Trigonometry with Analytic GeometryAlgebraISBN:9781133382119Author:SwokowskiPublisher:Cengage