Fundamentals of Geotechnical Engineering (MindTap Course List)
5th Edition
ISBN: 9781305635180
Author: Braja M. Das, Nagaratnam Sivakugan
Publisher: Cengage Learning
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Chapter 16, Problem 16.15P
To determine
Find the depth of the mat for a fully compensated foundation.
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For the rigid shallow foundation (2*4m)
shown in Fig, calculate Immediate
settlement the center of the foundation if
. (net pressure qo = 100 kPa. Assume 0.3
X
2 m
0.5 m
3.5 m
W.T
Q=2000 kN
6 m-3 m
y=22 kN/m²
Ce=0.805
C₁ = 0.3
e=0.753
OCR = 1.4
G. s
Dense Sand
Y = 22 kN/m³
Silty Clay
Silty Sand
Y = 18 kN/m²
Refer to Figure 5.2 and consider a rectangular foundation. Given: B = 1.5 m, L = 2.5 m, Df = 1.2 m, H = 0.9 m, Φ' = 40º, c' = 0, and γ = 17 kN/m3. Using a factor of safety of 3, determine the gross allowable load the foundation can carry. Use Eq. (5.3).
A continuous foundation, supported by sand, has a width of 2 m and the depth of foundation is 1.5m. The known soil characteristics are as follows: ϕ’ = 40°, c’ = 0, and γ = 16.5 kN/m³. If the loadeccentricity is 0.2 m, determine the ultimate load per unit length of the foundation.(Ans: ???? =5,260??)
Chapter 16 Solutions
Fundamentals of Geotechnical Engineering (MindTap Course List)
Ch. 16 - Prob. 16.1PCh. 16 - A 2.0 m wide continuous foundation carries a wall...Ch. 16 - Determine the maximum column load that can be...Ch. 16 - A 2.0 m wide strip foundation is placed in sand at...Ch. 16 - A square column foundation has to carry a gross...Ch. 16 - The applied load on a shallow square foundation...Ch. 16 - A column foundation (Figure 16.23) is 3 m 2 m in...Ch. 16 - Prob. 16.8PCh. 16 - A 2 m 3 m spread foundation placed at a depth of...Ch. 16 - An eccentrically loaded foundation is shown in...
Ch. 16 - For an eccentrically loaded continuous foundation...Ch. 16 - The shallow foundation shown in Figure 16.12...Ch. 16 - A mat foundation measuring 14 m 9 m has to be...Ch. 16 - Repeat Problem 16.13 with the following: Mat...Ch. 16 - Prob. 16.15PCh. 16 - For the mat in Problem 16.15, what will be the...Ch. 16 - Prob. 16.17CTPCh. 16 - Prob. 16.18CTPCh. 16 - A 2.0 m 2.0 m square pad footing will be placed...
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- A 8 m layer of sand, of saturated unit weight 22 kN/m3, overlies a 6 m layer of clay, of saturated unit weight 27 kN/m3. A foundation carrying 1200 KN load is to be founded on the soil layer. If the clay is normally consolidated and the increase in effective pressure due to the foundation load at the center of clay is 27 kN/m2, Soil parameters are Cc = 0.25, eo = 1.0. Assume required data •Draw the soil profile diagram in detail, mentioning all the soil properties with the foundation details. •Calculate the consolidation settlement at the center of the clay layer.arrow_forwardH.Q 1 Consider a rectangular foundation. Given: B = 1.5 m, L = 2.5 m, Df= 1.2 m, H =0.9 m, o' = 40°, c' = 0, and y= 17 kN/m3. Using a factor of safety of 3, determine the gross allowable load the foundation can carry. Use Meyerhof equation.arrow_forwardA rectangular foundation 3.0 × 1.50m carries a uniform load of 40 kN/m². Determine the vertical stress at P which is 3m below the ground surface. Use equivalent point load method. um 3m 0.5m 0.5m 3m Im (1) (2) VEN SETENGG Im- (3) Liebarrow_forward
- Please solve this question. Q. No. 1: A foundation 4x4 m is located at a depth of 1 m in a layer of saturated clay 13 m thick. Characteristic Parameters for the clay are cu=100 kN/m2, u=0, c'=0, '=32o, Cc=0.36, eo=0.784, NCC, sat=21 kN/m3. Determine the design load of the foundation to ensure (a) a factor of safety with respect to shear failure of 3 using the traditional method, (b) consolidation settlement does not exceed 30 mm.arrow_forward10. A flexible foundation is subjected to a uniformly distributed load of q-500 kN/m². Table 3 could be useful. Determine the increase in vertical stress, in kPa, Aoz at a depth of z=3m under point F. B 4m 3m 6m E 10m Table 10.3 Variation of I, with m and n m 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 1.0 0.1 0.0047 0.0092 0.0270 0.0279 0.2 0.0132 0.0092 0.0179 0.0259 0.0132 0.0259 0.0374 0.0222 0.0242 0.0435 0.0474 0.0629 0.0686 0.0258 0.0504 0.0528 0.0547 0.3 0.0731 0.0766 0.0794 0.4 0.1013 0.5 0.0198 0.0387 0.1202 0.6 0.0222 0.0435 0.7 0.0242 0.0474 0.0947 0.1069 0.1168 0.1247 0.1311 0.1361 0.1365 0.1436 0.1491 0.1537 0.1598 0.0168 0.0198 0.0328 0.0387 0.0474 0.0559 0.0168 0.0328 0.0474 0.0602 0.0711 0.0801 0.0873 0.0931 0.0977 0.0559 0.0711 0.0840 0.0947 0.1034 0.1104 0.1158 0.0629 0.0801 0.0686 0.0873 0.1034 0.8 0.0258 0.0504 0.0731 0.0931 0.1104 0.9 0.0270 0.0528 0.0766 0.0977 0.1158 0.0794 0.1013 0.1202 0.0832 0.1263 1.4 0.1300 1.6 0.0306 0.0599 0.0871 0.1114 0.1324 1.8 0.0309 0.0606…arrow_forwardPROBLEMS 8.1 Refer to Figure 8.3. For a flexible load area, given: B= 3 m, L=4.6m, q= 180KN/m², D; =2m, H = 00, v= 0.3, and E = 8500KN/m³. Estimate the elastic settlement at the center of the loaded area. Use Eq. (8.14). %3D Foundation B×L Rigid :foundation Flexible foundation H settlement settlement v = Poisson's ratio E = Modulus of elasticity Soil Rock Figure 8.3 Elastic settlement of flexible and rigid foundations. (8.14)arrow_forward
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- A bldg. has an L-shape as shown in the plan. The load exerted by the structure is 68 kPa. Compute the total vertical stress in kPa due to the structure load at a depth of 4.5 m. below the interior corner A of the L. shaped bldg. Assume that the foundation is under the entire bldg. Unit weight of soil is 17.50 kN/m.arrow_forwardA column foundation (Figure P3.5) is 3 m x 2 m in plan. Given: D; = 2 m, o' = 25°, c' = 50 kN/m². Using Eq. (3.23) and FS = 4, determine the net allowable load [see Eq. (3.15)] the foundation could carry. Use bearing capac- ity, shape, and depth factors given in Şection 3.6.arrow_forward9.6 A mat foundation is shown in Figure P9.6. The design considerations are L = 12 m, B = 10 m, D = 2.2 m, Q = 30 MN, x₁ = 2 m, x₂ = 2 m, x3 = 5.2 m, and precon solidation pressure o 105 kN/m². Calculate the conso dation settlement under the center of the mat. D₁ X3 Figure P9.6 Size of mat = B x L Vo Clay Ysat = 17.5 kN/m³ €= 0.88 C=0.38 C₁ = 0.1 Sand y= 16.0 kN/m³ Water table Sand Ysat = 18.0 kN/m³arrow_forward
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