Explanation Given: Use the inverse in exercise 9,that is G − 1 ( x , y ) = ( 3 x − y , − 5 x + 2 y ) Calculation: Since ( x , y ) = ( 2 , 1 ) . Therefore x = 2 and y = 1 Now, G − 1 ( 2 , 1 ) = ( 3 × 2 − 1 , − 5 × 2 + 2 × 1 ) G − 1 ( 2 , 1 ) = ( 6 − 1 , − 10 + 2 ) G − 1 ( 2 , 1 ) = ( 5 , − 8 ) Hence, The point is ( 5 , − 8 ) in the u v - plane which maps to ( 2 , 1 ) in the x y -plane. (b) Given: Use the inverse in exercise 9,that is G − 1 ( x , y ) = ( 3 x − y , − 5 x + 2 y ) Calculation: Since ( x , y ) = ( − 2 , 1 ) and ( 3 , 4 ) ...

4th Edition

ISBN: 9781319050733

Author: Rogawski

Publisher: MAC HIGHER

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Question

Chapter 16.6, Problem 10E

To determine

To find:

Use the inverse in exercise 9 to find

(a)A point in the $u v$ plane mapping to $(2, 1)$ .

(b)a segment in the $u v$ plane to the segment joining $(- 2, 1) and (3, 4)$ .

Expert Solution & Answer

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Chapter 16.6, Problem 9E

Chapter 16.6, Problem 11E

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Chapter 16 Solutions

CALCULUS (CLOTH)

Ch. 16.1 - Prob. 1PQ Ch. 16.1 - Prob. 2PQ Ch. 16.1 - Prob. 3PQ Ch. 16.1 - Prob. 4PQ Ch. 16.1 - Prob. 5PQ Ch. 16.1 - Prob. 6PQ Ch. 16.1 - Prob. 1E Ch. 16.1 - Prob. 2E Ch. 16.1 - Prob. 3E Ch. 16.1 - Prob. 4E

Ch. 16.1 - Prob. 5E Ch. 16.1 - Prob. 6E Ch. 16.1 - Prob. 7E Ch. 16.1 - Prob. 8E Ch. 16.1 - Prob. 9E Ch. 16.1 - Prob. 10E Ch. 16.1 - Prob. 11E Ch. 16.1 - Prob. 12E Ch. 16.1 - Prob. 13E Ch. 16.1 - Prob. 14E Ch. 16.1 - Prob. 15E Ch. 16.1 - Prob. 16E Ch. 16.1 - Prob. 17E Ch. 16.1 - Prob. 18E Ch. 16.1 - Prob. 19E Ch. 16.1 - Prob. 20E Ch. 16.1 - Prob. 21E Ch. 16.1 - Prob. 22E Ch. 16.1 - Prob. 23E Ch. 16.1 - Prob. 24E Ch. 16.1 - Prob. 25E Ch. 16.1 - Prob. 26E Ch. 16.1 - Prob. 27E Ch. 16.1 - Prob. 28E Ch. 16.1 - Prob. 29E Ch. 16.1 - Prob. 30E Ch. 16.1 - Prob. 31E Ch. 16.1 - Prob. 32E Ch. 16.1 - Prob. 33E Ch. 16.1 - Prob. 34E Ch. 16.1 - Prob. 35E Ch. 16.1 - Prob. 36E Ch. 16.1 - Prob. 37E Ch. 16.1 - Prob. 38E Ch. 16.1 - Prob. 39E Ch. 16.1 - Prob. 40E Ch. 16.1 - Prob. 41E Ch. 16.1 - Prob. 42E Ch. 16.1 - Prob. 43E Ch. 16.1 - Prob. 44E Ch. 16.1 - Prob. 45E Ch. 16.1 - Prob. 46E Ch. 16.1 - Prob. 47E Ch. 16.1 - Prob. 48E Ch. 16.1 - Prob. 49E Ch. 16.1 - Prob. 50E Ch. 16.1 - Prob. 51E Ch. 16.1 - Prob. 52E Ch. 16.1 - 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Prob. 2E Ch. 16.5 - Prob. 3E Ch. 16.5 - Prob. 4E Ch. 16.5 - Prob. 5E Ch. 16.5 - Prob. 6E Ch. 16.5 - Prob. 7E Ch. 16.5 - Prob. 8E Ch. 16.5 - Prob. 9E Ch. 16.5 - Prob. 10E Ch. 16.5 - Prob. 11E Ch. 16.5 - Prob. 12E Ch. 16.5 - Prob. 13E Ch. 16.5 - Prob. 14E Ch. 16.5 - Prob. 15E Ch. 16.5 - Prob. 16E Ch. 16.5 - Prob. 17E Ch. 16.5 - Prob. 18E Ch. 16.5 - Prob. 19E Ch. 16.5 - Prob. 20E Ch. 16.5 - Prob. 21E Ch. 16.5 - Prob. 22E Ch. 16.5 - Prob. 23E Ch. 16.5 - Prob. 24E Ch. 16.5 - Prob. 25E Ch. 16.5 - Prob. 26E Ch. 16.5 - Prob. 27E Ch. 16.5 - Prob. 28E Ch. 16.5 - Prob. 29E Ch. 16.5 - Prob. 30E Ch. 16.5 - Prob. 31E Ch. 16.5 - Prob. 32E Ch. 16.5 - Prob. 33E Ch. 16.5 - Prob. 34E Ch. 16.5 - Prob. 35E Ch. 16.5 - Prob. 36E Ch. 16.5 - Prob. 37E Ch. 16.5 - Prob. 38E Ch. 16.5 - Prob. 39E Ch. 16.5 - Prob. 40E Ch. 16.5 - Prob. 41E Ch. 16.5 - Prob. 42E Ch. 16.5 - Prob. 43E Ch. 16.5 - Prob. 44E Ch. 16.5 - Prob. 45E Ch. 16.5 - Prob. 46E Ch. 16.5 - Prob. 47E Ch. 16.5 - Prob. 48E Ch. 16.5 - Prob. 49E Ch. 16.5 - 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Prob. 29E Ch. 16.6 - Prob. 30E Ch. 16.6 - Prob. 31E Ch. 16.6 - Prob. 32E Ch. 16.6 - Prob. 33E Ch. 16.6 - Prob. 34E Ch. 16.6 - Prob. 35E Ch. 16.6 - Prob. 36E Ch. 16.6 - Prob. 37E Ch. 16.6 - Prob. 38E Ch. 16.6 - Prob. 39E Ch. 16.6 - Prob. 40E Ch. 16.6 - Prob. 41E Ch. 16.6 - Prob. 42E Ch. 16.6 - Prob. 43E Ch. 16.6 - Prob. 44E Ch. 16.6 - Prob. 45E Ch. 16.6 - Prob. 46E Ch. 16.6 - Prob. 47E Ch. 16.6 - Prob. 48E Ch. 16.6 - Prob. 49E Ch. 16.6 - Prob. 50E Ch. 16.6 - Prob. 51E Ch. 16.6 - Prob. 52E Ch. 16 - Prob. 1CRE Ch. 16 - Prob. 2CRE Ch. 16 - Prob. 3CRE Ch. 16 - Prob. 4CRE Ch. 16 - Prob. 5CRE Ch. 16 - Prob. 6CRE Ch. 16 - Prob. 7CRE Ch. 16 - Prob. 8CRE Ch. 16 - Prob. 9CRE Ch. 16 - Prob. 10CRE Ch. 16 - Prob. 11CRE Ch. 16 - Prob. 12CRE Ch. 16 - Prob. 13CRE Ch. 16 - Prob. 14CRE Ch. 16 - Prob. 15CRE Ch. 16 - Prob. 16CRE Ch. 16 - Prob. 17CRE Ch. 16 - Prob. 18CRE Ch. 16 - Prob. 19CRE Ch. 16 - Prob. 20CRE Ch. 16 - Prob. 21CRE Ch. 16 - Prob. 22CRE Ch. 16 - Prob. 23CRE Ch. 16 - Prob. 24CRE Ch. 16 - Prob. 25CRE Ch. 16 - Prob. 26CRE Ch. 16 - Prob. 27CRE Ch. 16 - Prob. 28CRE Ch. 16 - Prob. 29CRE Ch. 16 - Prob. 30CRE Ch. 16 - Prob. 31CRE Ch. 16 - Prob. 32CRE Ch. 16 - Prob. 33CRE Ch. 16 - Prob. 34CRE Ch. 16 - Prob. 35CRE Ch. 16 - Prob. 36CRE Ch. 16 - Prob. 37CRE Ch. 16 - Prob. 38CRE Ch. 16 - Prob. 39CRE Ch. 16 - Prob. 40CRE Ch. 16 - Prob. 41CRE Ch. 16 - Prob. 42CRE Ch. 16 - Prob. 43CRE Ch. 16 - Prob. 44CRE Ch. 16 - Prob. 45CRE Ch. 16 - Prob. 46CRE Ch. 16 - Prob. 47CRE Ch. 16 - Prob. 48CRE Ch. 16 - Prob. 49CRE Ch. 16 - Prob. 50CRE Ch. 16 - Prob. 51CRE Ch. 16 - Prob. 52CRE Ch. 16 - Prob. 53CRE Ch. 16 - Prob. 54CRE Ch. 16 - Prob. 55CRE Ch. 16 - Prob. 56CRE Ch. 16 - Prob. 57CRE Ch. 16 - Prob. 58CRE Ch. 16 - Prob. 59CRE Ch. 16 - Prob. 60CRE Ch. 16 - Prob. 61CRE

Knowledge Booster

Use the inverse in exercise 9 to find (a)A point in the u v plane mapping to ( 2 , 1 ) . (b)a segment in the u v plane to the segment joining ( − 2 , 1 ) and ( 3 , 4 ) .

Solution Summary: The author explains how to find a point in the u v plane mapping to ( 2, 1 ).

To find:

Use the inverse in exercise 9 to find

(a)A point in the $u v$ plane mapping to $(2, 1)$ .

(b)a segment in the $u v$ plane to the segment joining $(- 2, 1) and (3, 4)$ .

Want to see the full answer?

Chapter 16 Solutions

Use the inverse in exercise 9 to find (a)A point in the u v plane mapping to ( 2 , 1 ) . (b)a segment in the u v plane to the segment joining ( − 2 , 1 ) and ( 3 , 4 ) .

Solution Summary: The author explains how to find a point in the u v plane mapping to ( 2, 1 ).

To find: Use the inverse in exercise 9 to find (a)A point in the uv plane mapping to (2,1). (b)a segment in the uv plane to the segment joining (−2,1) and (3,4).

Want to see the full answer?

Chapter 16 Solutions

To find:

Use the inverse in exercise 9 to find

(a)A point in the $u v$ plane mapping to $(2, 1)$ .

(b)a segment in the $u v$ plane to the segment joining $(- 2, 1) and (3, 4)$ .