Introduction to Algorithms
3rd Edition
ISBN: 9780262033848
Author: Thomas H. Cormen, Ronald L. Rivest, Charles E. Leiserson, Clifford Stein
Publisher: MIT Press
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Chapter 18.2, Problem 2E
Program Plan Intro
To explain the circumstances of redundant DISK-READ or DISK-WRITE is called by B-TREE-INSERT.
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Present an algorithm (in outline form) for inserting an element into a sorted linked list so that the list is always in sorted order. Do not utilize a sorting routine, but rather devise an insert (add) algorithm that will search the list and insert the new element in the proper place in the list so that the list is always in order. Assume that the objects involved all properly override both the equals (==) and the compareTo (>, <, >=, and <=) methods. The list is to be maintained in ascending order. Assume that the add method has the following signature. public void Add(E element)
Suppose 1,000 Integer elements are generated at random and are inserted into a
sorted linked list and a binary search tree (BST) separately. Considering the efficiency
of searching for an element in the two structures, which of the following statements
is true?
The search operation on the list takes longer time because the numbers are not
sorted.
The search operation will take the same time in both structures.
The search operation on the BST takes shorter time because it is relatively
balanced.
None of these.
The search operation on the BST takes longer time because the numbers are not
sorted.
Question 10
The enqueue() operation on a QueueADT can be implemented in constant time using
(Select all which apply.)
a singly-linked list (with a tail reference) where the front of the queue is the head of the list
a singly-linked list (without a tail reference) where the front of the queue is the head of the list
an oversized array where the back of the queue is at index size-1
an oversized array where the back of the queue is always at index
an oversized array with circular indexing
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- Develop a linked-list processing function, IsolateTargetSoloAsTail, to process a linked list as follows. ● If a target cannot be found on the given list, a new node containing the target is created and added to the list's end (made the new tail node). ► This includes the case where the given list is empty, in which the new tail node added is also the new head node. (This is so because the only node in a 1-node list is the list's head and tail node.) ● If the target appears only once on the given list, the target-matching node is moved to the list's end (made the new tail node). ► Nothing needs to be done if the target-matching node is already the tail node (of the given list). ● If the target appears multiple times on the given list, the first target-matching node is moved to the list's end (made the new tail node), and all other target-matching nodes are to be deleted from the list. ► Note that although the target-matching node to be…arrow_forwardConstruct a data type akin to a queue that only allows one insert per element. Maintain a record of all inserted objects in an existence symbol table, and prevent attempts to re-insert them.arrow_forwardGiven a singly linked list START, to insert a data element ITEM into the list tothe right of node NODE (ITEM is to be inserted as the successor of the data elementrepresented by node NODE), Write the steps to be undertaken and illustrates the logical representation of the insert operation.arrow_forward
- Two major issues of simple Queue data structure are 1) Memory wastage, and 2) limitation of using the same array indices again after the queue elements are deleted. How can you solve these problems? Briefly explain your proposed solutions.What changes you need to make in the following enqueue() function, so that the above-mentioned problems will not happen again.Perform this task on paper, take a clear picture of solution and paste it in answer section. void enqueue(int val) { if(isFull()) cout<<”Queue is Full”<<endl; else myArray[++rear] = val; }arrow_forwardCombine the STAQUE abstract data type, a linked stack, and a linked queue. Create procedures for insert and delete operations, PUSHINS and POPDEL, on a non-empty STAQUE.PUSHINS adds an element to the top or rear of the STAQUE, whereas POPDEL removes items from the top or front of the list, according on a directive supplied to the process.arrow_forward(a) In implementing a Queue using an array, a problem might arise if the Queueis implemented in such a way that items in the Queue are inserted at thenext available location and removed from the next leading position, butsuch that, once deleted, the emptied space is unused. The problem thatarises is one where there is free space still in the array, but it is not usablebecause it is not at the end.Demonstrate this problem with a Queue that is stored in an array of size 5for the following instructions. Next, explain how you might resolve thisproblem.Queue q = new Queue(5); // assume the Queue constructor takes 5 asthe size of the arrayq.enqueue(3);q.enqueue(4);q.enqueue(1);q.dequeue( );q.dequeue( );q.enqueue(6);q.enqueue(5);q.dequeue( ); // at this point,// there are only 2 item2 in the queueq.enqueue(7); // this enqueue cannot occur, why??arrow_forward
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