Physics for Scientists and Engineers: Foundations and Connections
1st Edition
ISBN: 9781133939146
Author: Katz, Debora M.
Publisher: Cengage Learning
expand_more
expand_more
format_list_bulleted
Question
Chapter 19.3, Problem 19.3CE
To determine
The explanation for the statement ‘if the potential energy curve were symmetric, hot materials would not expand’.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
A white dwarf star is essentially a degenerate electron gas, with a bunch of nuclei mixed in to balance the charge and to provide the gravitational attraction that holds the star together. In this problem you will derive a relation between the mass and the radius of a white dwarf star, modeling the star as a uniform-density sphere. White dwarf stars tend to be extremely hot by our standards; nevertheless, it is an excellent approximation in this problem to set T = O.
Question is attached
A white dwarf star is essentially a degenerate electron gas, with a bunch of nuclei mixed in to balance the charge and to provide the gravitational attraction that holds the star together. In this problem you will derive a relation between the mass and the radius of a white dwarf star, modeling the star as a uniform-density sphere. White dwarf stars tend to be extremely hot by our standards; nevertheless, it is an excellent approximation in this problem to set T = O.
Suppose instead that the electrons in the white dwarf star are highly relativistic. Using the result of the previous problem, show that the total kinetic energy of the electrons is now proportional to 1/R instead of 1/R2. Argue that there is no stable equilibrium radius for such a star.
Show that for an ideal gas _ c p = _ c v + Ru.
Chapter 19 Solutions
Physics for Scientists and Engineers: Foundations and Connections
Ch. 19.1 - The Fahrenheit scale remains useful in part due to...Ch. 19.2 - Prob. 19.2CECh. 19.3 - Prob. 19.3CECh. 19.3 - Prob. 19.4CECh. 19.4 - Prob. 19.5CECh. 19.5 - Prob. 19.6CECh. 19.6 - Prob. 19.7CECh. 19 - Prob. 1PQCh. 19 - Prob. 2PQCh. 19 - Prob. 3PQ
Ch. 19 - Prob. 4PQCh. 19 - Prob. 5PQCh. 19 - Prob. 6PQCh. 19 - Prob. 7PQCh. 19 - Prob. 8PQCh. 19 - Object A is placed in thermal contact with a very...Ch. 19 - Prob. 10PQCh. 19 - Prob. 11PQCh. 19 - Prob. 12PQCh. 19 - Prob. 13PQCh. 19 - The tallest building in Chicago is the Willis...Ch. 19 - Prob. 15PQCh. 19 - Prob. 16PQCh. 19 - At 22.0C, the radius of a solid aluminum sphere is...Ch. 19 - Prob. 18PQCh. 19 - Prob. 19PQCh. 19 - Prob. 20PQCh. 19 - The distance between telephone poles is 30.50 m in...Ch. 19 - Prob. 22PQCh. 19 - Prob. 23PQCh. 19 - Prob. 24PQCh. 19 - Prob. 25PQCh. 19 - Prob. 26PQCh. 19 - Prob. 27PQCh. 19 - Prob. 28PQCh. 19 - Prob. 29PQCh. 19 - Prob. 30PQCh. 19 - Prob. 31PQCh. 19 - Prob. 32PQCh. 19 - Prob. 33PQCh. 19 - Prob. 34PQCh. 19 - Prob. 35PQCh. 19 - Prob. 36PQCh. 19 - Prob. 37PQCh. 19 - Prob. 38PQCh. 19 - Prob. 39PQCh. 19 - On a hot summer day, the density of air at...Ch. 19 - Prob. 41PQCh. 19 - Prob. 42PQCh. 19 - Prob. 43PQCh. 19 - Prob. 44PQCh. 19 - Prob. 45PQCh. 19 - Prob. 46PQCh. 19 - Prob. 47PQCh. 19 - A triple-point cell such as the one shown in...Ch. 19 - An ideal gas is trapped inside a tube of uniform...Ch. 19 - Prob. 50PQCh. 19 - Prob. 51PQCh. 19 - Case Study When a constant-volume thermometer is...Ch. 19 - An air bubble starts rising from the bottom of a...Ch. 19 - Prob. 54PQCh. 19 - Prob. 55PQCh. 19 - Prob. 56PQCh. 19 - Prob. 57PQCh. 19 - Prob. 58PQCh. 19 - Prob. 59PQCh. 19 - Prob. 60PQCh. 19 - Prob. 61PQCh. 19 - Prob. 62PQCh. 19 - Prob. 63PQCh. 19 - Prob. 64PQCh. 19 - Prob. 65PQCh. 19 - Prob. 66PQCh. 19 - Prob. 67PQCh. 19 - Prob. 68PQCh. 19 - Prob. 69PQCh. 19 - Prob. 70PQCh. 19 - Prob. 71PQCh. 19 - A steel plate has a circular hole drilled in its...Ch. 19 - Prob. 73PQCh. 19 - A gas is in a container of volume V0 at pressure...Ch. 19 - Prob. 75PQCh. 19 - Prob. 76PQCh. 19 - Prob. 77PQCh. 19 - Prob. 78PQCh. 19 - Prob. 79PQCh. 19 - Prob. 80PQCh. 19 - Two glass bulbs of volumes 500 cm3 and 200 cm3 are...
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- My physics class has turned to online due to the COVID-19 and I am having trouble with some of the word problems my teacher gave me to work on. She presented me with: I am contemplating a career change. If I had 500g of stolen gold jewelry, how much energy would I have to add to it to melt it (so that it was not longer recognizable)? Pretend that it is pure gold. Would you be able to show me how to accomplish this problem so I can see the steps? Thank you for your time. John Paytonarrow_forwardQuestion 6: Free energy minimization Consider a theoretical system in which the particles interact so that the internal energy depends on volume as U = nRT + n², where A = 1.31e+01 J m³/mole² is a very small repulsive interaction between the particles and S = nRln V. Using minimization of free energy with respect to the volume, find the external pressure if the equilibrium volume is 1.64e-02 m³, the number of particles is 3.04e+00 moles, and the temperature is 2.30e+02 K (a) 3.55e+05 Pa (b) -9.54e+04 Pa (c) 3.62e+05 Pa (d) 3.48e+05 Pa (e) 8.05e+05 Pa ✓ ✓ 100% This question is complete and cannot be answered again.arrow_forwardIn the simple kinetic theory of a gas we discussed in class, the molecules are assumed to be point-like objects (without any volume) so that they rarely collide with one another. In reality, each molecule has a small volume and so there are collisions. Let's assume that a molecule is a hard sphere of radius r. Then the molecules will occasionally collide with each other. The average distance traveled between two successive collisions (called mean free path) is λ = V/(4π √2 r2N) where V is the volume of the gas containing N molecules. Calculate the mean free path of a H2 molecule in a hydrogen gas tank at STP. Assume the molecular radius to be 10-10 a) 2.1*10-7 m b) 4.2*10-7 m c) none of these.arrow_forward
- At what temperature would the rms speed of the helium atoms (mass=6.66x10^-27kg) equal its escape speed from the earth which is 1.12x 10^4 m/s? Answer is given as 60509 K but cannot figure out how that could be it.arrow_forwardHelium atoms interact very weakly with each other; helium only liquefies at 4.2 K at standardpressure. What is the kinetic energy of a helium atom:(a) at 100. K?(b) at 10.0 K?arrow_forwardA white dwarf star is essentially a degenerate electron gas, with a bunch of nuclei mixed in to balance the charge and to provide the gravitational attraction that holds the star together. In this problem you will derive a relation between the mass and the radius of a white dwarf star, modeling the star as a uniform-density sphere. White dwarf stars tend to be extremely hot by our standards; nevertheless, it is an excellent approximation in this problem to set T = O. The equilibrium radius of the white dwarf is that which minimizes the total energy Ugrav + Ukinetic. Sketch the total energy as a function of R, and find a formula for the equilibrium radius in terms of the mass. As the mass increases, does the radius increase or decrease? Does this make sense?arrow_forward
- A boat explodes in two fragments of masses 100 kg and 97 kg after being launched accidentally, without knowing their directions. If the speed of the first and second fragments are 50 m/s and 100 m/s, find the minimum internal energy of the explosion.arrow_forwardAn ideal gas is confined to a container at a temperature of 330 K. 1)What is the average kinetic energy of an atom of the gas? (Express your answer to two significant figures.)arrow_forwardI) We consider atoms of rubidium in the gaseous state. The molar mass of rubidium is M-87 g/mol. 1) At T=900 K, the rubidium acts like and ideal gas. At this temperature the free energy F is given by h2 F = -kgT ln Z where Z = with z N! V and A = (; 1/2 N being the number of 2TmkBT particles of the gas and m the mass of one particle. a) Explain the presence of the N! in the equation. b) Derive the expression of F as a function of T and the number of particles per unit volume, n=N/V. c) Show that u = T In(nA) where 7 is a quantity that you will express as a function of T.arrow_forward
- The vapor pressure of pure solid silver and solid silver-palladium alloys are given in the following: For silver: -13,700 T log P For the solid silver-palladium alloy: -13,800 log P = T Derive the free energy v. temperature of the two systems. -+8.73 +8.65 (torr) (torr)arrow_forwardHow much work do we have to do (in J, at a constant temperature) to atomize a liquid with a volume of 1 dm3 if droplets of the same size are formed during atomization? For simplicity, assume that the droplet is cube-shaped with an edge length of 1000 nm and a surface tension of 50 mJ / m2.arrow_forward3. (Zemansky and Dittman, Problem 9.13) a) Derive the equation aCy av =T aT2 b) Use the preceding result to prove that for an ideal gas, Cy is a function of T only.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Physics for Scientists and Engineers: Foundations...PhysicsISBN:9781133939146Author:Katz, Debora M.Publisher:Cengage Learning
Physics for Scientists and Engineers: Foundations...
Physics
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Cengage Learning
The Laws of Thermodynamics, Entropy, and Gibbs Free Energy; Author: Professor Dave Explains;https://www.youtube.com/watch?v=8N1BxHgsoOw;License: Standard YouTube License, CC-BY