College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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Chapter 23, Problem 6CQ
To determine
The possibility of taking photograph of virtual image.
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College Physics
Ch. 23.1 - In the overhead view if Figure 23.3, the image of...Ch. 23.3 - A person spearfishing from a boat sees a fish...Ch. 23.3 - True or False: (a) The image of an object placed...Ch. 23.5 - A clear plastic sandwich bag filled with water can...Ch. 23.5 - In Figure 23.25a, the blue object arrow is...Ch. 23.5 - An object is placed to the left of a converging...Ch. 23 - Tape a picture of yourself on a bathroom mirror....Ch. 23 - Prob. 2CQCh. 23 - The top row of Figure CQ23.3 shows three ray...Ch. 23 - Construct ray diagrams to determine whether each...
Ch. 23 - Construct ray diagrams to determine whether each...Ch. 23 - Prob. 6CQCh. 23 - Suppose you want to use a converging lens to...Ch. 23 - Lenses used in eyeglasses, whether converging or...Ch. 23 - In a Jules Verne novel, a piece of ice is shaped...Ch. 23 - If a cylinder of solid glass or clear plastic is...Ch. 23 - Prob. 11CQCh. 23 - Prob. 12CQCh. 23 - Why does the focal length of a mirror not depend...Ch. 23 - A person spear fishing from a boat sees a...Ch. 23 - An object represented by a gray arrow, is placed...Ch. 23 - (a) Does your bathroom mirror show you older or...Ch. 23 - Suppose you stand in front of a flat mirror and...Ch. 23 - Prob. 3PCh. 23 - In a church choir loft, two parallel walls are...Ch. 23 - A periscope (Fig. P23.5) is useful for viewing...Ch. 23 - A dentist uses a mirror to examine a tooth that is...Ch. 23 - A convex spherical mirror, whose focal length has...Ch. 23 - To fit a contact lens to a patient's eye, a...Ch. 23 - A virtual image is formed 20.0 cm from a concave...Ch. 23 - While looking at her image in a cosmetic minor,...Ch. 23 - Prob. 11PCh. 23 - A dedicated sports car enthusiast polishes the...Ch. 23 - A concave makeup mirror it designed to that a...Ch. 23 - A 1.80-m-tall person stands 9.00 m in front of a...Ch. 23 - A man standing 1.52 m in front of a shaving mirror...Ch. 23 - Prob. 16PCh. 23 - At an intersection of hospital hallways, a convex...Ch. 23 - The mirror of a solar cooker focuses the Suns rays...Ch. 23 - A spherical mirror is to be used to form an image,...Ch. 23 - Prob. 20PCh. 23 - A cubical block of ice 50.0 cm on an edge is...Ch. 23 - A goldfish is swimming inside a spherical bowl of...Ch. 23 - A paperweight is made of a solid hemisphere with...Ch. 23 - The top of a swimming pool is at ground level. If...Ch. 23 - A transparent sphere of unknown composition is...Ch. 23 - A man inside a spherical diving bell watches a...Ch. 23 - A jellyfish is floating in a water-filled aquarium...Ch. 23 - Figure P23.28 shows a curved surface separating a...Ch. 23 - A contact lens is made of plastic with an index of...Ch. 23 - A thin plastic lens with index of refraction n =...Ch. 23 - A converging lens has a local length of 10.0 cm....Ch. 23 - Prob. 32PCh. 23 - A diverging lens has a focal length of magnitude...Ch. 23 - A diverging lens has a focal length of 20.0 cm....Ch. 23 - Prob. 35PCh. 23 - The nickels image in Figure P23.36 has twice the...Ch. 23 - An object of height 8.00 cm it placed 25.0 cm to...Ch. 23 - An object is located 20.0 cm to the left of a...Ch. 23 - A converging lens is placed 30.0 cm to the right...Ch. 23 - (a) Use the thin-lens equation to derive an...Ch. 23 - Two converging lenses, each of focal length 15.0...Ch. 23 - A converging lens is placed at x = 0, a distance d...Ch. 23 - A 1.00-cm-high object is placed 4.00 cm to the...Ch. 23 - Two converging lenses having focal length of f1 =...Ch. 23 - Lens L1 in figure P23.45 has a focal length of...Ch. 23 - An object is placed 15.0 cm from a first...Ch. 23 - Prob. 47APCh. 23 - Prob. 48APCh. 23 - Prob. 49APCh. 23 - Prob. 50APCh. 23 - The lens and the mirror in figure P23.51 are...Ch. 23 - The object in Figure P23.52 is mid-way between the...Ch. 23 - Prob. 53APCh. 23 - Two rays travelling parallel to the principal axis...Ch. 23 - To work this problem, use the fact that the image...Ch. 23 - Consider two thin lenses, one of focal length f1...Ch. 23 - An object 2.00 cm high is placed 10.0 cm to the...Ch. 23 - Prob. 58APCh. 23 - Figure P23.59 shows a converging lens with radii...Ch. 23 - Prob. 60APCh. 23 - The lens-makers equation for a lens with index n1...Ch. 23 - An observer to the right of the mirror-lens...Ch. 23 - The lens-markers equation applies to a lens...Ch. 23 - Prob. 64APCh. 23 - A glass sphere (n = 1.50) with a radius of 15.0 cm...Ch. 23 - An object 10.0 cm tall is placed at the zero mark...
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- A ray of light strikes a flat, 2.00-cm-thick block of glass (n = 1.50) at ail angle of 30.0 with respect to the normal (Fig. P22.18). (a) Find the angle of refraction at the lop surface. (b) Find the angle of incidence at the bottom surface and the refracted angle. (c) Find the lateral distance d by which the light beam is shifted. (d) Calculate the speed of light in the glass and (e) the time required for the light to pass through the glass block. (f) Is the travel time through the block affected by the angle of incidence? Explain.arrow_forwardA thin plastic lens with index of refraction n = 1.67 has radii of curvature given by R1 = 12 0 cm and R2 = 40.0 cm. Determine (a) the focal length of the lens, (b) whether the lens Ls converging or diverging and the image distances for object distances of (c) infinity, (d) 8,00 cm, and (e) 50.0 cm.arrow_forwardFigure P23.28 shows a curved surface separating a material with index of refraction n1 from a material with index n2. The surface forms an image I of object O. The ray shown in red passes through the surface along a radial line. Its angles of incidence and refraction are both zero, so its direction does not change at the surface. For the ray shown in blue, the direction changes according to n1 sin 1 = n2 sin 2. For paraxial rays, we assume 1 and 2 are small, so we may write n1 tan 1 n2 tan 2. The magnification is defined as M = h/h. Prove that the magnification is given by M = n1q/n2p. Figure P23.28arrow_forward
- Figure P36.95 shows a thin converging lens for which the radii of curvature of its surfaces have magnitudes of 9.00 cm and 11.0 cm. The lens is in front of a concave spherical mirror with the radius of curvature R = 8.00 cm. Assume the focal points F1 and F2 of the lens are 5.00 cm from the center of the lens, (a) Determine the index of refraction of the lens material. The lens and mirror are 20.0 cm apart, and an object is placed 8.00 cm to the left of the lens. Determine (b) the position of the filial image and (c) its magnification as seen by the eye in the figure. (d) Is the final image inverted or upright? Explain.arrow_forwardA thin plastic lens with index of refraction n = 1.67 has radii of curvature given by R1 = 12 0 cm and R2 = 40.0 cm. Determine (a) the focal length of the lens, (b) whether the lens Ls converging or diverging and the image distances for object distances of (c) infinity, (d) 8,00 cm, and (e) 50.0 cm.arrow_forwardThe end of a solid glass rod of refractive index 1.50 is polished to have the shape of a hemispherical surface of radius 1.0 cm. A small object is placed in air (refractive index 1.00) on the axis 5.0 cm to the left of the vertex. Determine the position of the image.arrow_forward
- The object in Figure P23.52 is mid-way between the lens and the mirror, which are separated by a distance d = 25.0 cm. The magnitude of the mirrors radius of curvature is 20.0 cm, and the lens has a focal length of 16.7 cm. (a) Considering only the light that leaves the object and travels first toward the mirror, locate the final image formed by this system. (b) Is the image real or virtual? (c) Is it upright or inverted? (d) What is the overall magnification of the image? Figure P23.52arrow_forwardLight passes from a material with index of refraction 1.3 into one with index of refraction 1.2. Compared with the incident ray, what happens to the refracted ray? (a) It bends toward the normal. (b) It is undeflected. (c) It bends away from the normal.arrow_forwardA leaf of length h is positioned 71.0 cm in front of a converging lens with a focal length of 39.0 cm. An observer views the image of the leaf from a position 1.26 in behind the lens, as shown in Figure P25.25. (a) What is the magnitude of the lateral magnification (the ratio of the image size to the object size) produced by the lens? (b) What angular magnification is achieved by viewing the image of the leaf rather than viewing the loaf directly? Figure P25.25arrow_forward
- Figure P26.72 shows a thin converging lens for which the radii of curvature of its surfaces have magnitudes of 9.00 cm and 11.0 cm. The lens is in front of a concave spherical mirror with the radius of curvature R = 8.00 cm. Assume the focal points F1 and F2 of the lens are 5.00 cm from the center of the lens. (a) Determine the index of refraction of the lens material. The lens and mirror are 20.0 cm apart, and an object is placed 8.00 cm to the left of the lens. Determine (b) the position of the final image and (c) its magnification as seen by the eye in the figure. (d) Is the final image inverted or upright? Explain.arrow_forwardA lamp of height S cm is placed 40 cm in front of a converging lens of focal length 20 cm. There is a plane mirror 15 cm behind the lens. Where would you find the image when you look in the mirror?arrow_forwardA man inside a spherical diving bell watches a fish through a window in the bell, as in Figure P23.26. If the diving bell has radius R = 1.75 m and the fish is a distance p = 1 00 m from the window, calculate (a) the image distance and (b) the magnification. Neglect the thickness of the window. Figure P23.26arrow_forward
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AP Physics 2 - Geometric Optics: Mirrors and Lenses - Intro Lesson; Author: N. German;https://www.youtube.com/watch?v=unT297HdZC0;License: Standard YouTube License, CC-BY