Physics for Scientists and Engineers
6th Edition
ISBN: 9781429281843
Author: Tipler
Publisher: MAC HIGHER
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Chapter 26, Problem 57P
(a)
To determine
The proof that average current is
(b)
To determine
The proof that relation between magnetic moment and
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A bismuth ball of radius r=5 mm is placed in a magnetic field of induction vector B=2*10^(-5) T. What is the magnetic moment of the ball? What is its direction? The magnetic susceptibility of bismuth is -7.6*10^(-4).
A charge q is distributed uniformly around a thin ring of radius r.The ring is rotating about an axis through its center and perpendicular to its plane, at an angular speed v. (a) Show that the magnetic moment due to the rotating charge has magnitude m mw 1/2 qvr 2 . (b) What is the direction of this magnetic moment if the charge is positive?
The angular momentum of a mass distribution where a differential element particle of mass m with velocity v and located
at position r is defined in the form
L =
dmr x v =
dvpr x v,
p= nm
where n is the number of particles per unit volume and m is its mass. If each of the particles has a charge q, with their
movement they constitute a current
J = nqv
Show that the relationship between the magnetic dipole moment and the angular momentum is
L
m =
2m
where the magnetic moment is defined
m =
dvr x J
Chapter 26 Solutions
Physics for Scientists and Engineers
Ch. 26 - Prob. 1PCh. 26 - Prob. 2PCh. 26 - Prob. 3PCh. 26 - Prob. 4PCh. 26 - Prob. 5PCh. 26 - Prob. 6PCh. 26 - Prob. 7PCh. 26 - Prob. 8PCh. 26 - Prob. 9PCh. 26 - Prob. 10P
Ch. 26 - Prob. 11PCh. 26 - Prob. 12PCh. 26 - Prob. 13PCh. 26 - Prob. 14PCh. 26 - Prob. 15PCh. 26 - Prob. 16PCh. 26 - Prob. 17PCh. 26 - Prob. 18PCh. 26 - Prob. 19PCh. 26 - Prob. 20PCh. 26 - Prob. 21PCh. 26 - Prob. 22PCh. 26 - Prob. 23PCh. 26 - Prob. 24PCh. 26 - Prob. 25PCh. 26 - Prob. 26PCh. 26 - Prob. 27PCh. 26 - Prob. 28PCh. 26 - Prob. 29PCh. 26 - Prob. 30PCh. 26 - Prob. 31PCh. 26 - Prob. 32PCh. 26 - Prob. 33PCh. 26 - Prob. 34PCh. 26 - Prob. 35PCh. 26 - Prob. 36PCh. 26 - Prob. 37PCh. 26 - Prob. 38PCh. 26 - Prob. 39PCh. 26 - Prob. 40PCh. 26 - Prob. 41PCh. 26 - Prob. 42PCh. 26 - Prob. 43PCh. 26 - Prob. 44PCh. 26 - Prob. 45PCh. 26 - Prob. 46PCh. 26 - Prob. 47PCh. 26 - Prob. 48PCh. 26 - Prob. 49PCh. 26 - Prob. 50PCh. 26 - Prob. 51PCh. 26 - Prob. 52PCh. 26 - Prob. 53PCh. 26 - Prob. 54PCh. 26 - Prob. 55PCh. 26 - Prob. 56PCh. 26 - Prob. 57PCh. 26 - Prob. 58PCh. 26 - Prob. 59PCh. 26 - Prob. 60PCh. 26 - Prob. 61PCh. 26 - Prob. 62PCh. 26 - Prob. 63PCh. 26 - Prob. 64PCh. 26 - Prob. 65PCh. 26 - Prob. 66PCh. 26 - Prob. 67PCh. 26 - Prob. 68PCh. 26 - Prob. 69PCh. 26 - Prob. 70PCh. 26 - Prob. 71PCh. 26 - Prob. 72PCh. 26 - Prob. 73PCh. 26 - Prob. 74PCh. 26 - Prob. 75PCh. 26 - Prob. 76PCh. 26 - Prob. 77PCh. 26 - Prob. 78PCh. 26 - Prob. 79PCh. 26 - Prob. 80PCh. 26 - Prob. 81P
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- Let E be the electric field of magnitude 6.0x10^6 N/C and B be the magnetic fi electron is accelerated with a potential of 200 V, will it show zero deflection?arrow_forwardConsider an electron rotating in a circular orbit of radius r. Show that the magnitudes of the magnetic dipole moment μ and the angular momentum L of the electron are related by: μ/L = e/2m.arrow_forwardUsing the Right-hand rule, find the direction of the torque if the magnetic moment is along the +x axis and the magnetic field is along the +z axisarrow_forward
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