Physics for Scientists and Engineers
6th Edition
ISBN: 9781429281843
Author: Tipler
Publisher: MAC HIGHER
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Chapter 29, Problem 28P
(a)
To determine
To Show:
(b)
To determine
To Show:
Q factor is dimensionless.
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Chapter 29 Solutions
Physics for Scientists and Engineers
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- The emf of an ac source is given by v(t)=V0sint, where V0=100V and =200 . Find an expression that represents the output current of the source if it is connected across (a) a 20-pF capacitor, (b) a 20-mH inductor, and (c) a 50 resistor.arrow_forwardDo Kirchhoff’s rules apply to circuits that contain inductors and Capacitors?arrow_forwardAt s1iat frequency is the reactance of a 20F capacitor equal to that of a 10-mH inductor?arrow_forward
- An ac source of voltage amplitude 10 V delivers electric energy at a rate of 0.80 W when its current output is 2.5 A. What is the phase angle between the emf and the current?arrow_forwardAt 1000 Hz, the reactance of a 5.0-mH inductor is equal to the reactance of a particular capacitor. What is the capacitance of the capacitor?arrow_forwardWhat is the resistance R in the circuit shown below if the amplitude of the ac through the inductor is 4.24 A?arrow_forward
- A 40-mH inductor is connected to a 60-Hz AC source whose voltage amplitude is 50 V. If an AC voltmeter is placed across the inductor, what does it read?arrow_forwardCan a circuit e1eent have both capacitance and inductance?arrow_forwardThe self-inductance and capacitance of an oscillating LC circuit are L = 20 mH and C = 1.0 F , respectively. (a) What is the frequency of the oscillation? (b) If the maximum potential difference the plates of the capacitor is 50 V, what is the maximum current in the circuit?arrow_forward
- L, C and R represent the physical quantities inductance, capacitance and resistance respectively. The combinations which have the dimensions of frequency are (a) RC R (b) L (c) VLC (d)는arrow_forwardThe diagram shows a simple electric circuit consisting of a power source, a resistor, and an inductor. If voltage V is first applied at time t = 0, then the current I flowing through the circuit at time t is given by I as attached, where L is the inductance and R is the resistance. Use L’Hôpital’s Rule to find the formula for the current by fixing V and L and letting R approach 0 from the right.arrow_forwardThis problem concerns the electric circuit shown in the figure below. where C is the capacitance and L is the inductance, so A charged capacitor connected to an inductor causes a current to flow through the inductor until the capacitor is fully discharged. The current in the inductor, in turn, charges up the capacitor until the capacitor is fully charged again. If Q(t) is the charge on the capacitor at time t, and I is the current, then dQ dt If the circuit resistance is zero, then the charge Q and the current I in the circuit satisfy the differential equation dI 'dt + If L=1 henry, R=1 ohm, and C = 4 farads, find a formula for the charge when (a) Q (0) = 0 and Q (0) = 5: Q(t)= 4e^(-1/2) Capacitor L (b) Q(0) = 5 and Q (0) = 0: Q(t) = Resistor mamm DOUVID Inductor L I= 8²0+0=0 d²Q dt2 Then, just as as a spring can have a damping force which affects its motion, so can a circuit; this is introduced by the resistor, so that if the resistance of the resistor is R d²Q dQ dt +R dt² +9=0. www…arrow_forward
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