Introductory Chemistry: A Foundation
Introductory Chemistry: A Foundation
9th Edition
ISBN: 9781337399425
Author: Steven S. Zumdahl, Donald J. DeCoste
Publisher: Cengage Learning
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Chapter 3, Problem 15CR
Interpretation Introduction

Interpretation:

The value 593.2 kg should be converted to grams.

Concept Introduction:

An arithmetical multiplier which is used for converting a quantity expressed in one unit into another equivalent set of units is said to be conversion factor.

Expert Solution
Check Mark

Answer to Problem 15CR

5932 g.

Explanation of Solution

Since,  1 kg = 1000 gSo,  593.2 kg = 539.2 kg × 1000 g/ 1 kg5932 g.

Interpretation Introduction

Interpretation:

The value 593.2lbsshould be converted to grams.

Concept Introduction:

An arithmetical multiplier which is used for converting a quantity expressed in one unit into another equivalent set of units is said to be conversion factor.

Expert Solution
Check Mark

Answer to Problem 15CR

269070.99 g.

Explanation of Solution

Since, 1 lb = 453.592 g

So,  593.2 lb = 539.2 lb × 453.592 g/ 1 lb269070.99 g.

Interpretation Introduction

Interpretation:

The value 8.312 km should be converted to miles.

Concept Introduction:

An arithmetical multiplier which is used for converting a quantity expressed in one unit into another equivalent set of units is said to be conversion factor.

Expert Solution
Check Mark

Answer to Problem 15CR

5.165 miles.

Explanation of Solution

Since, 1 km = 0.6214 mile

So,  8.312 km = 8.312 km × 0.6214 mile/ 1 km5.165 miles.

Interpretation Introduction

Interpretation:

The value 8.312 ft should be converted to miles.

Concept Introduction:

An arithmetical multiplier which is used for converting a quantity expressed in one unit into another equivalent set of units is said to be conversion factor.

Expert Solution
Check Mark

Answer to Problem 15CR

0.00157 mile.

Explanation of Solution

Since, 1 ft = 0.000189 mile

So,  8.312 ft = 8.312 ft × 0.000189 mile / 1 ft0.00157 mile.

Interpretation Introduction

Interpretation:

The value 6.219 ft should be converted to meters.

Concept Introduction:

An arithmetical multiplier which is used for converting a quantity expressed in one unit into another equivalent set of units is said to be conversion factor.

Expert Solution
Check Mark

Answer to Problem 15CR

1.895 m.

Explanation of Solution

Since, 1 ft = 0.3048 m

So,  6.219 ft = 6.219 ft × 0.3048 m / 1 ft1.895 m.

Interpretation Introduction

Interpretation:

The value 6.219 cm should be converted to meters.

Concept Introduction:

An arithmetical multiplier which is used for converting a quantity expressed in one unit into another equivalent set of units is said to be conversion factor.

Expert Solution
Check Mark

Answer to Problem 15CR

0.06219 m.

Explanation of Solution

Since, 1 cm = 0.01 m

So,  6.219 cm = 6.219 cm × 0.01 m / 1 cm0.06219 m.

Interpretation Introduction

Interpretation:

The value 329.2 L should be converted to milliliters.

Concept Introduction:

An arithmetical multiplier which is used for converting a quantity expressed in one unit into another equivalent set of units is said to be conversion factor.

Expert Solution
Check Mark

Answer to Problem 15CR

329200 mL.

Explanation of Solution

Since, 1 L = 1000 mL

So,  329.2 L = 329.2 L × 1000 mL / 1 L329200 mL.

Interpretation Introduction

Interpretation:

The value 9.934 qts should be converted toliters.

Concept Introduction:

An arithmetical multiplier which is used for converting a quantity expressed in one unit into another equivalent set of units is said to be conversion factor.

Expert Solution
Check Mark

Answer to Problem 15CR

9.397 L.

Explanation of Solution

Since, 1 qt = 0.946 L

So,  9.934 qts= 9.934 qts× 0.946 L / 1 qt9.397 L.

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Chapter 3 Solutions

Introductory Chemistry: A Foundation

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