Genetic Analysis: An Integrated Approach (3rd Edition)
3rd Edition
ISBN: 9780134605173
Author: Mark F. Sanders, John L. Bowman
Publisher: PEARSON
expand_more
expand_more
format_list_bulleted
Concept explainers
Videos
Textbook Question
Chapter 3, Problem 29P
A wild-type Drosophila male and female are crossed, producing 324 female progeny and 161 male progeny. All their progeny are wild type.
a. Propose a genetic hypothesis to explain these data.
b. Design an experiment that will test your hypothesis, using the wild-type progeny identified above. Describe the results you expect if your hypothesis is true.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
Drosophila females heterozygous for three recessive mutations, a, b, and c , were crossed to males homozygous for all three mutations.The cross yielded the following results:
in the image
Q. Construct a linkage map showing the correct order of these genes and estimate the distances between them.
Some sweet-pea plants have purple flowers and others have white flowers. A homozygous variety of sweet pea that has purple flowers is crossed with a homozygous variety that has white flowers. All the F1 have purple flowers. When these F1 self-fertilize, the F2 appear in a ratio of 916 purple to 716 white. a. Give genotypes for the purple and white flowers in these crosses. b. Draw a hypothetical biochemical pathway to explain the production of purple and white flowers in sweet peas
The fruit fly, Drosophila melanogaster, a vestigial female fly is mated to a male that is scarlet eyes and bristled. Phenotypically wild type F1 female progeny were mated to fully homozygous (mutant) males, and the following progeny (of 1000 total) were observed (shown on table)
a. Which gene is in the middle?
b. What are the map distances between the three genes for this question?
c. Calculate and show the work for coefficient of coincidence
d. Calculate the interference. What does this mean and what does it tell you?
Chapter 3 Solutions
Genetic Analysis: An Integrated Approach (3rd Edition)
Ch. 3 - Examine the following diagrams of cells from an...Ch. 3 - Our closest primate relative, the chimpanzee, has...Ch. 3 -
3. In a test of his chromosome theory of...Ch. 3 - Cohesion between sister chromatids, as well as...Ch. 3 - 5. The diploid number of the hypothetical animal...Ch. 3 - 6. An organism has alleles R1 and R2 on one pair...Ch. 3 - Explain how the behavior of homologous chromosomes...Ch. 3 - 8. Suppose crossover occurs between the homologous...Ch. 3 -
9. Alleles A and a are on one pair of autosomes,...Ch. 3 - Prob. 10P
Ch. 3 - Describe the role of the following structures or...Ch. 3 - A womans father has ornithine transcarbamylase...Ch. 3 - In humans, hemophilia A (OMIM 306700) is an...Ch. 3 -
14. A wild-type male and a wild-type female...Ch. 3 - 15. A woman with severe discoloration of her tooth...Ch. 3 - 16. In a large metropolitan hospital, cells from...Ch. 3 - In cats, tortoiseshell coat color appears in...Ch. 3 - 18. The gene causing Coffin–Lowry syndrome (OMIM...Ch. 3 - 19. Four eye-color mutants in Drosophila—apricot,...Ch. 3 - 20. For each pedigree shown,
a. Identify which...Ch. 3 - 21. Use the blank pedigrees provided to depict...Ch. 3 - 22. Figure 3.22 (page 89) illustrates reciprocal...Ch. 3 - 23. In fruit flies, yellow body (y) is recessive...Ch. 3 - 24. In a species of fish, a black spot on the...Ch. 3 - LeschNyhan syndrome (OMIM 300322) is a rare...Ch. 3 - 26. In humans, SRY is located near a...Ch. 3 - 27. In an 1889 book titled Natural Inheritance...Ch. 3 - 28. In Drosophila, the X-linked echinus eye...Ch. 3 - 29. A wild-type Drosophila male and female are...Ch. 3 - 30. Drosophila has a diploid chromosome number of...Ch. 3 - The cell cycle operates in the same way in all...Ch. 3 - 33. Form a small discussion group and decide on...Ch. 3 - 34. Duchenne muscular dystrophy (DMD; OMIM 310200)...Ch. 3 - Prob. 35P
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biology and related others by exploring similar questions and additional content below.Similar questions
- The data set attached summarizes F2 numbers from an F1 cross arising from two, true-breeding Drosophila strains (P generation), which differ with respect to two mutant traits. Here are the hypothesis: Leg length - The wild-type and mutant alleles for leg length are incomplete dominant relative to each other. Justification: The data set includes three phenotypic categories for leg length: wild type (long leg), medium leg, and truncated wings. The presence of three distinct phenotypes suggests an incomplete dominance pattern, where the heterozygous individuals exhibit an intermediate leg length phenotype (medium leg). The absence of purebred short-legged individuals supports the idea that the long leg allele is dominant over the short leg allele. This shows that mode of inheritance is incomplete dominance of the alleles relative to each other. Since the data does not mention any specific differences between males and females, we can assume that the mode of inheritance for the trait is…arrow_forwardConsider the first category of test-cross offspring shown in figure 8.2 (+b, LS). Consider also that the parents of the heterozygous female flies in the test cross had the following genotypes: bb, SS, and +, LL. A. What would be the physical phenotype of these flies? B. If PC was conducted with the DNA of one of these flies using the primers for the molecular marker, what would be the appearance of the bands on an electrophoresis gel with the PC products? C. If the gene for black body and the locus for the molecular marker (L long or S short) were unlinked, what proportion of the test-cross progeny would be black flies that are heterozygous for the molecular marker? What proportion would be flies with normal body color, which are homozygous for one form of the molecular marker? D. If the gene for black body and the locus for the molecular marker were linked, how would the proportion of flies be different?arrow_forwardConsider two maize plants:a. Genotype C/c m ; Ac/Ac+, where cm is an unstable allele caused by a Ds insertionb. Genotype C/c m, where cm is an unstable allele caused by Ac insertionWhat phenotypes would be produced and in what proportions when (1) each plant is crossed with a basepair-substitution mutant c/c and (2) the plant in part a is crossed with the plant in part b? Assume that Ac and c are unlinked, that the chromosome-breakage frequency is negligible, and that mutant c /C is Ac+.arrow_forward
- In Drosophila, the wildtype eye color is black. In the laboratory, you screened for mutants than when homozygous results to different eye phenotypes. You found two mutants 1) red eye (re) and 2) white eye (we). You performed a complementation test and the resulting eye phenotype was gray. From the results, what conclusion can you make? A. There was complementation, thus the two mutations are alleles of different genes. B. There was no complementation, thus the two mutations are alleles of different genes. C. The two mutations failed to complement, thus they are alleles of different genes. D. The two mutations failed to complement, thus they are alleles of the same genes. E. The two mutations complemented, hence they are likely controlled by different genes.arrow_forwardYou believe that the gene you're investigating, eyes absent, is an autosomal recessive mutant allele F7 ge in Drosophila. You set up a cross between a true-breeding mutant male and a true-breeding wildtype female to obtain the F1 generation. You then cross the F1 flies. In the F2 offspring, you observe the following: 237 wild-type males 180 wild-type females 70 mutant males 83 mutant females Based on these findings, is the mutant allele autosomal recessive? How do you know?arrow_forwardPlease explain how you do this question step by step I am very confused! thank you:) You have three independent mutant alleles in the Drosophila gene no-antenna: nan1, nan2 and nan3. You determine the phenotype of Drosophila that are heterozygous for the three alleles (heterozygous for a wild-type allele and a mutant allele), and that are homozygous for the three mutant alleles. The antenna is composed of three segments that are followed at the distal end by a feathery arista (that is the antenna is composed of three segments and an arista). Allele nan1 nan2 nan3 heterozygous Wild-type No arista Wild-type homozygous No arista No antenna No antenna nan1 is a __x__ allele, nan2 is a __y__ allele, and nan3 is a __z__ allele. X Y Z A Dominant negative Null Hypomorphic B Null Dominant negative Hypomorphic C Null Hypomorphic Dominant negative D Hypomorphic Dominant negative Null E Dominant negative Hypomorphic Null Referencing the table above, select the…arrow_forward
- Answer the following with a short solution if needed: a. The gametes of a worm's genotype SsYy should produce what genotypes? b. A genetic cross between two F1-hybrid rose plants having yellow petals will yield what percent green-petal plants in the F2 generation? Yellow petals are dominant to green. c. Brown fur is dominant over light-colored fur. What is the phenotype of the resulting offspring if you cross a heterozygous brown fur and a light-colored fur?arrow_forwardSome sweet-pea plants have purple flowers and others have white flowers. A homozygous variety of sweet pea that has purple flowers is crossed with a homozygous variety that has white flowers. All the F1have purple flowers. When these F1 self-fertilize, the F2 appear in a ratio of 916 purple to 716 white. a.Draw a hypothetical biochemical pathway to explain the production of purple and white flowers in sweet peas.arrow_forwardThe normal color of snapdragons is red. Some pure lines showing the variations of flower color have been found. When these lines were crossed, they gave the results attached. A. From the data given, determine if alleles of one, two, or three genes are generating these traits and why? B. Define the results of cross #5 with gene symbols and a complete explanation of ratios and any relevant genetic terms.arrow_forward
- E. W. Lindstrom crossed two corn plants with green seedlings and obtained the following progeny: 3583 green seedlings, 853 virescentwhite seedlings, and 260 yellow seedlings (E. W. Lindstrom. 1921. Genetics 6:91–110). a. Give the genotypes for the green, virescent-white, and yellow progeny. b. Explain how color is determined in these seedlings. c. Is there epistasis among the genes that determine color in the corn seedlings? If so, which gene is epistatic and which is hypostatic?arrow_forwardConsider two maize plants:a. Genotype C/cm ; Ac/Ac+, where cm is an unstableallele caused by a Ds insertionb. Genotype C/cm, where cm is an unstable allele causedby Ac insertionWhat phenotypes would be produced and in whatproportions when (1) each plant is crossed with a basepair-substitution mutant c/c and (2) the plant in part a iscrossed with the plant in part b? Assume that Ac and care unlinked, that the chromosome-breakage frequencyis negligible, and that mutant c /C is Ac+.arrow_forwardConsider the first category of test-cross offspring shown in figure 8.2 (+b, LS). Consider also that the parents of the heterozygous female flies in the test cross had the following genotypes: bb, SS, and +, LL. A. What would be the physical phenotype of these flies? B. If PCR was conducted with the DNA of one of these flies using the primers for the molecular marker, what would be the appearance of the bands on an electrophoresis gel with the PCR products? C. If the gene for black body and the locus for the molecular marker (L long or S short) were unlinked, what proportion of the test-cross progeny would be black flies that are heterozygous for the molecular marker? What proportion would be flies with normal body color, which are homozygous for one form of the molecular marker? D. If the gene for black body and the locus for the molecular marker were linked, how would the proportion of flies be different?arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Human Anatomy & Physiology (11th Edition)BiologyISBN:9780134580999Author:Elaine N. Marieb, Katja N. HoehnPublisher:PEARSON
Biology 2eBiologyISBN:9781947172517Author:Matthew Douglas, Jung Choi, Mary Ann ClarkPublisher:OpenStax
Anatomy & PhysiologyBiologyISBN:9781259398629Author:McKinley, Michael P., O'loughlin, Valerie Dean, Bidle, Theresa StouterPublisher:Mcgraw Hill Education,
Molecular Biology of the Cell (Sixth Edition)BiologyISBN:9780815344322Author:Bruce Alberts, Alexander D. Johnson, Julian Lewis, David Morgan, Martin Raff, Keith Roberts, Peter WalterPublisher:W. W. Norton & Company
Laboratory Manual For Human Anatomy & PhysiologyBiologyISBN:9781260159363Author:Martin, Terry R., Prentice-craver, CynthiaPublisher:McGraw-Hill Publishing Co.
Inquiry Into Life (16th Edition)BiologyISBN:9781260231700Author:Sylvia S. Mader, Michael WindelspechtPublisher:McGraw Hill Education
Human Anatomy & Physiology (11th Edition)
Biology
ISBN:9780134580999
Author:Elaine N. Marieb, Katja N. Hoehn
Publisher:PEARSON
Biology 2e
Biology
ISBN:9781947172517
Author:Matthew Douglas, Jung Choi, Mary Ann Clark
Publisher:OpenStax
Anatomy & Physiology
Biology
ISBN:9781259398629
Author:McKinley, Michael P., O'loughlin, Valerie Dean, Bidle, Theresa Stouter
Publisher:Mcgraw Hill Education,
Molecular Biology of the Cell (Sixth Edition)
Biology
ISBN:9780815344322
Author:Bruce Alberts, Alexander D. Johnson, Julian Lewis, David Morgan, Martin Raff, Keith Roberts, Peter Walter
Publisher:W. W. Norton & Company
Laboratory Manual For Human Anatomy & Physiology
Biology
ISBN:9781260159363
Author:Martin, Terry R., Prentice-craver, Cynthia
Publisher:McGraw-Hill Publishing Co.
Inquiry Into Life (16th Edition)
Biology
ISBN:9781260231700
Author:Sylvia S. Mader, Michael Windelspecht
Publisher:McGraw Hill Education
Genetic Variation and Mutation | 9-1 GCSE Science Biology | OCR, AQA, Edexcel; Author: SnapRevise;https://www.youtube.com/watch?v=bLP8udGGfHU;License: Standard YouTube License, CC-BY