For motion 2, draw vectors in region II of the enlargement that represent the initial and the final momentum of the ball. Draw these vectors using the same scale that you need for motion I (i.e., the relative lengths should represent the relative magnitudes). Use these vectors to construct the change in momentum vector
How should the direction
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- Use vectors to solve the following problems. Both cars weigh 1500 kg. Use the scale 1 cm = 1,000 kg x m/s. Assume all collisions to be sticking. Draw a picture represents the problem too. The first car is travelling at 20 m/s east. The second car is travelling at 30m/s north. Using vectors draw to scale the component vectors and the resultant from their collision. Then solve using your trigonometric functions. Also: use Pythagorean Theorem (to find magnitude/resultant), inversed tangent (to find direction/angle) because vectors = magnitude & direction, and use formula: momentum = mv(before) = mv(after)arrow_forwardPlease only Part A and C; thank you! A ball of mass 0.472 kg moving east (+x direction) with a speed of 3.80 m/sm/s collides head-on with a 0.236 kg ball at rest. Assume that the collision is perfectly elastic. Part A What is be the speed of the 0.472-kg ball after the collision? Express your answer to three significant figures and include the appropriate units. v1=_____________ Part C What is the speed of the 0.236-kg ball after the collision? Express your answer to three significant figures and include the appropriate units. v2=____________ Note: The direction of velocity of both v1 and v2 is to the east.arrow_forwardtwo identical carts (750 g each) move along a frictionless track. One moves to the right at 1.2 m/s, the other to the left at 0.9 m/s. What is the momentum (in kg m/s) of the first cart (moving to the right)? (Assume right is the positive direction). B. What is the total momentum (in kg m/s) of the two cart system in the previous problem? (Right is positive)? C. If the carts collide and stick together, what is their final speed (in m/s)? (Remember: right is positive for this problem)arrow_forward
- The 5.8-Mg bus B is traveling to the right at vB = 20 m/s. Meanwhile a 2-Mg car A is traveling at VA = 12 m/s to the right. the Vehicles crash and become entangled. Assume that the vehicles are free to roll during collision. (Figure 1) Figure 1 of 1 Part A Determine their common velocity just after the collision. Express your answer to three significant figures and include the appropriate units. V = 0 Submit Value μÀ Provide Feedback Request Answer Unitsarrow_forwardA firework explodes into three pieces as shown in the diagram below. Now that you have set up the equation for the x and y components of the final momentum of the firework, let's do some physics! Given: ∙∙ The initial firework had a mass of 9.0 kg and was launched at vi = 50 m/s vertically straight up. ∙∙ The firework explodes into three pieces of equal mass 3.0 kg. The angles θ1 = θ3 = 40 ∘. ∙∙ Speed v1 = 100 m/s. What is the speed v2? Note: the angles shown for mass m1 and mass m3 are relative to the horizontal x-axis. Mass m2 is moving straight up (y-axis).arrow_forwardThree objects A, B, and C are moving as shown in (Figure 1). Assume that Va = 10.6 m/s , Vb = 10.0 m/s, and Vc = 4.00 m/s. Find the x component of the net momentum of the particles if we define the system to consist of A and C. Find the y component of the net momentum of the particles if we define the system to consist of A and C. Find the x component of the net momentum of the particles if we define the system to consist of B and C. Find the y component of the net momentum of the particles if we define the system to consist of B and C. Find the x component of the net momentum of the particles if we define the system to consist of all three objects. Find the y component of the net momentum of the particles if we define the system to consist of all three objects.arrow_forward
- In order to answer this question, follow the steps provided and remember that the total initial momentum of the system must equal the total final momentum. Also, remember that momentum and velocity are vector quantities so you must specify a negative sign if the motion is to the left. A green truck of mass 2500 kg travels to the right with a velocity vig = 3.7 m/s. The green truck approaches a red truck with mass 1460 kg that is traveling to the left with a velocity of vir = -3 m/s. The trucks collide and stick together after the collision. What is the final velocity, vf of the green-red truck system after the collision. (look at the figure/picture)(a) What was the initial momentum of the green truck before the collision?pgi = 9250 kg m/s(b) What was the initial momentum of the red truck before the collision?pri = -4380 kg m/s(c) What was the total initial momentum of the system of trucks?pTf = 4870 kg m/s (d) What must be the total final momentum of the system after the collision if…arrow_forwardThree objects AA, BB, and CC are moving as shown in the figure below (Figure 1). Assume that vAvAv_A = 12.0 m/sm/s, vBvBv_B = 9.6 m/sm/s, and vCvCv_C = 2.8 m/sm/s. a) Find the xx-component of the net momentum of the particles if we define the system to consist of BB and CC. Express your answer in kilogram meters per second. b) Find the xx-component of the net momentum of the particles if we define the system to consist of all three objects. Express your answer in kilogram meters per second. both answers are not zero, tried that its wrong.arrow_forwardV; h M m n the diagram above, a block of mass M is initially at rest on a horizontal surface at the base of an inclined plane. The surface and plane have negligible friction. The block is struck by a projectile of mass m traveling with a horizontal velocity v, . The projectile becomes embedded in the alock, and they move together to the right with speed v . Which of the following is a correct expression for vf ? A gh +2gh (m+M) D Marrow_forward
- Three objects A, B, and C are moving as shown in the figure below (Figure 1). Assume that A = 11.0 m/s, vB = 9.2 m/s, and vc = 4.0 m/s. Figure 5.0 kg B60° Vc. HA 6.0 kg 10.0 kg 1 of 1 > Find the x-component of the net momentum of the particles if we define the system to consist of A and C. Express your answer in kilogram meters per second. [ΠΙ ΑΣΦ ? Px = kg. m/s Submit Previous Answers Request Answer X Incorrect; Try Again; 4 attempts remaining Part B Find the y-component of the net momentum of the particles if we define the system to consist of A and C. Express your answer in kilogram meters per second. OF [Π ΑΣΦ kg. m/s Request Answer Part C Find the x-component of the net momentum of the particles if we define the system to consist of B and C. Express your answer in kilogram meters per second. IVE ΑΣΦ ? kg. m/s Py = Submit Px =arrow_forwardA billiard player took his shot on a tournament game moving the cue ball at a speed of 3.5 m/s and makes a glancing collision with the target ball. After collision, the cue ball moves off at an angle of theta = 37.0 deg relative to the original direction of its motion and the target ball deflects at an angle of phi to the same axis but opposite direction. 1. Find the final speeds of the two billiard balls. a. 1.09 m/s b. 2.11 m/s c. 3.2 m/s d. 3.9 m/s 2. Calculate for the the angle phi. a. 37 deg b. 41 deg c. 53 deg d. 60 degarrow_forwardThe speed of the fastest-pitched baseball was 45.0 m/s, and the ball's mass was 145 g. You may want to review (Page) For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of Preliminary analysis of a collision. ▾ Part A What was the magnitude of the momentum of this ball? p= Submit ▾ Part B K= How many joules of kinetic energy did this ball have? Templates Symbols undo redo Teset keyboard shortcuts Help M ▾ Part C Submit U= Request Answer ▾ Part D Templates Symbols undo redo M Submit Request Answer dan tak How fast would a 56.0 gram ball have to travel to have the same amount of kinetic energy? feset keyboard shortcuts Help > 4 Templates Symbols undo rego Teset keyboard shortcuts Help M .. Request Answer kg-m/s Templates Symbols undo' rego Peser keyboard shortcuts Help J ongon How fast would a 56.0 gram ball have to travel to have the same amount of momentum? m/s m la Review | Constantsarrow_forward
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