Concept explainers
The angular spread of visible light passing through a prism.
Answer to Problem 35.39P
The angular spread of visible light passing through a prism is
Explanation of Solution
Given info: The index of refraction for violet light in silica flint glass is
The figure of light ray passing through the prism is shown as below,
The expression of the Snell’s law is,
Here,
For the red color:
Consider the angle of refraction on the first face of the prism is
Substitute
Thus, the angle of refraction on the first face of the prism is
The angle of incidence on the second face of the prism is,
Here,
Substitute
Consider the angle of refraction on the second face of the prism is
Substitute
Thus, the angle of refraction on the second face of the prism is
The angle of deviation is,
Here,
Substitute
Thus, the angle of deviation for red color is
For the violet color:
Consider the angle of refraction on the first face of the prism is
Substitute
Thus, the angle of refraction on the first face of the prism is
The angle of incidence on the second face of the prism is,
Substitute
Consider the angle of refraction on the second face of the prism is
Substitute
Thus, the angle of refraction on the second face of the prism is
The angle of deviation is,
Substitute
Thus, the angle of deviation for violet color is
The angular spread of visible light passing through a prism is,
Substitute
Conclusion:
Therefore, the angular spread of visible light passing through a prism is
Want to see more full solutions like this?
Chapter 35 Solutions
Physics for Scientists and Engineers
- Light is incident on a prism as shown in Figure P38.31. The prism, an equilateral triangle, is made of plastic with an index of refraction of 1.46 for red light and 1.49 for blue light. Assume the apex angle of the prism is 60.00. a. Sketch the approximate paths of the rays for red and blue light as they travel through and then exit the prism. b. Determine the measure of dispersion, the angle between the red and blue rays that exit the prism. Figure P38.31arrow_forwardFigure P23.28 shows a curved surface separating a material with index of refraction n1 from a material with index n2. The surface forms an image I of object O. The ray shown in red passes through the surface along a radial line. Its angles of incidence and refraction are both zero, so its direction does not change at the surface. For the ray shown in blue, the direction changes according to n1 sin 1 = n2 sin 2. For paraxial rays, we assume 1 and 2 are small, so we may write n1 tan 1 n2 tan 2. The magnification is defined as M = h/h. Prove that the magnification is given by M = n1q/n2p. Figure P23.28arrow_forwardA light ray is incident on an interface between water (n = 1.333) and air (n = 1.0002926) from within the air. If the angle of incidence in the air is 30.0, what is the angle of the refracted ray in the water?arrow_forward
- Figure P23.28 shows a curved surface separating a material with index of refraction n1 from a material with index n2. The surface forms an image I of object O. The ray shown in red passes through the surface along a radial line. Its angles of incidence and refraction are both zero, so its direction does not change at the surface. For the ray shown in blue, the direction changes according to n1 sin 1 = n2 sin 2. For paraxial rays, we assume 1 and 2 are small, so we may write n1 tan 1 n2 tan 2. The magnification is defined as M = h/h. Prove that the magnification is given by M = n1q/n2p. Figure P23.28arrow_forwardConsider a beam of light from the left entering a prism of apex angle as shown in Figure P34.34. Two angles of incidence, 1, and 3, are shown as Hell as two angles of refraction, 2 and 4. Show that = 1 + 3. Figure P34.34arrow_forward
- Physics for Scientists and Engineers, Technology ...PhysicsISBN:9781305116399Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningPrinciples of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningPhysics for Scientists and Engineers with Modern ...PhysicsISBN:9781337553292Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
- Physics for Scientists and EngineersPhysicsISBN:9781337553278Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningPhysics for Scientists and Engineers: Foundations...PhysicsISBN:9781133939146Author:Katz, Debora M.Publisher:Cengage LearningCollege PhysicsPhysicsISBN:9781305952300Author:Raymond A. Serway, Chris VuillePublisher:Cengage Learning