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Technetium-99
a. At noon, the patient is given 10 mCi (millicuries) of
b. At what time will the level of radioactivity reach 3 mCi? Round to the nearest tenth of an hour.
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Precalculus
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- 1. Can balloons hold more air or more water before bursting? A student purchased a large bag of 12-inch balloons. He randomly selected 10 balloons from the bag and then randomly assigned half of them to be filled with air until bursting and the other half to be filled with water until bursting. He used devices to measure the amount of air and water was dispensed until the balloons burst. Here's the data: Air (ft') Water (ft) 0.52 0.44 0.58 0.41 0.50 0.55 0.46 0.61 0.38 0.45 Does the data give convincing evidence air filled balloons can attain a greater volume than water filled balloons?arrow_forwardGiven : The blue catfish is the largest species of North American catfish. The current world record stands at 143 pounds. According to American Expedition, the average weight of a blue catfish is between 20 to 40 pounds. Also, the largest blue catfish ever caught was at the John H. Kerr Reservoir, you believe that the mean weight of the fish in this reservoir is greater than 40 pounds. A 50 blue catfish caught at this reservoir. n = 50 α = 0 . 05 α = 0 . 05 x = 40 . 35 p o u n d s x = 40 . 35 p o u n d s s = 2 . 8 p o u n d sarrow_forwardThe concentration of carbon dioxide (CO2) in the atmosphere is increasing rapidly due to our use of fossil fuels. Because plants use CO2 to fuel photosynthesis, more CO2 may cause trees and other plants to grow faster. An elaborate apparatus allows researchers to pipe extra CO2 to a 30-meter circle of forest. They selected two nearby circles in each of three parts of a pine forest and randomly chose one of each pair to receive extra CO2. The response variable is the mean increase in base area for 30 to 40 trees in a circle during a growing season. We measure this in percent increase per year. Here are one year's data. Pair Control plot Treated plot Treated - Control 9.782 10.647 0.865 2 7.283 9.254 1.971 3 5.712 8.695 2.983 (a) State the null and alternative hypotheses. (Where u is the mean difference, treated minus control.) Но: и На: и ? : Explain clearly why the investigators used a one-sided alternative. The researchers have no preconceived idea what extra CO2 will do to the growth…arrow_forward
- Exhibit 9-5 n = 16 HO: u z 80 x = 75.607 Ha: µ < 80 o = 8.246 Assume the population is normally distributed. 4. Refer to Exhibit 9-5. The p-value is equal to .0332 .9834 -.0166 .0166arrow_forward(a) A certain type of hummingbird is known to have an average weight of 4.55 grams. A researcher wonders if hummingbirds (of this same type) living in the Grand Canyon differ in weight from the population as a whole. The researcher finds a sample of 30 such hummingbirds from the Grand Canyon and calculates their average weight to be 3.75 grams. Ο Α. H : μ = 4.55, Ο B. H : μ 3.75 D. Ho = 4.55, H₁ 4.55 OE. Ho = 4.55, H 115 OB. Ho = 118.2, Ha 118.2 Ο C. H : μ = 118.2, H@ :μ 115 OE. Ho = 115, H₁115 F. Ho = 115, H₂ 69 Ο C. H : μ = 71, H@ :μ 69, Ha : μ 69arrow_forward
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