Explanation Given information: The equation: 1 3 x 3 + 1 2 x 2 + 3 = 0 , x 1 = − 3 Calculation: The Newton’s method is x n + 1 = x n − f ( x ) f ' ( x ) with x 1 = − 3 We have − 3.0000 , − 2.7500 , − 2.7186 f ( x ) = 1 3 x 3 + 1 2 x 2 + 3 f ' ( x ) = x 2 + x

15th Edition

ISBN: 9781133109631

Author: Stewart, JAMES, Day, Troy

Publisher: Cengage Learning,

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Chapter 3.8, Problem 22E

To determine

To find: Use Newton’s method with the specific initial approximation x1 and x3, the third approximation to the root of the given equation. (Give your answer to four decimal places.)

13x3+12x2+3=0, x1=−3

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Chapter 3.8, Problem 21E

Chapter 3.8, Problem 23E

Chapter 3 Solutions

Biocalculus

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Use Newton’s method with the specific initial approximation x 1 and x 3 , the third approximation to the root of the given equation. (Give your answer to four decimal places.) 1 3 x 3 + 1 2 x 2 + 3 = 0 , x 1 = − 3

Solution Summary: The author explains how Newton's method is used to find the root of the given equation.

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To find: Use Newton’s method with the specific initial approximation x1 and x3, the third approximation to the root of the given equation. (Give your answer to four decimal places.)

13x3+12x2+3=0, x1=−3

Want to see the full answer?

Chapter 3 Solutions

Use Newton’s method with the specific initial approximation x 1 and x 3 , the third approximation to the root of the given equation. (Give your answer to four decimal places.) 1 3 x 3 + 1 2 x 2 + 3 = 0 , x 1 = − 3

Solution Summary: The author explains how Newton's method is used to find the root of the given equation.

Concept explainers

Videos

To find: Use Newton’s method with the specific initial approximation x1 and x3, the third approximation to the root of the given equation. (Give your answer to four decimal places.) 13x3+12x2+3=0, x1=−3

Want to see the full answer?

Chapter 3 Solutions

To find: Use Newton’s method with the specific initial approximation x1 and x3, the third approximation to the root of the given equation. (Give your answer to four decimal places.)

13x3+12x2+3=0, x1=−3