(a)
Interpretation:
The molarity of 25.00 mL solution of iron(III) nitrate should be determined which reacts with 12.54 mL of 0.1488 M sodium carbonate.
Concept introduction:
Number of moles is equal to the ratio of given mass to the molar mass.
The mathematical expression is given by:
Number of moles =
Molarity is defined as the ratio of number of moles of solute to the volume of the solution in liters.
The mathematical expression is given by:
Molarity =
A solution of salt of metal when reacts with other solution to give products, the formula which is used to find the volume of either solution is given by:
Where, M1 and M2 are molarity of the solution
V1 and V2 are volume of the solution
(b)
Interpretation:
The molarity of 25.00 mL solution of iron(III) nitrate should be determined which reacts with 7.58 g of potassium phosphate.
Concept introduction:
Number of moles is equal to the ratio of given mass to the molar mass.
The mathematical expression is given by:
Number of moles =
Molarity is defined as the ratio of number of moles of solute to the volume of the solution in liters.
The mathematical expression is given by:
Molarity =
A solution of salt of metal when reacts with other solution to give products, the formula which is used to find the volume of either solution is given by:
Where, M1 and M2 are molarity of the solution
V1 and V2 are volume of the solution
(c)
Interpretation:
The molarity of 25.00 mL solution of iron(III) nitrate should be determined which reacts with 10.00 mL of 0.1573 M
Concept introduction:
Number of moles is equal to the ratio of given mass to the molar mass.
The mathematical expression is given by:
Number of moles =
Molarity is defined as the ratio of number of moles of solute to the volume of the solution in liters.
The mathematical expression is given by:
Molarity =
A solution of salt of metal when reacts with other solution to give products, the formula which is used to find the volume of either solution is given by:
Where, M1 and M2 are molarity of the solution
V1 and V2 are volume of the solution
Trending nowThis is a popular solution!
Chapter 4 Solutions
Chemistry: Principles and Reactions
- A soluble iodide was dissolved in water. Then an excess of silver nitrate, AgNO3, was added to precipitate all of the iodide ion as silver iodide, AgI. If 1.545 g of the soluble iodide gave 2.185 g of silver iodide, how many grams of iodine are in the sample of soluble iodide? What is the mass percentage of iodine, I, in the compound?arrow_forwardWhen 10. L of water is added to 3.0 L of 6.0 M H2SO4, what is the molarity of the resulting solution? Assume the volumes are additive.arrow_forwardA 1.345-g sample of a compound of barium and oxygen was dissolved in hydrochloric acid to give a solution of barium ion, which was then precipitated with an excess of potassium chromate to give 2.012 g of barium chromate, BaCrO4. What is the formula of the compound?arrow_forward
- Twenty-five mL of a 0.388 M solution of Na2SO4 is mixed with 35.3 mL of 0.229 M Na2SO4. What is the molarity of the resulting solution? Assume that the volumes are additive.arrow_forwardWhat is the molarity of a solution of sodium hydrogen sulfate that is prepared by dissolving 9.21 g NaHSO4 in enough water to form 2.00-L solution? What is the molarity of each ion in the solution?arrow_forwardWrite a balanced equation for the reaction of hydroiodic acid, HI, with calcium hydroxide, Ca(OH)2. Then, write the balanced complete ionic equation and the net ionic equation for this neutralization reaction.arrow_forward
- An antacid tablet has calcium carbonate as the active ingredient; other ingredients include a starch binder. You dissolve the tablet in hydrochloric acid and filter off insoluble material. You add potassium oxalate to the filtrate (containing calcium ion) to precipitate calcium oxalate. If a tablet weighing 0.750 g gave 0.629 g of calcium oxalate, what is the mass percentage of active ingredient in the tablet?arrow_forwardDetermine the volume of sulfuric acid solution needed to prepare 37.4 g of aluminum sulfate, Al2(SO4)3, by the reaction 2Al(s)+3H2SO4(aq)Al2(SO4)3(aq)+3H2(g) The sulfuric acid solution, whose density is 1.104 g/mL, contains 15.0% H2SO4 by mass.arrow_forwardDetermine the volume of sodium hydroxide solution needed to prepare 26.2 g sodium phosphate, Na3PO4, by the reaction 3NaOH(aq)+H3PO4(aq)Na3PO4(aq)+3H2O(l) The sodium hydroxide solution, whose density is 1.133 g/mL, contains 12.0% NaOH by mass.arrow_forward
- Chemistry: Principles and PracticeChemistryISBN:9780534420123Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward MercerPublisher:Cengage LearningChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningGeneral Chemistry - Standalone book (MindTap Cour...ChemistryISBN:9781305580343Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; DarrellPublisher:Cengage Learning
- Chemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage LearningIntroductory Chemistry: A FoundationChemistryISBN:9781337399425Author:Steven S. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistry for Engineering StudentsChemistryISBN:9781337398909Author:Lawrence S. Brown, Tom HolmePublisher:Cengage Learning