Horizons: Exploring the Universe (MindTap Course List)
14th Edition
ISBN: 9781305960961
Author: Michael A. Seeds, Dana Backman
Publisher: Cengage Learning
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Textbook Question
Chapter 4, Problem 4P
If a planet had an average distance from the Sun of 10 AU, what would its orbital period be?
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Chapter 4 Solutions
Horizons: Exploring the Universe (MindTap Course List)
Ch. 4 - Why did Greek astronomers conclude that the...Ch. 4 - Why did classical astronomers conclude that Earth...Ch. 4 - How did the Ptolemaic model explain retrograde...Ch. 4 - In what ways were the models of Ptolemy and...Ch. 4 - Why did the Copernican hypothesis win gradual...Ch. 4 - Why is it difficult for scientists to replace an...Ch. 4 - Why did Tycho Brahe expect the new star of 1572 to...Ch. 4 - How was Tycho’s model of the Universe similar to...Ch. 4 - Explain how Kapler’s lows contradict uniform...Ch. 4 - What is the difference between a hypothesis ,...
Ch. 4 - How did The Alfonsine Tables, The Prutenic Tables,...Ch. 4 - Review Galileo’s telescopic discoveries and...Ch. 4 - Galileo was condemned by the Inquisition, but...Ch. 4 - How do Newton’s laws lead you to conclude that...Ch. 4 - Explain why you might describe the orbital motion...Ch. 4 - Prob. 16RQCh. 4 - How Do We know? How would you respond to someone...Ch. 4 - Prob. 18RQCh. 4 - How Do We Know? Why is it important that a...Ch. 4 - Science historian Thomas Kuhn has said that De...Ch. 4 - Many historians suspect that Galileo offended Pope...Ch. 4 - Prob. 3DQCh. 4 - If you lived on Mars, which planets would describe...Ch. 4 - Galileo’s telescope showed him that Venus has a...Ch. 4 - Galileo’s telescopes were not of high quality by...Ch. 4 - If a planet had an average distance from the Sun...Ch. 4 - If a space probe were sent into an orbit around...Ch. 4 - Neptune orbits the Sun with a period of 164.8...Ch. 4 - Venus’s average distance from the Sun is 0.72 AU...Ch. 4 - The circular velocity of Earth around the Sun is...Ch. 4 - What is the orbital velocity of an Earth satellite...Ch. 4 - Prob. 1LTLCh. 4 - Prob. 2LTLCh. 4 - Why is it a little bit misleading to say that this...Ch. 4 - Prob. 4LTLCh. 4 - Mercury’s orbit hardly deviates from a circle, but...
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- What is the average distance from the Sun (in astronomical units) of a planet with an orbital period of 45.66 years?arrow_forwardComet Halley (Fig. P11.21) approaches the Sun to within 0.570 AU, and its orbital period is 75.6 yr. (AU is the symbol for astronomical unit, where 1 AU = 1.50 1011 m is the mean EarthSun distance.) How far from the Sun will Halleys comet travel before it starts its return journey?arrow_forwardWhat is the period of an object orbiting the Sun at 1.524 AU?arrow_forward
- What would be the period of an object orbiting the sun with a semimajor axis of 15AU?arrow_forwardIf a fictitious planet has an average distance from the sun of 2.0 AU what is its orbital periodarrow_forwardThe average distance between Mars and the Sun is 1.52 AU. What is the orbital period of Mars? Provide you answer in time units of years.arrow_forward
- If you find a planet's orbital period around the Sun to be ~15 years, what would be its approximate semimajor axis to the nearest AU?arrow_forwardA comet (see the figure below) approaches the Sun to within 0.570 AU, and its orbital period is 79.6 yr. (AU is the symbol for astronomical unit, where 1 AU = 1.50 x 1011 m is the mean Earth-Sun distance.) How far from the Sun will the comet travel before it starts its return journey?arrow_forwardThe planet Earth has a semi-major axis of a = 1.00 AU and an orbital period of P= 1 sidereal year = 365.25 days = 3.156 x 10^7 s. Compute the orbital periods of bodies orbiting the Sun with each of the following semi-major axes. a) a = 0.1 AU b) a = 10 AU c) a = 100 AU d) a = 1000 AU e) a = 10,000 AU 1 AU = 1.496 x 10^8 km = 1.496 x 10^11 m = 1.496 x 10^13 cm. GM(sun) = 1.327 x 10^20 m^3/s^2 = (Newton's Constant) x (Mass of Sun) %3D %3Darrow_forward
- A superior planet is having a sidereal period of 1.6 years. Calculate the synodic period?arrow_forwardDetermine what the period of revolution of the Earth would be if its distance from the Sun were 3.5 AU rather than 1 AU. Assume that the mass of the Sun remains the same. The final unit should be y in the answer.arrow_forwardSaturn has an angular size of 16”, and an observed Synodic Period of 1.035yrs. Saturn’s moon, Titan orbits the planet with an angular separation of 192”, with a period of 15.9days. From these observations we can determine Saturn’s mass. Use the Sidereal Period of Saturn above to find the distance to Saturn from the Sun.arrow_forward
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