What is the output of the following code segment?
Write(“Red”);
else
Write(“Orange”);Â
a. Red
b. Orange
c. RedOrange
d. nothing
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Microsoft Visual C#
- What does the following code segment display? for(f=0; f<3; ++f); write ("{0} ", f); a. 0 b. nothing c. 3 d. 0 1 2arrow_forwardnum1 = int(input("Enter first value:"))num2 = int(input("Enter second value:"))num3 = int(input("Enter third value:")) # Type your code after this line. if (num1 >= num2) and (num1 >= num3):print("Enter first value:" "Enter second value:" "Enter third value:" 'Largest value is:' , num1 )elif (num2 >= num1) and (num2 >= num3):print("Enter first value:" "Enter second value:" "Enter third value:" 'Largest value is:' , num2 )elif (num3 >= num1) and (num3 >= num2):print("Enter first value:" "Enter second value:" "Enter third value:" 'Largest value is:' , num3 ) What is wrong with thisarrow_forward7. How would you declare a variable storing a person's name? String name = Jeff; String name = "Jeff"; name String = "Jeff"; string name = "Jeff"; 8. These characters mark the beginning of a single-line comment. /** // /*/ */ 9. Variable names can't start with a number. True Falsearrow_forward
- num1 = int(input("Enter first value:"))num2 = int(input("Enter second value:"))num3 = int(input("Enter third value:")) # Type your code after this line. if (num1>=num2)and(num1>=num3):print("Enter first value:" "Enter second value:" "Enter third value:" 'Largest value is:' , num1)elif (num2>=num1) and (num2>=num3):print("Enter first value:" "Enter second value:" "Enter third value:" 'Largest value is:' , num2) else:print("Enter first value:" "Enter second value:" "Enter third value:" 'Largest value is:' , num3) When i run it, it states enter first value, enter second value, and enter third value, twicearrow_forwardPrint "user_num1 is negative." if user_num1 is less than 0. End with newline. Assign user_num2 with 1 if user_num2 is greater than 12. Otherwise, print "user_num2 is less than or equal to 12.". End with newline. My code: user_num1 = int(input())user_num2 = int(input()) if user_num1 < 0: print("user_num1 is negative.") if user_num2 > 12: user_num2 == 1 else: print("user_num2 is less than or equal to 12.") print('user_num2 is', user_num2) When the input is 0 and 13 my output for user_num2 is 13 and it should be 1. I don't know what I'm doing wrong.arrow_forwardchar letter1; char letter2; letter1 = 'y'; while (letter1 <= 'z') { letter2 = 'a'; while (letter2 <= 'c'){ System.out.print("" + letter1 + letter2 + " "); ++letter2; } ++letter1; } For this code why did we use "" before and after in this line? System.out.print("" + letter1 + letter2 + " "); ++letter2; What if we don't use the blank quotation would the output be same? because I don't see the reason for putting those quotation mark.arrow_forward
- o assign a double variable d to an int variable x, you write ____. x = d; x = (double) d; x = (int) d; d = x;arrow_forwardAssume that an int variable age has been declared and already given a value. Assume further that the user has just been presented with the following menu: • S: hangar steak, red potatoes, asparagus T: whole trout, long rice, brussel sprouts • B: cheddar cheeseburger, steak fries, cole slaw (Yes, this menu really IS a menu!) Write some code that reads the String (S or T or B) that the user types in into a String variable choice that has already been declared and prints out a recommended accompanying drink as follows: if the value of age is 21 or lower, the recommendation is "vegetable juice" for steak, "cranberry juice" for trout, and "soda" for the burger. Otherwise, the recommendations are "cabernet", "chardonnay", and "IPA" for steak, trout, and burger respectively. Regardless of the value of age, your code should print "invalid menu selection" if the character read into choice was not S or T or B. ASSUME the availability of a variable, stdin, that references a Scanner object…arrow_forwardGiven the following declaration: int x; int* p; Which of the following expressions is allowed? Select one: a. p = x; b. p = &x; %3D C. p = *x; d. x = p;arrow_forward
- What is the final value of y? int x = 4; 6; int y if (x < 10) { if (y < 5) { y = y + 1; } } else { } y = 7; } else { y = y + 10;arrow_forwardWhat is the value of x after the following code executes? int x=10; if(x++ >10) { x =13; } a. 10 b.9 c.13 d.11arrow_forwardComment these two codes def volumeFormula(radius, høyde): PI = 3.14 Volume = PI * radius ** 2 * høyde return Volume height = int(input("height= ")) radius = int(input("radius = ")) if høyde < 0 or radius < 0: print("Please input vaild number") else: volume_print = volumeFormula(radius, høyde) print("The volume of cylinder is :" + str(volume_print) + "cm^3") input() radius = float(input('Number:\n')) pi = 3.14 volume = (4 * pi * radius**3)/3 print('Volume is %.2f' % volume)arrow_forward
- Microsoft Visual C#Computer ScienceISBN:9781337102100Author:Joyce, Farrell.Publisher:Cengage Learning,