Modern Physics for Scientists and Engineers
4th Edition
ISBN: 9781133103721
Author: Stephen T. Thornton, Andrew Rex
Publisher: Cengage Learning
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Question
Chapter 4, Problem 9P
(a)
To determine
The number of alpha particles that will be scattered at angle greater than 90°
(b)
To determine
The alpha particles that will be scattered between 70° and 80°
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1. In an experiment done by scattering 7.7-MeV a particles from a thin gold foil, experimenters find that 5,000
a particles are scattered at an angle greater than 50°. (a) How many of these a particles will be scattered at
an angle greater than 90°? (b) How many will be scattered between 70° and 80°?
Alpha particles of kinetic energy 5.4 MeV are incident at a rate of 3.2 x 107 per second on a copper foil of thickness 3.2 x 10-6 m. A circular detector of diameter 1.0 cm is placed 13 cm
from the foil at an angle of 30° with the direction of the incident alpha particles. At what rate does the detector measure scattered alpha particles? (The molar mass of copper is
63.5 g/mol and its density is 8.9 g/cm³.)
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A 20 MeV alpha particle is fired toward a 238U nucleus. It follows the path as shown. What is the alpha particle’s speed when it is closest to the nucleus, 20 fm from its center? Assume that the nucleus doesn’t move.
Chapter 4 Solutions
Modern Physics for Scientists and Engineers
Ch. 4 - Prob. 1QCh. 4 - Prob. 2QCh. 4 - Prob. 3QCh. 4 - Prob. 4QCh. 4 - Prob. 5QCh. 4 - Prob. 6QCh. 4 - Prob. 7QCh. 4 - Prob. 8QCh. 4 - Prob. 9QCh. 4 - Prob. 10Q
Ch. 4 - Prob. 11QCh. 4 - Prob. 12QCh. 4 - Prob. 13QCh. 4 - Prob. 2PCh. 4 - Prob. 3PCh. 4 - Prob. 4PCh. 4 - Prob. 5PCh. 4 - Prob. 6PCh. 4 - Prob. 7PCh. 4 - What fraction of 5-MeV α particles will be...Ch. 4 - Prob. 9PCh. 4 - Prob. 10PCh. 4 - Prob. 11PCh. 4 - Prob. 12PCh. 4 - Prob. 13PCh. 4 - Prob. 14PCh. 4 - Prob. 15PCh. 4 - Prob. 16PCh. 4 - Prob. 17PCh. 4 - Prob. 18PCh. 4 - Prob. 19PCh. 4 - Prob. 20PCh. 4 - Prob. 21PCh. 4 - Prob. 22PCh. 4 - Prob. 23PCh. 4 - Prob. 24PCh. 4 - Prob. 25PCh. 4 - Prob. 26PCh. 4 - Prob. 27PCh. 4 - Prob. 28PCh. 4 - Prob. 29PCh. 4 - Prob. 30PCh. 4 - Prob. 31PCh. 4 - Prob. 32PCh. 4 - Prob. 33PCh. 4 - Prob. 34PCh. 4 - Prob. 35PCh. 4 - Prob. 36PCh. 4 - Prob. 37PCh. 4 - Prob. 38PCh. 4 - Prob. 39PCh. 4 - Prob. 40PCh. 4 - Prob. 41PCh. 4 - Prob. 42PCh. 4 - Prob. 43PCh. 4 - Prob. 44PCh. 4 - Prob. 45PCh. 4 - Prob. 46PCh. 4 - Prob. 47PCh. 4 - Prob. 48PCh. 4 - Prob. 49PCh. 4 - Prob. 50PCh. 4 - Prob. 51PCh. 4 - Prob. 52PCh. 4 - Prob. 54PCh. 4 - Prob. 55PCh. 4 - Prob. 56PCh. 4 - Prob. 57PCh. 4 - Prob. 59PCh. 4 - Prob. 60PCh. 4 - Prob. 61P
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- When an alpha particle collides elastically with a nucleus, the nucleus recoils. Suppose a 6.00 MeV alpha particle has a head-on elastic collision with a silver-108 nucleus that is initially at rest. (a) What is the kinetic energy of the recoiling nucleus? MeV (b) What is the kinetic energy of the rebounding alpha particle? MeVarrow_forwardThe speed of the alpha particles in Rutherford experiment was 0.01c, the scattering material was gold. What was the impact parameter of the alpha particle scattered by 60°?arrow_forwardIn a scattering experiment, you concentrate on Alpha particles with impact parameters b=0, 1×10^-3, and 1×10^0 mm. For which b will the behavior of the Alpha particle be very different in Thomson's and Rutherford's models and for which will it be nearly similar?arrow_forward
- J 5 Question 2 (1) Assume that the average energy of β-rays (electrons) emitted from the S-ray source is 0.8 MeV, and the average ionization energy of gas molecules (atoms) in the GM counter tube is about 30 eV. Find the number of gas molecules ionized when one electron enters the GM tube (1MeV = 10°eV). (2) Assuming that the electrons and cations thus generated are attracted to the electrode as they are, what is the total amount of negative charge generated by ionization in C (coulombs)? (3) If this ionization takes 10-4s, what is the current flowing through the anode?arrow_forwardHow much energy is imparted to one cell during one day’s treatment? Assume that the specific gravity of the tumor is 1 and that 1 J = 6 * 1018 eV. (a) 120 keV; (b) 12 MeV; (c) 120 MeV; (d) 120 * 103 MeV.arrow_forwardIn the experiment, alpha particles follow a hyperbolic trajectory. The figure shows an alpha particle A initially approaching a gold nucleus N and being deflected at an angle 0 = 90°. N is located at a focus of the hyperbola, and the trajectory of A passes through a vertex of the hyperbola. ++► x y = x y =-x a. Determine the equation of the trajectory of the alpha particle if d = 4 x 10 14 m. Choose the correct equation below. O A. X= -. + 16 x 10 - 28 В. X= Vy + 16 ×10-28 OC. D. X= + 4x 10 - 28 X = - 4x 10-28 b. What was the minimum distance between the centers of the alpha particle and the gold nucleus? (Use scientific notation. Round to the nearest tenth as needed.)arrow_forward
- A charged particle with initial kinetic energy of 80.3 keV ionizes an electron in the K shell of a silver atom. The binding energy for K-shell electrons in silver is 25.5 keV. The charged particle has kinetic energy of 43.7 keV after the interaction. What is the kinetic energy of the secondary electron, after it is ejected from the silver atom?arrow_forwardFind the fraction of 7.7-MeV α particles that is deflected at an angle of 90° or more from a gold foil of 10 -6 m thickness.arrow_forward2. The mass attenuation coefficient of copper is 0.0589 cm2/g for 1.0-MeV photons. Find required thickness of the protective copper shield in order to achieve 50 % reduction of X-Ray radiation intensity. The density of copper is 8.9 g/cm3. Kindly the Correct Answer.arrow_forward
- What fraction of 5-MeV - particles will be scattered through angles greater than 8° from a gold foil (Z = 79, density=19.3 g/cm3) of thickness 10-8 m?arrow_forwardAn 8.3 MeV alpha particle is shot directly toward the nucleus of a gold atom (atomic number 79). What is the distance of closest approach of the alpha particle to the nucleus?arrow_forwardA narrow beam of 0.5 MeV photons is incident normally on a 3 mm iron slab. What fraction of the phatons have an interaction in the slab? Mass attenuation coefficient of iron 0.08 cm/g, density of iron =7.87 g/cm O a. 0.828 O b. 0.172 Oc. 0.58 O d. 0.42arrow_forward
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