Physics for Scientists and Engineers
6th Edition
ISBN: 9781429281843
Author: Tipler
Publisher: MAC HIGHER
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter 5, Problem 116P
(a)
To determine
The change in reading on the scale.
(b)
To determine
The magnitude and direction of acceleration of center of mass.
(c)
To determine
The reading of scale when
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
Mass Ma lies on top of mass Mp, as shown. Assume M, > Mạ.
The two blocks are pulled from rest by a massless rope passing
over a pulley. The pulley is accelerated at rate A. Block M, slides
on the table without friction, but there is a constant friction force f
between Ma and M, due to their relative motion. Find the tension
in the rope.
A block of mass m,- 13.4 kg is on a frictionless table to the left of a second block of mass m,- 21.7 kg, attached by a horizontal string (see the figure below).
HINT
F
(a) If a horizontal force of 2.13 x 102 N is exerted on the block m, in the positive x-direction, use the system approach to find the acceleration (in m/s) of the two blocks.
m/s2
(b) What is the tension (in N) in the string connecting the blocks?
N
Need Help? Read It Watch
Bucket A and block Care connected by a cable that passes over drum B. Drum Brotates slowly counterclockwise and the
coefficients of friction at all surfaces are μ, = 0.35 and μ = 0.25. Given, W=104 kg.
ME
Determine the smallest combined mass m of the bucket and its contents for which block C will remain at rest. (Round the final answer
to two decimal places.)
The smallest combined mass m of the bucket and its contents for which block Cwill remain at rest is
kg.
Chapter 5 Solutions
Physics for Scientists and Engineers
Ch. 5 - Prob. 1PCh. 5 - Prob. 2PCh. 5 - Prob. 3PCh. 5 - Prob. 4PCh. 5 - Prob. 5PCh. 5 - Prob. 6PCh. 5 - Prob. 7PCh. 5 - Prob. 8PCh. 5 - Prob. 9PCh. 5 - Prob. 10P
Ch. 5 - Prob. 11PCh. 5 - Prob. 12PCh. 5 - Prob. 13PCh. 5 - Prob. 14PCh. 5 - Prob. 15PCh. 5 - Prob. 16PCh. 5 - Prob. 17PCh. 5 - Prob. 18PCh. 5 - Prob. 19PCh. 5 - Prob. 20PCh. 5 - Prob. 21PCh. 5 - Prob. 22PCh. 5 - Prob. 23PCh. 5 - Prob. 24PCh. 5 - Prob. 25PCh. 5 - Prob. 26PCh. 5 - Prob. 27PCh. 5 - Prob. 28PCh. 5 - Prob. 29PCh. 5 - Prob. 30PCh. 5 - Prob. 31PCh. 5 - Prob. 32PCh. 5 - Prob. 33PCh. 5 - Prob. 34PCh. 5 - Prob. 35PCh. 5 - Prob. 36PCh. 5 - Prob. 37PCh. 5 - Prob. 38PCh. 5 - Prob. 39PCh. 5 - Prob. 40PCh. 5 - Prob. 41PCh. 5 - Prob. 42PCh. 5 - Prob. 43PCh. 5 - Prob. 44PCh. 5 - Prob. 45PCh. 5 - Prob. 46PCh. 5 - Prob. 47PCh. 5 - Prob. 48PCh. 5 - Prob. 49PCh. 5 - Prob. 50PCh. 5 - Prob. 51PCh. 5 - Prob. 52PCh. 5 - Prob. 53PCh. 5 - Prob. 54PCh. 5 - Prob. 55PCh. 5 - Prob. 56PCh. 5 - Prob. 57PCh. 5 - Prob. 58PCh. 5 - Prob. 59PCh. 5 - Prob. 60PCh. 5 - Prob. 61PCh. 5 - Prob. 62PCh. 5 - Prob. 63PCh. 5 - Prob. 65PCh. 5 - Prob. 67PCh. 5 - Prob. 68PCh. 5 - Prob. 69PCh. 5 - Prob. 70PCh. 5 - Prob. 71PCh. 5 - Prob. 72PCh. 5 - Prob. 73PCh. 5 - Prob. 74PCh. 5 - Prob. 75PCh. 5 - Prob. 76PCh. 5 - Prob. 77PCh. 5 - Prob. 78PCh. 5 - Prob. 79PCh. 5 - Prob. 80PCh. 5 - Prob. 82PCh. 5 - Prob. 83PCh. 5 - Prob. 84PCh. 5 - Prob. 85PCh. 5 - Prob. 86PCh. 5 - Prob. 87PCh. 5 - Prob. 88PCh. 5 - Prob. 89PCh. 5 - Prob. 90PCh. 5 - Prob. 91PCh. 5 - Prob. 92PCh. 5 - Prob. 93PCh. 5 - Prob. 94PCh. 5 - Prob. 95PCh. 5 - Prob. 96PCh. 5 - Prob. 97PCh. 5 - Prob. 101PCh. 5 - Prob. 102PCh. 5 - Prob. 103PCh. 5 - Prob. 104PCh. 5 - Prob. 105PCh. 5 - Prob. 106PCh. 5 - Prob. 107PCh. 5 - Prob. 108PCh. 5 - Prob. 109PCh. 5 - Prob. 110PCh. 5 - Prob. 111PCh. 5 - Prob. 112PCh. 5 - Prob. 113PCh. 5 - Prob. 114PCh. 5 - Prob. 115PCh. 5 - Prob. 116PCh. 5 - Prob. 117PCh. 5 - Prob. 118PCh. 5 - Prob. 119PCh. 5 - Prob. 120PCh. 5 - Prob. 121PCh. 5 - Prob. 122PCh. 5 - Prob. 123PCh. 5 - Prob. 124PCh. 5 - Prob. 125PCh. 5 - Prob. 126PCh. 5 - Prob. 127PCh. 5 - Prob. 128PCh. 5 - Prob. 129PCh. 5 - Prob. 130PCh. 5 - Prob. 131PCh. 5 - Prob. 132PCh. 5 - Prob. 133PCh. 5 - Prob. 134PCh. 5 - Prob. 135PCh. 5 - Prob. 136PCh. 5 - Prob. 137PCh. 5 - Prob. 138PCh. 5 - Prob. 139P
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- Check Your Understanding Calculate the acceleration of the system, and the tension in the string, when the masses are andarrow_forwardAlthough people would surely avoid getting into the elevatorwith you, suppose that you weigh yourself while onan elevator that is moving. Would you weigh more than,less than, or the same as when the scale is on a stationaryfloor?a passenger of mass m 72.2 kg stands ona platform scale in an elevator cab.We are concerned withthe scale readings when the cab is stationary and when it ismoving up or down.(a) Find a general solution for the scale reading, whateverthe vertical motion of the cab.arrow_forwardThe same rocket sled drawn is deceleratedat a rate of 196 m/s2. What force is necessary to producethis deceleration? Assume that the rockets are off. The massof the system is 2100 kg.arrow_forward
- If the rocket sled starts with onlyone rocket burning, what is the magnitude of its acceleration?Assume that the mass of the system is 2100 kg, the thrust Tis 2.4×104 N, and the force of friction opposing the motionis known to be 650 N. (b) Why is the acceleration not onefourth of what it is with all rockets burning?arrow_forwardAlthough people would surely avoidgetting into the elevator with you, suppose that you wiegh yourself while on an elevator that is moving. Would you weigh more than, less than, or the same as when the scale is on a stationary floor? In fig.ą, a passenger of mass m 72.2 kg stands on a platform scale in an elevator cab. We are concerned with the scale readings when when the cab is stationary and when it is moving up or down. (a) find a general solution for the scale reading, whatever the vertical motion of the cab. (b)what does the scale read if the cab is stationary or moving upward at a constant 0.50 m/s?arrow_forwardA chair of mass 12.0 kg is sitting on the horizontal floor which is not frictionless. Youpush on the chair with a force F=40.0N that is directed at and angle of 37.0 degree below thehorizontal and the chair slides along the floor. Use your FBD in No. 2 and Newton’s Lawsof Motion to calculate the Normal Force that the floor is exerts on the chair.arrow_forward
- A wedge with mass M rests on a frictionless,horizontal tabletop. A block with mass m is placed on the wedge(Fig. ). There is no friction between the block and the wedge.The system is released from rest. (a) Calculate the acceleration of thewedge and the horizontal and vertical components of the acceleration ofthe block. (b) Do your answers to part (a) reduce to the correct resultswhen M is very large? (c) As seen by a stationary observer, what is theshape of the trajectory of the block?arrow_forwardA block of mass m, = 14.4 kg is on a frictionless table to the left of a second block of mass m, = 17.2 kg, attached by a horizontal string (see the figure below). HINT F m1 M2 (a) If a horizontal force of 1.13 x 102 N is exerted on the block m, in the positive x-direction, use the system approach to find the acceleration (in m/s?) of the two blocks. m/s2 (b) What is the tension (in N) in the string connecting the blocks? Narrow_forwardConsider the 65.0 kg Ice skater being pushed by two others shown In the figure. Frot F2 Free-body diagram F, F, F, (a) Find the direction (in degrees) and magnitude (in N) of F,et, the total force exerted on her by the others, glven that the magnitudes F, and F, are 25.2 N and 15.4 N, respectively. direction o (counterclockwise from the direction of F, is positive) magnitude (b) What is her initial acceleration (in m/s?) if she is initlally stationary and wearing steel-bladed skates that point in the direction of F? (c) What is her acceleration (in m/s2) assuming she is already moving in the direction of Fot? Remember that friction is always in the opposite direction of motion or attempted motion between surfaces in contact. m/s? (in the direction of Frot)arrow_forward
- A SpaceX rocket with an initial mass of m0 uses its engines to hover, stationary,just above the ground. (a) Write down a differential equation for the rocket’s mass usingthe condition that the thrust must balance the force of gravity. Assume the exhaust speedvex is a constant. (b) The rocket burns fuel and hovers until the final mass is mf . Solve forthe amount of time it is able to hover. (c) Calculate the hover time for a rocket that burnsan amount of fuel equal to 30% of its initial mass, with an exhaust speed of 2000 m/s.arrow_forwardThe two boxes are in contact, and hence they have the same acceleration. We find this acceleration with Newton’s second law; that is, wedivide the net horizontal force by the total mass of the two boxes.arrow_forwardThe forces acting onan object weighingW units on aninclined planepositioned at anangle of θ with thehorizontal (see figure)are modeled byμW cos θ = W sin θ,where μ is the coefficient of friction. Solve theequation for μ and simplify the result.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- University Physics Volume 1PhysicsISBN:9781938168277Author:William Moebs, Samuel J. Ling, Jeff SannyPublisher:OpenStax - Rice University
University Physics Volume 1
Physics
ISBN:9781938168277
Author:William Moebs, Samuel J. Ling, Jeff Sanny
Publisher:OpenStax - Rice University
Newton's Third Law of Motion: Action and Reaction; Author: Professor Dave explains;https://www.youtube.com/watch?v=y61_VPKH2B4;License: Standard YouTube License, CC-BY