EBK MANUFACTURING PROCESSES FOR ENGINEE
6th Edition
ISBN: 9780134425115
Author: Schmid
Publisher: YUZU
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Chapter 5, Problem 5.18Q
To determine
The difference in the tendency for shrinkage void formation for metal with short freezing and long freezing ranges.
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In casting experiments performed during a certain alloy and
type of sand mould it took 155 second for a cube shaped
casting to solidify. The cube was 50 mm on a side.
(i)
Determine the value of the mould constant in
Chvorinov's Rule.
(ii)
If the same alloy and mould type were used, find the
total solidification time for cylindrical casting in which
the diameter D = 30 mm and length L = 50 mm.
%3D
Under uniform cooling, a spherical casting of 25
mm diameter undergoes volumetric solidification
shrinkage and volumetric solid contraction of 2.5%
and 6.2%, respectively. Determine the diameter of
the casting after solidification.
Q1/ In a homogeneous solidification process, assume molten metal solidifies into a spherical
nucleus with a BCC structure. The given data are; lattice parameter (0.292 nm), the heat of
fusion energy (1.85×10-9 J/m³), latent surface free energy (0.204 J/m²), critical radius (1-35
nm), equilibrium melting temperature (1516 K), and room temperature (27 °C). Calculate the
following for this metal;
(a) supercooling value temperature (b) activation tree energy (c) number of atoms in a
nucleus of critical size.
Chapter 5 Solutions
EBK MANUFACTURING PROCESSES FOR ENGINEE
Ch. 5 - Prob. 5.1QCh. 5 - Prob. 5.2QCh. 5 - Prob. 5.3QCh. 5 - Prob. 5.4QCh. 5 - Prob. 5.5QCh. 5 - Prob. 5.6QCh. 5 - Prob. 5.7QCh. 5 - Prob. 5.8QCh. 5 - Prob. 5.9QCh. 5 - Prob. 5.10Q
Ch. 5 - Prob. 5.11QCh. 5 - Prob. 5.12QCh. 5 - Prob. 5.13QCh. 5 - Prob. 5.14QCh. 5 - Prob. 5.15QCh. 5 - Prob. 5.16QCh. 5 - Prob. 5.17QCh. 5 - Prob. 5.18QCh. 5 - Prob. 5.19QCh. 5 - Prob. 5.20QCh. 5 - Prob. 5.21QCh. 5 - Prob. 5.22QCh. 5 - Prob. 5.23QCh. 5 - Prob. 5.24QCh. 5 - Prob. 5.25QCh. 5 - Prob. 5.26QCh. 5 - Prob. 5.27QCh. 5 - Prob. 5.28QCh. 5 - Prob. 5.29QCh. 5 - Prob. 5.30QCh. 5 - Prob. 5.31QCh. 5 - Prob. 5.32QCh. 5 - Prob. 5.33QCh. 5 - Prob. 5.34QCh. 5 - Prob. 5.35QCh. 5 - Prob. 5.36QCh. 5 - Prob. 5.37QCh. 5 - Prob. 5.38QCh. 5 - Prob. 5.39QCh. 5 - Prob. 5.40QCh. 5 - Prob. 5.41QCh. 5 - Prob. 5.42QCh. 5 - Prob. 5.43QCh. 5 - Prob. 5.44QCh. 5 - Prob. 5.45QCh. 5 - Prob. 5.46QCh. 5 - Prob. 5.47QCh. 5 - Prob. 5.48QCh. 5 - Prob. 5.49QCh. 5 - Prob. 5.50QCh. 5 - Prob. 5.51QCh. 5 - Prob. 5.52QCh. 5 - Prob. 5.53QCh. 5 - Prob. 5.54QCh. 5 - Prob. 5.55QCh. 5 - Prob. 5.56QCh. 5 - Prob. 5.57QCh. 5 - Prob. 5.58QCh. 5 - Prob. 5.59QCh. 5 - Prob. 5.60QCh. 5 - Prob. 5.61PCh. 5 - Prob. 5.62PCh. 5 - Prob. 5.63PCh. 5 - Prob. 5.64PCh. 5 - Prob. 5.65PCh. 5 - Prob. 5.66PCh. 5 - Prob. 5.67PCh. 5 - Prob. 5.68PCh. 5 - Prob. 5.69PCh. 5 - Prob. 5.70PCh. 5 - Prob. 5.71PCh. 5 - Prob. 5.72PCh. 5 - Prob. 5.73PCh. 5 - Prob. 5.74PCh. 5 - Prob. 5.75PCh. 5 - Prob. 5.76PCh. 5 - Prob. 5.77PCh. 5 - Prob. 5.78PCh. 5 - Prob. 5.79PCh. 5 - Prob. 5.80PCh. 5 - Prob. 5.81PCh. 5 - Prob. 5.82PCh. 5 - Prob. 5.83PCh. 5 - Prob. 5.84PCh. 5 - Prob. 5.85PCh. 5 - Prob. 5.86PCh. 5 - Prob. 5.87PCh. 5 - Prob. 5.88PCh. 5 - Prob. 5.89PCh. 5 - Prob. 5.90PCh. 5 - Prob. 5.91PCh. 5 - Prob. 5.92PCh. 5 - Prob. 5.93DCh. 5 - Prob. 5.94DCh. 5 - Prob. 5.95DCh. 5 - Prob. 5.96DCh. 5 - Prob. 5.97DCh. 5 - Prob. 5.98DCh. 5 - Prob. 5.99DCh. 5 - Prob. 5.100DCh. 5 - Prob. 5.101DCh. 5 - Prob. 5.102DCh. 5 - Prob. 5.103DCh. 5 - Prob. 5.104DCh. 5 - Prob. 5.105DCh. 5 - Prob. 5.106DCh. 5 - Prob. 5.107DCh. 5 - Prob. 5.108DCh. 5 - Prob. 5.109DCh. 5 - Prob. 5.110DCh. 5 - Prob. 5.111DCh. 5 - Prob. 5.112DCh. 5 - Prob. 5.113DCh. 5 - Prob. 5.114DCh. 5 - Prob. 5.115D
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.Similar questions
- A slab of 1500 mm x 750 mm x 500 mm is required to be cast using a sand casting process. It was observed previously that the total solidification time (T) for this casting = 1.6 min. Find out the cylindrical riser dimensions (diameter to height ratio = 1) for a solidification time T = 5 min.arrow_forward(b) What are the factors that affecting the freezing rate during solidification of the molten metal and evaluate why nearly all metals experience shrinkage during solidification process.arrow_forward(c) A square casting has a volume and surface area equal to 1000 mm³ and 600 mm² respectively, and a cylindrical riser through which the molten metal is poured has a volume and surface area equal to 282 mm³ and 244 mm² respectively. Using Chvorinov's rule, determine whether such a design would avoid shrinkage cavities.arrow_forward
- 2) Explain the reasons for shrinkage that occurs during solidification of a cylindrical casting What do you make for compensation of shrinkage depending on the casting operation?arrow_forward(a) Which variables affect the total solidification time for casting process? Justify your answer from a suitable equation. Q3 What are the factors that affecting the freezing rate during solidification of the molten metal and evaluate why nearly all metals experience shrinkage during solidification process.arrow_forwardA cast steel slab of dimension 30 x 20 x 5 cm is poured horizontally using a side riser. The riser is cylindrical in shape with diameter and height, both equal to D. The freezing ratio of the mould is (a) 8D/75 (c) 75/8D (b) 4D/75 (d) 75/4Darrow_forward
- It's important to explain the fundamentals of strain hardening. Is this technique still reliable in hot conditions? Explainarrow_forwardQuestion-6. For solidification of a piece of FCC-metal at 860 °C. The melting point of the metal is 1260 °C. The latent heat of fusion and surface free energy are -2.16 x108 J/m³ and 0.126 J/m², respectively. If nucleation is homogeneous, answer the following questions: (a) Compute the critical radius r* in nm (b) Compute the activation free energy AG* in J (c) If the lattice parameter is 0.26 nm at the melting temperature, compute the number of atoms found in a nucleus of critical size (d) Compute the critical radius at the supercooling degree of 260 K.arrow_forward(a) For the solidification of iron, calculate the critical radius r* and the activation free energy ΔG* if nucleation is homogeneous. Values for the latent heat of fusion and surface free energy are –1.85 × 109 J/m3 and 0.204 J/m2, respectively. Use the supercooling value ΔT = 286 K, and the melting point of iron is 1538°C. (Critical radius, r* in nm and Activation Free Energy ΔG* in J) (b) Now calculate the number of atoms found in a nucleus of critical size. Assume a lattice parameter of 0.292 nm for solid iron at its melting temperature. (Number of Atoms for Critical Size in atoms/critical nuclues)arrow_forward
- A flat plate is to be cast in an open mold whose bottom has a square shape of 12.5 cm by 12.5 cm. The mold is 7.0 cm deep. A total of 350 cm³ of molten aluminum is poured into the mold. Solidification shrinkage is known to be 6.25%, which is a volumetric contraction, not a linear contraction. Table 7.1 lists the linear shrinkage due to thermal contraction after solidification. If the availability of molten metal in the mold allows the square shape of the cast plate to maintain its square dimension until solidification is completed, determine the final dimensions (width and height) of the plate.arrow_forwardThe basics of strain hardening should be explained. Is this method still effective at high temperatures? explainarrow_forwardOn the continuous growth, Calculate the interfacial undercooling if the melting temperature is 600 K and the latent heat of melting is given as 30 kJ/kg? (Assume the driving force for solidification as 45 kJ/kg?arrow_forward
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Explanation of Solidification of Metals & Alloys | Manufacturing Processes; Author: Magic Marks;https://www.youtube.com/watch?v=G5z9KknF_s8;License: Standard Youtube License