Concept explainers
(a)
Interpretation:
The molar mass of each liquid should be calculated.
Concept Introduction :
Here,
P − pressure
V − volume
n − number of moles
R − universal gas constant
T − temperature
(a)
Answer to Problem 5.71P
Liquid I =
Liquid II =
Liquid III =
Explanation of Solution
Sample I;
Sample II;
Sample III;
(b)
Interpretation:
The molecular formula of each sample should be determined.
Concept Introduction :
Molecular formula is a way of representing the number of moles of each atom present in a molecule.
(b)
Answer to Problem 5.71P
Sample I =
Sample II =
Sample III =
Explanation of Solution
Sample I;
Mass of boron in 1 mol of sample I =
Mass of hydrogen in 1 mol of sample I =
Therefore, molecular formula of sample I =
Sample II;
Mass of boron in 1 mol of sample II =
Mass of hydrogen in 1 mol of sample II =
Therefore, molecular formula of sample II =
Sample III;
Mass of boron in 1 mol of sample III =
Mass of hydrogen in 1 mol of sample III =
Therefore, molecular formula of sample III =
(c)
Interpretation:
The molecular formula of sample IV should be determined.
Concept Introduction :
The rate of effusion is related to molar mass as follows:
(c)
Answer to Problem 5.71P
Explanation of Solution
Rate of effusion of SO2 =
Rate of effusion of BxHy =
Therefore, formula of sample IV =
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Chapter 5 Solutions
Principles of General Chemistry
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